On Sun, Nov 29, 2009 at 11:14:58AM +0200, Dotan Cohen wrote:
2009/11/29 Andrew Sackville-West and...@farwestbilliards.com:
On Sun, Nov 29, 2009 at 01:22:15AM +0200, Dotan Cohen wrote:
will get the ones that start with capital alphas. if you want initial
caps *only* then:
grep
On Sat, Nov 28, 2009 at 7:13 AM, Dotan Cohen dotanco...@gmail.com wrote:
I have a long binary file (about 12 MB) that I need to extract the
text from via strings. Naturally, there are a lot of junk lines such
as these:
pDuf
#k0H}g)
GoV5
rLeY1
TMlq,*
Is there a way to grep the output of
On Sun, Nov 29, 2009 at 01:22:15AM +0200, Dotan Cohen wrote:
will get the ones that start with capital alphas. if you want initial
caps *only* then:
grep ^[A-Z][a-z]*$
would match those.
Thanks. I meant that caps could only be at the beginning of a word,
not in the middle.
2009/11/29 Andrew Sackville-West and...@farwestbilliards.com:
On Sun, Nov 29, 2009 at 01:22:15AM +0200, Dotan Cohen wrote:
will get the ones that start with capital alphas. if you want initial
caps *only* then:
grep ^[A-Z][a-z]*$
would match those.
Thanks. I meant that caps could
Dotan Cohen wrote:
This means that only words that start with a caps are valid. I need
can start with a caps, but caps can be nowhere else. I got that like
this:
grep ^[A-Za-z][a-z]*$
However I think that there is a better way.
This is a good exercise. I am bettering my regex skills as
I have a long binary file (about 12 MB) that I need to extract the
text from via strings. Naturally, there are a lot of junk lines such
as these:
pDuf
#k0H}g)
GoV5
rLeY1
TMlq,*
Is there a way to grep the output of strings in order to only show
lines that contain words found in the aspell
In 880dece00911280713n6193b8das6970e8a071fc2...@mail.gmail.com, Dotan Cohen
wrote:
Is there a way to grep the output of strings in order to only show
lines that contain words found in the aspell dictionary? Thanks in
advance.
I once wrote a small program against the aspell API to do something
On Sat, Nov 28, 2009 at 11:32:59AM -0600, Boyd Stephen Smith Jr. wrote:
In 880dece00911280713n6193b8das6970e8a071fc2...@mail.gmail.com, Dotan Cohen
wrote:
Is there a way to grep the output of strings in order to only show
lines that contain words found in the aspell dictionary? Thanks in
ISTM that because the output of strings is not discrete list of
potential words, but is instead a long list of concatenated
characters, this problem is really rather daunting. The output should
probably be first broken up into something resembling words by perhaps
breaking on non-alphabetic
On Saturday 28 November 2009 16:13:55 Dotan Cohen wrote:
I have a long binary file (about 12 MB) that I need to extract the
text from via strings. Naturally, there are a lot of junk lines
such as these:
pDuf
#k0H}g)
GoV5
rLeY1
TMlq,*
Is there a way to grep the output of strings in
On Sun, Nov 29, 2009 at 12:00:33AM +0200, Dotan Cohen wrote:
ISTM that because the output of strings is not discrete list of
potential words, but is instead a long list of concatenated
characters, this problem is really rather daunting. The output should
probably be first broken up into
will get the ones that start with capital alphas. if you want initial
caps *only* then:
grep ^[A-Z][a-z]*$
would match those.
Thanks. I meant that caps could only be at the beginning of a word,
not in the middle. Expanding your example, I figured that would be:
grep ^[A-Z]?[a-z]*$ // note
On Sun, Nov 29, 2009 at 01:22:15AM +0200, Dotan Cohen wrote:
will get the ones that start with capital alphas. if you want initial
caps *only* then:
grep ^[A-Z][a-z]*$
would match those.
Thanks. I meant that caps could only be at the beginning of a word,
not in the middle.
Dotan writes:
Is there a way to grep the output of strings in order to only show
lines that contain words found in the aspell dictionary?
Try this:
#!/bin/bash
strings $1 | while read line
do
if [ ` echo $line | sed -e 's/[^a-zA-Z ]//g' | wc -m` -lt 6 ]
then
continue
fi
echo $line | sed -e
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