Re: [Firebird-devel] subselects in head

2012-10-23 Thread Kjell Rilbe
Den 2012-10-23 10:32 skrev Frank såhär: select R1.RDB$RELATION_NAME from RDB$RELATION_FIELDS F1 join RDB$RELATIONS R1 on F1.RDB$RELATION_NAME = R1.RDB$RELATION_NAME where F1.RDB$FIELD_NAME ='EMP_NO' and (not exists(select R2.RDB$RELATION_NAME

Re: [Firebird-devel] subselects in head

2012-10-23 Thread Frank
On 23/10/12 11:24, Dmitry Yemanov wrote: It smells like a bug caused by the new restriction ;-) I will investigate that, thanks. thank you Frank -- Fascinating creatures, phoenixes, they can carry immensely heavy loads, their tears have healing powers and they make highly faithful

Re: [Firebird-devel] subselects in head

2012-10-23 Thread Frank
Am 23.10.2012 13:37, schrieb Kjell Rilbe: But your query still seems strange... Just trying to be helpful, so I hope I'm not being a pain... :-) ... OK, but then why is R2 even present in the subselect? To demonstrate an error in joins in subselects in FB3.0 You can simplify your query

[Firebird-devel] Sourceforge services down

2012-10-23 Thread Mark Rotteveel
Various services of SourceForge (including CVS and Subversion) are down: https://sourceforge.net/blog/various-sourceforge-services-down/ -- Mark Rotteveel -- Everyone hates slow websites. So do we. Make your web apps