My thinking is the current density is uniform in the outer surface of a round 
tube falling according to skin depth at that frequency. At higher frequencies 
there is no current on the inner surface so whether they touch when squashed is 
immaterial, no current there anyway.
What is relevant is the shape of the magnetic field as the tube is 
progressively squashed. As it gets flatter the current distribution moves 
closer and closer to that of a strip. There are no sudden effects.
73 Alan
G0HIQ

> Message: 3
> Date: Fri, 27 Apr 2018 01:35:36 +0000
> From: "Dauer, Edward" <eda...@law.du.edu>
> To: "elecraft@mailman.qth.net" <elecraft@mailman.qth.net>
> Subject: [Elecraft] Current Flow on Copper Strips - a Question
> Message-ID: <f2268a16-106d-4c09-9fcb-e8d95d0a5...@law.du.edu>
> Content-Type: text/plain; charset="utf-8"
> 
>    Since I don't know what precedes the word "thus" in the quotation below I 
> would ask if someone could explain this phenomenon for me.
> 
> I am trying to visualize this with a thought experiment.  In an earlier post 
> someone (Skip?) mentioned that early transmission lines were sometimes hollow 
> copper tubes, to respect the fact that AC flows only on the outside of a 
> conductor.  So, imagine a hollow tube carrying RF (which may approximate the 
> fast rise and fall times of a high voltage strike).  Current is flowing all 
> over the surface, I gather.  Now squeeze the tube along its length so that a 
> cross section becomes an ever flatter ellipse.  At the last instant squeeze 
> it so that the sides are in contact with each other.  What happens to the 
> current flow as that squeezing occurs?  Is it still all around the squished 
> tube until the instant the two sides join?  And then it all flows primarily 
> along the edges of the now flat conductor?  

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