On Mon, Jun 15, 2009 at 06:57:45PM -0800, Mel Flynn wrote:
On Monday 15 June 2009 17:21:16 Gary Kline wrote:
Encl: dephp.c, test
case '?':
ch = getchar();
while (1)
{
if (ch == '?' (ch = getchar()) == '')
{
On Tue, Jun 16, 2009 at 08:30:40AM -0700, Gary Kline wrote:
On Mon, Jun 15, 2009 at 06:57:45PM -0800, Mel Flynn wrote:
On Monday 15 June 2009 17:21:16 Gary Kline wrote:
Encl: dephp.c, test
case '?':
ch = getchar();
while (1)
{
On Jun 16, 2009, at 10:30 AM, Gary Kline wrote:
I thought my initial getchar() != EOF would handle that.
But then there's that do-forever loop.
As I said, the most common problem people had was failing to check of
EOF in all the places it could occur, and so looping forever.
On Jun 16, 2009, at 12:02 PM, Gary Kline wrote:
this works, but still gives a warning. it's sloppy coding, but
as a second version...
You've got some superfluous tests for EOF in some places, and you may
also be missing some.
Your approach has been to look ahead with an
On Tue, Jun 16, 2009 at 06:32:43PM -0500, Jeffrey Goldberg wrote:
On Jun 16, 2009, at 12:02 PM, Gary Kline wrote:
this works, but still gives a warning. it's sloppy coding, but
as a second version...
You've got some superfluous tests for EOF in some places, and you may
also
guys,
last night i was lost with a slightly shorter version of this.
even looking at a printout did nothing. this morning i had another go
and went in a corner and started at the code. finally i figured it out.
this *seems* to work... The only thing this does is remove the ?
and ? delimiters.
On Monday 15 June 2009 17:21:16 Gary Kline wrote:
Encl: dephp.c, test
case '?':
ch = getchar();
while (1)
{
if (ch == '?' (ch = getchar()) == '')
{
break;
}
else
