James Wilkinson wrote:
I wrote:
into ~/.inputrc , and log in again, completion should be disabled.
You'll also have disabled the rest of the settings in /etc/inputrc: you
might like to either copy them across, or try putting
$include /etc/inputrc
into ~/.inputrc .
Mike McCarty replied:
Hmm,
Frank Cox wrote:
On Wed, 27 Aug 2008 10:51:55 -0500
Mike McCarty [EMAIL PROTECTED] wrote:
Because I find that I'm frequently hitting TAB when intending
to use CAPS-LOCK and getting extraneous stuff in my command line
which I then have to edit back out.
Have you considered re-arranging your
Mike McCarty wrote:
Hmm, created ~/.inputrc
$ cat ~/.inputrc
include /etc/inputrc
I believe you should have '$include /etc/inputrc', and not
'include /etc/inputrc'.
HOWEVER, so is I. IOW, I can no longer type the letter i
in either upper or lower case. I can, however, type in a
tab.
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Mike McCarty wrote:
snip
to get a login shell, and indeed completion is turned off.
HOWEVER, so is I. IOW, I can no longer type the letter i
in either upper or lower case. I can, however, type in a
tab. Hmm...
i have used same .bashrc from years
I wrote:
into ~/.inputrc , and log in again, completion should be disabled.
You'll also have disabled the rest of the settings in /etc/inputrc: you
might like to either copy them across, or try putting
$include /etc/inputrc
into ~/.inputrc .
Mike McCarty replied:
Hmm, created ~/.inputrc
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James Wilkinson wrote:
snip
If I use your .inputrc, then lower-case i stops working for me, too.
However, if I put the $ into the $include command, then the i key works
properly.
'$' defines a *string variable* and must be present.
man bash
-
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James Wilkinson wrote:
snip
If I use your .inputrc, then lower-case i stops working for me, too.
However, if I put the $ into the $include command, then the i key works
properly.
'$' defines a *string variable* and must be present.
** in
I wrote:
However, if I put the $ into the $include command, then the i key works
properly.
g wrote:
'$' defines a *string variable*
Not in this case, no. ~/.inputrc is not a shell script (at least in the
conventional case of the term).
and must be present.
That’s what I was saying.
**
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James Wilkinson wrote:
snip
However, if I put the $ into the $include command, then the i key works
properly.
i read.
'$' defines a *string variable*
Not in this case, no. ~/.inputrc is not a shell script (at least in the
conventional case
I'd like to disable the bash completion feature. I've read
the info bash stuff, and I see lots of ways to specify what
happens after or during completion, but I didn't see (overlooked?)
how to turn it off. Any bash gurus out there know how to disable
it entirely?
I don't want to turn off line
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