Re: [development-axapta] FormControl Declaration Problem

Use the below stmt after 'super()' in Init method of the form. element.control(Control::xx).visible(false); // xx is the form control name (Group/Field). Hope this helps! Regards, Diwakar From: shamika shamik...@yahoo.com To:

Re: [development-axapta] retrieve directory / folder path

Check the macro WinAPI where the paths are defined and check for #CSIDL_PERSONAL Tip: Check where and how the method getFolderPath is used in AOT :) From: ramankt2001 raman_...@hotmail.com To: development-axapta@yahoogroups.com Sent: Fri, 16 July, 2010

Re: [development-axapta] Queries VS Select

Select statement is not dynamic, you cannot add filtering conditions at runtime whereas, using Query you can prompt the user to add/change filtering criteria at runtime. Regards Diwakar From: pranam mukher pranam_shub...@yahoo.co.in To: axa knwoldge

Re: [development-axapta] I got a problem with employee form

Lets say you have added a new table MS_EmplTable to add your new fields to EmplTable and EmplId is the relation. Checklist - Set the joinSource property of MS_EmplTable dataSource to EmplTable. - Set the dataSource property of the new tabpage to MS_EmplTable. - If you are displaying these new

Re: [development-axapta] directory control on form

What type is FilePath? Use the same type. Guess it's a string, use a StringEdit control and set the ExtendedDataType propety to FilePath. From: ramankt2001 raman_...@hotmail.com To: development-axapta@yahoogroups.com Sent: Wed, 4 August, 2010 12:19:26 PM