Re: Maybe Schulze is decisive.

1998-08-31 Thread Markus Schulze
Dear Norman, the aim of this e-mail is to prove, that Schulze wins cannot be cyclic. It is sufficient to prove that if Candidate A defeats candidate B via beat-paths and candidate B defeats candidate C via beat-paths, then candidate A defeats candidate C via beat-paths. ** First:

Re: Random Ballot Tiebreaker

1998-08-31 Thread Markus Schulze
Dear Blake, you wrote (28 Aug 1998): I suggest that the way to judge the randomness of a method should be by outcome. If given a certain example, method X has 5 possible outcomes, while method Y has only 3, I would conclude that in that case at least, X has behaved more randomly. The

Re: Maybe Schulze is decisive.

1998-08-31 Thread Norman Petry
Dear Markus, Thank-you for providing a proof of the impossibility of 3-candidate cycles in a beat-path matrix. This result is interesting, because it suggests that if your proof could be generalised to apply to cycles of any size, this would greatly simplify the calculation of the Schwartz-set