Hello,
I am developing a personal website with django on google app engine.
The site works when I do not use templates. See here:
vrao423.appspot.com. But when I change try to use templates I separate
the base into files index and base.
Here is my base:
http://www.w3.org/
TR/html4/strict.dtd">
Take a look here
http://dpaste.com/73953/
or following
# in models.py
class Seed(models.Model):
name = models.CharField(max_length=128)
UPLOAD_ROOT = 'uploads'
files = models.FileField(upload_to=UPLOAD_ROOT, blank=True,
null=True)
source = models.CharField(max_length=256,
On Fri, 2009-07-31 at 20:56 -0700, django user wrote:
> So is there a viable django solution for this problem?
You can implement your own session support. It's not that difficult.
Django is just a layer on top of Python, so there's a Django solution to
any computable problem. Django's default
So is there a viable django solution for this problem?
On Jul 31, 7:50 pm, Malcolm Tredinnick
wrote:
> On Fri, 2009-07-31 at 19:43 -0700, django user wrote:
> > I'm interested in a solution for this as well.
>
> > I am thinking that a good way might be to rewrite the
You can unregister the User model and default UserAdmin from the admin
site, then register it again but after changing form and add_form of
UserAdmin with you custom form classes. Looking at the code for
django.contrib.auth.admin will probably make things clearer for you:
On Thu, Jul 30, 2009 at 12:18:17AM -0700, gentlestone wrote:
> I found this text on the tutorial page
> http://docs.djangoproject.com/en/dev/ref/models/instances/
> -
> ...you could reference this using permalink() as follows:
>
>
On Fri, 2009-07-31 at 19:43 -0700, django user wrote:
> I'm interested in a solution for this as well.
>
> I am thinking that a good way might be to rewrite the auth middleware
> to check and see if a user login for this user exists and if it does
> then remove that login and log in the current
I'm interested in a solution for this as well.
I am thinking that a good way might be to rewrite the auth middleware
to check and see if a user login for this user exists and if it does
then remove that login and log in the current user. A message could
then be passed to the login page letting
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Try: {% if user.is_authenticated() %}
If that doesn't work, you would need to setup the
TEMPLATE_CONTEXT_PROCESSORS setting in settings.py.
http://docs.djangoproject.com/en/dev/ref/settings/#template-context-processors
Luke
On Fri, 2009-07-31 at 16:31 -0700, mviamari wrote:
> Hello,
>
> I'm trying to make a form for data entry into my database that uses
> ChoiceFields for foreign keys. Obviously, the ideal choice would be
> ModelChoiceField, however I'm not using the django ORM, so I've
> assumed that's not going
On Fri, 2009-07-31 at 14:42 -0700, Unnamed_Hero wrote:
> I have something like this:
>
> class Translation1(models.Model):
> code = models.IntegerField(primary_key=True)
> description = models.CharField()
>
> class Translation2(models.Model):
> code =
On Fri, 2009-07-31 at 11:42 -0400, Faheem Mitha wrote:
>
> Hi everybody,
>
> I upgraded from somewhere around Django 1.0 to 1.0.2, and some things
> broke and had to be changed. In the following, f is an object of class
> 'django.core.files.uploadedfile.TemporaryUploadedFile'. I need to
>
>
On Fri, Jul 31, 2009 at 08:04:50AM -0700, When ideas fail wrote:
> Is there a way i can stopped people who are already logged in logging
> in again?
My initial thought - this sounds risky - for a website.
How do you know if the user is already logged in?
The computer they were using may have
Ok, thanks, i will try that. As a thought could i not have something
like:
{% ifequal user.username "" %}
login form
{% else %}
you are already logged in
I don't know if that would work or not though.
On 1 Aug, 01:30, Luke Seelenbinder
wrote:
> -BEGIN PGP
Thanks :)
Luke Seelenbinder wrote:
> -BEGIN PGP SIGNED MESSAGE-
> Hash: SHA1
>
> No, you would not. Hope that helps.
>
> Luke
>
> luke.seelenbin...@gmail.com
>
> "I [may] disapprove of what you say, but I will defend to the death your
> right to say it." -- Voltaire
>
>
> Vasil
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No, you would not. Hope that helps.
Luke
luke.seelenbin...@gmail.com
"I [may] disapprove of what you say, but I will defend to the death your
right to say it." -- Voltaire
Vasil Vangelovski wrote:
> It's like this:
> I actually have 3 projects.
It's like this:
I actually have 3 projects. These projects share apps. So all the apps
besides the third party ones are placed in one folder which is on
PYTHONPATH. The third party ones are in another folder on the
PYTHONPATH. Yes 2 of these projects use the admin and do use the
ModelBackend
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No it doesn't. That would be your problem, you would have to write a
custom backend if you wanted to not show the login form to already
logged-in visitors.
Luke
luke.seelenbin...@gmail.com
"I [may] disapprove of what you say, but I will defend to
I'm using (r'^login/$', 'django.contrib.auth.views.login',
{'template_name': 'blogSite/login.html'}), for the view, so does that
pass a request of not?
On 1 Aug, 01:09, Luke Seelenbinder
wrote:
> -BEGIN PGP SIGNED MESSAGE-
> Hash: SHA1
>
> Are you passing
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Vasil,
That will vary on what the apps you are using. If none of the apps
depend on django.contrib.auth, you won't need it, unless you want to use
the django admin (which depends on django.contrib.auth).
To fully answer your question, we would need
I'm making a very small project that will use the apps/models from a
larger one. This will be hosted on a separate domain. Now the larger
project uses the models from django.contrib.auth, but I don't need and
don't want to store users in a database for this smaller one. I'll just
provide my
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Are you passing the "request" to it?
That's the only thing I can think of that would mess it up, otherwise it
looks good syntactically.
Luke
luke.seelenbin...@gmail.com
"I [may] disapprove of what you say, but I will defend to the death your
right
Hi, i am using this template to log people in, but it seems to always
return the login form no matter what i do, i can be logged in or
logged out and it will still say i need to log in.
Does anyone know what might be happening. Any help would be
appreciated.
Thanks
{% extends
Hello,
I'm trying to make a form for data entry into my database that uses
ChoiceFields for foreign keys. Obviously, the ideal choice would be
ModelChoiceField, however I'm not using the django ORM, so I've
assumed that's not going to work (I'm using Elixir/SQLAlchemy).
I originally set the
I have something like this:
class Translation1(models.Model):
code = models.IntegerField(primary_key=True)
description = models.CharField()
class Translation2(models.Model):
code = models.IntegerField(primary_key=True)
description = models.CharField()
class
shameless bump. Still can't figure out how this would be
accomplished...
On Jul 8, 8:01 pm, Tim Boy wrote:
> What's the best way to make this "custom" widget. I can't find any
> information online with someone making a widget do anything different to the
> actual html of
In our webapp we needed to allow dashes "-" in our usernames. I've
enabled that for the consumer signup process just fine with this regex
r'^[\w-]+$'
How can I tell the admin app so that I can edit usernames in auth >
users to allows the "-" character in usernames?
I got it!
thank you
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On Fri, Jul 31, 2009 at 1:23 PM, weiwei wrote:
> Could you please expand the process " send all those names to the
> same Django instance" a little bit more detailed?
that's totally about the frontend server and not about Django. As
Graham said, apache accepts
On Fri, Jul 31, 2009 at 1:56 PM, Daymien wrote:
>
> Hallo,
>
> How could I implement forward declaration in django models?
> this example wouldn't work for me:
> Has anyone an idear or a solution?
>
> This django model show a simple implementation for a bloodline
Hallo,
How could I implement forward declaration in django models?
this example wouldn't work for me:
Has anyone an idear or a solution?
This django model show a simple implementation for a bloodline app!
from
Makes perfect sense, thanks for that pointer!
On Jul 31, 11:17 am, Alex Gaynor wrote:
> On Fri, Jul 31, 2009 at 1:15 PM, Margie wrote:
>
> > I am seeing some behavior with session that I don't understand. If I
> > have a session variable called
Could you please expand the process " send all those names to the
same Django instance" a little bit more detailed?
Thanks
On Jul 31, 7:17 am, Javier Guerra wrote:
> On Fri, Jul 31, 2009 at 12:26 AM, weiwei wrote:
> > thanks, i was thinking
On Fri, Jul 31, 2009 at 1:15 PM, Margie wrote:
>
> I am seeing some behavior with session that I don't understand. If I
> have a session variable called recentAddIds that contains a list. I
> find that if I append to that list, like this:
>
>
I am seeing some behavior with session that I don't understand. If I
have a session variable called recentAddIds that contains a list. I
find that if I append to that list, like this:
request.session['recentAddIds'].append(newlySavedId)
Then when I next receive a GET, I find that
On Jul 30, 7:29 pm, Graham Dumpleton
wrote:
> If you are using mod_wsgi then you definitely do not need
> FORCE_SCRIPT_NAME as mod_wsgi does the correct think in respect of
> setting up SCRIPT_NAME/PATH_INFO. The only time it might not be right
> with mod_wsgi is if
I come from the world of Java and Hibernate and trying to get familiar
with Django (loving it by the way). The issue I am running into is the
relationship setup between the model classes and there related
objects. For instance say i have:
class Blog(models.Model):
name = models.CharField()
If I trash the .class files created by startproject, I can
successfully run the built-in server after the classes are re-
compiled.
On Jul 31, 11:21 am, fwierzbicki wrote:
> On Jul 31, 9:46 am, Brandon Taylor wrote:> Hi
> everyone,
>
> > I
On Jul 31, 9:46 am, Brandon Taylor wrote:
> Hi everyone,
>
> I created a new project through jython/django-admin.py and now I'm
> receiving this error when attempting to start the development server
> using jython...
This is a known bug on Jython, but we haven't gotten
On 31 Jul 2009, at 17:04 , When ideas fail wrote:
>
> Hello, if i am using this generic view in my urls.py?
>
> (r'^accounts/login/$', 'django.contrib.auth.views.login',
> {'template_name': 'myapp/login.html'}),
>
> Is there a way i can stopped people who are already logged in logging
> in again?
Hello,
I have a situation where I've created a site using django, using
sqlite3.
Thus far I've always had the database under version control (which,
seeing as it's a binary file, doesn't mean much other than the fact I
have a backup)
The problem becomes when I make changes on my home computer
I would like to do something like this, too!
Please help!
On Fri, Jul 31, 2009 at 5:04 PM, When ideas
fail wrote:
>
> Hello, if i am using this generic view in my urls.py?
>
> (r'^accounts/login/$', 'django.contrib.auth.views.login',
> {'template_name':
http://stackoverflow.com/questions/1212864/threaded-application-integrityerror
On Jul 31, 9:41 am, ramya wrote:
> Hi,
> I have python threaded application + Postgres. I am using Django's ORM
> to save to Postgres..
> I have concurrent save calls. Occasionally 2 threads
Hi everybody,
I upgraded from somewhere around Django 1.0 to 1.0.2, and some things
broke and had to be changed. In the following, f is an object of class
'django.core.files.uploadedfile.TemporaryUploadedFile'. I need to
1) Get the contents of the file corresponding to f. I had to change
On Fri, Jul 31, 2009 at 12:41 PM, ramya wrote:
>
> Hi,
> I have python threaded application + Postgres. I am using Django's ORM
> to save to Postgres..
> I have concurrent save calls. Occasionally 2 threads save with the
> same primary key which leads to an issue.
>
>
Hello, if i am using this generic view in my urls.py?
(r'^accounts/login/$', 'django.contrib.auth.views.login',
{'template_name': 'myapp/login.html'}),
Is there a way i can stopped people who are already logged in logging
in again?
Thanks
--~--~-~--~~~---~--~~
Salvatore Leone ha scritto:
> Hi,
>
> I've a form with a html array. How can I process this array in my view
> after the submit?
>
> I'm pretty sure the html code is correct because I can manage the array
> with a php script... so there must be a way to do it in python.
>
> -Salvatore
>
Hi Prabhu,
You are correct about how to fix the error you're seeing, but I think
you're confused about why you're seeing it. As with all
relationships,
an object in a many-to-many relationship must have a primary key value
before you can point a foreign key value at it from another table.
When
On Fri, Jul 31, 2009 at 1:42 AM, Asinox wrote:
> i try
> with .filter("field1__field2") where the field1 is the PK and the
> field2 is the FK.
that dowsn't sound right. i think you've misread the ORM chapters of
the documentation.
don't try to think in terms of the SQL you
On Fri, Jul 31, 2009 at 12:26 AM, weiwei wrote:
> thanks, i was thinking to have each user have a url as
> http://username.domain.com/
after you manage to configure your frontend server (apache, lightttpd,
nginx, whatever) to send all those names to the same
I was wondering if there was a way to redirect users after login to
the page they where looking at before they logged in.
So if they where on "/blog/" when they logged in they could be
redirected back and if they where on "/about_us/" they could be
redirected to "/about_us/"?
I'd appreciate any
i read it but i want to try my method, can anybody has idea how can i
implement it?
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Hi Vasil.
Thanks for the snippets, those are useful. I was somehow just very
confused on the mechanism that was being described, but it all makes
sense now.
Margie
On Jul 30, 11:41 am, Margie wrote:
> Hi Vasil,
>
> Could you clarify how I access the variable from
On Fri, Jul 31, 2009 at 8:53 AM, Fleg wrote:
>
> Yes, I saw this case and that's what I need...
> The point is that the proposed fix implies to patch the django core
> which I would prefer to avoid.
> The other solution need to add as many lines of code as you have
>
Hi everyone,
I created a new project through jython/django-admin.py and now I'm
receiving this error when attempting to start the development server
using jython...
iMac:musaic bt$ jython manage.py runserver
Traceback (most recent call last):
File "manage.py", line 4, in
import settings
Hi,
I have python threaded application + Postgres. I am using Django's ORM
to save to Postgres..
I have concurrent save calls. Occasionally 2 threads save with the
same primary key which leads to an issue.
Postgres log:
ERROR: duplicate key value violates unique constraint "store_pkey"
Hi,
I've a form with a html array. How can I process this array in my view
after the submit?
I'm pretty sure the html code is correct because I can manage the array
with a php script... so there must be a way to do it in python.
-Salvatore
Excellent! Thank you!
On 31 jul, 14:42, Karen Tracey wrote:
> On Fri, Jul 31, 2009 at 3:18 AM, Martje wrote:
>
> > I don't understand, sorry :$. Do you care to explain a little bit
> > more? Or could you give an example?
>
> > I'm using the admin
Karen hi,
Thanks for the reply. I think I narrowed it down to the way I
installed Python on this server. I can run django applications and
other python scripts just fine from the command line.
It turns out that a quick way to test my Python + Apache setup is
replace the .wsgi file with the
On Fri, Jul 31, 2009 at 8:53 AM, Michael Ralan wrote:
>
>
> I get an (unhelpful) xampp error message that reads
>
>
> Microsoft Visual C++ Runtime Library
> ---
> Runtime Error!
>
> Program: C:\xampp\apache\bin\httpd.exe
>
> R6034
>
> An application has
Nevermind. I chose the "standard" option when installing Jython, which
doesn't include sources. If you choose the "all" option, distutils is
included.
Hope that helps someone,
Brandon
On Jul 31, 7:48 am, Brandon Taylor wrote:
> Hello everyone,
>
> I'm getting a Jython
Yes, I saw this case and that's what I need...
The point is that the proposed fix implies to patch the django core
which I would prefer to avoid.
The other solution need to add as many lines of code as you have
associated objects (and for all objects)... which is quite heavy (if
you add a foreign
I get an (unhelpful) xampp error message that reads
Microsoft Visual C++ Runtime Library
---
Runtime Error!
Program: C:\xampp\apache\bin\httpd.exe
R6034
An application has made an attempt to load the C runtime library
incorrectly.
Please contact the application's
Hello everyone,
I'm getting a Jython environment set up, and have it installed and
working properly. Now it's time to install django-jython and django
itself.
The problem is, I can't install django-jython because I don't have
distutils installed for Jython. I also can't seem to find distutils
On Fri, Jul 31, 2009 at 8:36 AM, Michael Ralan wrote:
>
> Hi,
>
> I've searched the internet and come across a couple of pages
> ostensibly showing how this is done, but even the django documentation
> itself (sans being xampp-specific) has not met me with success.
>
> I got to
On Jul 31, 10:31 am, Salvatore Leone
wrote:
> Hi,
>
> I've got a form with various information and a file upload widget.
>
> Is there a way to uploads many files at the same time? So to have a link
> "add file" (and even "remove" file for already selected files).
>
Hi,
I've searched the internet and come across a couple of pages
ostensibly showing how this is done, but even the django documentation
itself (sans being xampp-specific) has not met me with success.
I got to the point where I've installed mod_wsgi, set up the test app
but am struggling with
On Fri, Jul 31, 2009 at 3:18 AM, Martje wrote:
>
> I don't understand, sorry :$. Do you care to explain a little bit
> more? Or could you give an example?
>
> I'm using the admin interface btw.
>
You added a custom field clean method to your model definition. This
On Fri, Jul 31, 2009 at 5:51 AM, Fleg wrote:
>
> Thanks for your suggestion, but I cannot... I need to do that from a
> method of the model itself.
> Basically, I need to use some stored procedures to modify datas in the
> database (and these stored procs can also
thx
(how stupid I am :-))
On 31. Júl, 14:17 h., Daniel Roseman wrote:
> On Jul 31, 12:54 pm, gentlestone wrote:
>
> > I want find all instances of model KeyWord, where ManyToMany field
> > categories is empty. I think in versieon 1.1 is the
You could try file_name.decode('utf-8', 'replace') which will tell the
encoder not to throw errors but for any character it can't encode it
will replace with a ?
On Jul 31, 12:26 pm, alecs wrote:
> Environment:
>
> Request Method: GET
> Request
>
On Jul 31, 12:54 pm, gentlestone wrote:
> I want find all instances of model KeyWord, where ManyToMany field
> categories is empty. I think in versieon 1.1 is the appropriate code
> like this:
>
> ... KeyWord.objects.annotate(cnt = Count(categories)).filter(cnt =
> 0) ...
thank you a lot, i am reading now
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On Jul 31, 12:45 pm, Mirat Bayrak wrote:
> > Do you mean you want the foreign key value to be the 'path' field of
> > the Category model? You could do this, but why would you want to? If
> > you ever want to refer to the category path from an Announce instance,
> > you
Another approach: if you don't have it yet, start by writing tests,
targeting a coverage of your code greater than 95%.
Tests are very useful for a lot of reasons, specially to ease the
evolution of your code... And in your situation, writing the tests
will lead you to review your code by
I want find all instances of model KeyWord, where ManyToMany field
categories is empty. I think in versieon 1.1 is the appropriate code
like this:
... KeyWord.objects.annotate(cnt = Count(categories)).filter(cnt =
0) ...
What is the similar code in old version 1.0 for resolve the same
result.
i am little confused, may be i only create category_path on announce model
and write path of selected category to there... it should work and simple :\
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>
>
> Do you mean you want the foreign key value to be the 'path' field of
> the Category model? You could do this, but why would you want to? If
> you ever want to refer to the category path from an Announce instance,
> you just do:
> announce.category.path
>
>
hmm i have to explain more i
Environment:
Request Method: GET
Request URL:
http://172.16.23.33/file/4719e0bdedaa4f741f032991894d52ecb08c3476a598504fd1fee92d
Django Version: 1.0.3
Python Version: 2.6.2
Installed Applications:
['django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
On Jul 31, 11:55 am, alecs wrote:
> I'm sending a file to user:
>
> upfile = UpFile.objects.get(file_hash=request.path[6:])
> user = get_object_or_404(User, username=request.user.username)
> down_file_log = DownFile.objects.create(user_id=user,
>
On Jul 31, 11:25 am, Mirat Bayrak wrote:
> I am working on a *Categories* application for my project. The model that i
> need to categorize ise *Announces*.. i descibed category in announces like
> this
>
> class Category
> ...
> ...
> path =
2009/7/31 Steven Church :
> Daniel,
>
> Thank you for replying. I have finally found time now to start working on
> this project again. I have the following.
>
> def viewlink(self, obj):
> return 'View & Print'
> viewlink.allow_tags = True
>
> and i have put
I'm sending a file to user:
upfile = UpFile.objects.get(file_hash=request.path[6:])
user = get_object_or_404(User, username=request.user.username)
down_file_log = DownFile.objects.create(user_id=user,
file_id=upfile)
wrapper = FileWrapper(file(upfile.file_path))
I am working on a *Categories* application for my project. The model that i
need to categorize ise *Announces*.. i descibed category in announces like
this
class Category
...
...
path = models.CharField
class Announce:
...
...
...
category =
hey susanne, sorry i could not help as i gave up that aplication.
perhaps some one surely can help u here
On Jul 31, 1:36 am, susanne wrote:
> Hello Mr.pallavi, Mr.George and other members,
> I have similar application like palavi. I followed this hints but not
> success.
Hi All,
When I try to create a Group (django.contrib.auth.models.Group)
dynamically, I get the below error.
'Group' instance needs to have a primary key value before a many-to-
many relationship can be used.
This is because I am trying to add permissions to the group object and
trying to save
Thanks for your suggestion, but I cannot... I need to do that from a
method of the model itself.
Basically, I need to use some stored procedures to modify datas in the
database (and these stored procs can also modify some other tables),
thus I need to reload after calling these procedures in
2009/7/31 Hernan Olivera :
> 2009/7/31 Daniel Roseman :
>>
>> On Jul 31, 7:21 am, Rex wrote:
>>> I just created my first Django site (as an academic research project).
>>> Now that it is done, I would like to get feedback on
2009/7/31 Daniel Roseman :
>
> On Jul 31, 7:21 am, Rex wrote:
>> I just created my first Django site (as an academic research project).
>> Now that it is done, I would like to get feedback on my code from a
>> Django expert so that I can learn
On Jul 31, 7:21 am, Rex wrote:
> I just created my first Django site (as an academic research project).
> Now that it is done, I would like to get feedback on my code from a
> Django expert so that I can learn where I can improve as a Django dev.
> How can I find
Hi,
I've got a form with various information and a file upload widget.
Is there a way to uploads many files at the same time? So to have a link
"add file" (and even "remove" file for already selected files).
A possible way is to use some ajax framework (like jquery).
So my questin is:
do I
i tried but i have no calendar displayed, i have an error calendar()
takes exaclty 3 arguments (1given)
When i tried to put 3 arguments in my urls.py, nothing change.
Thank you for help.
On Jul 30, 2:19 pm, kimo wrote:
> Thank you.
>
> I will have a look.
>
> On Jul
I don't understand, sorry :$. Do you care to explain a little bit
more? Or could you give an example?
I'm using the admin interface btw.
On 31 jul, 01:45, Karen Tracey wrote:
> On Thu, Jul 30, 2009 at 4:02 PM, Martje wrote:
>
> > Hey,
>
> > I've
Thanks Malcolm,
I will test it when i get back home :)
Alan
On Jul 31, 9:46 am, Malcolm Tredinnick
wrote:
> On Thu, 2009-07-30 at 12:33 -0700, zayatzz wrote:
> > ... Hello!
>
> > I have a model (profile) which's only required field is its foreignkey
> > -
On Thu, 2009-07-30 at 23:42 -0700, Asinox wrote:
> Thanks Malcom for replay, but, is not working for me, i think that is
> simple just .filter("field1__field2"), but i cant make the join i try
> with .filter("field1__field2") where the field1 is the PK and the
> field2 is the FK.
>
> here is my
On Thu, 2009-07-30 at 12:33 -0700, zayatzz wrote:
> ... Hello!
>
> I have a model (profile) which's only required field is its foreignkey
> - django.contrib.auth.User.
>
> Following the example of forementioned model and its manager i created
> manager for the profile:
>
> class
Thanks Malcom for replay, but, is not working for me, i think that is
simple just .filter("field1__field2"), but i cant make the join i try
with .filter("field1__field2") where the field1 is the PK and the
field2 is the FK.
here is my query:
p =
Hi Rex,
I am not a django expert (in fact I have just started working with Django
about a month back), but I have been in software development for a while.
Remote code review sounds like an interesting exercise. I will be glad to
help you with the review, but with no prior promises on the
I'd probably try emailing some of the top Django developers. This seems like
it would be a buyer's market, due to the job being short and fun for a
dedicated Django dev. Don't hire a noob like me. ;)
http://code.djangoproject.com/wiki/DevelopersForHire
Ben
On Thu, Jul 30, 2009 at 11:21 PM, Rex
Good evening Rex,
I'm a beginner to Python and Django and I've found running my scripts
through PyLint (http://pypi.python.org/pypi/pylint) to be very worth
while.
Regards,
Daniel
2009/7/30 Rex :
>
> I just created my first Django site (as an academic research
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