Re: [gentoo-user] Regex question
Hi, I just wanted to comment something about Iain's suggestion: '^\?.*(http|https|ftp)://' If you add that '^' you're assuming that's the beginning of the string (as you may already know); the thing is I cannot see the cases where your URL starts with '?', the characters, and finally protocol and rest of URL. I mean, I can understand you found that string somewhere in the URL, but I don't see it being like that from the very beginning. Perhaps I missed something by the way, can you guys enlight me? Regards, Abraham Marín Pérez [EMAIL PROTECTED] Responsable de I+D SILVANO CONSULTORES Tfno.: 93.412.79.12 -- Fax: 93.410.92.90 http://www.silvanoc.com/ Iain Buchanan [EMAIL PROTECTED] 04/06/2008 01:33 Por favor, responda a gentoo-user Para: gentoo-user@lists.gentoo.org cc: Asunto: Re: [gentoo-user] Regex question Hi, On Tue, 2008-06-03 at 17:39 +1000, Adam Carter wrote: I want to filter the strings; ? something http:// or ? something? https:// or ? something ftp:// from URLs in apache. I know i need to escape ? but i'm not sure about / / needs to be escaped in perl if your regex delimiters are / as well, but here you use ' so I would _hope_ that you don't need \/\/ sort of syntax. YMMV. and i've used '(something|otherthing|whatever)' to make the 'or's work. I usually do perl, but it should be the same... Actually on reading further, Apache uses Perl Compatible Regular Expressions provided by the PCRE library. Neat. You should be viewing this with a fixed width font too :) LocationMatch '(\?.*http:\/\/|\?.*https:\/\/|\?.*ftp\/\/)' typo here==^ how about taking the common bits out of the () '\?.*(http|https|ftp)://' and it's good practise to use ^ if that's what you're expecting: '^\?.*(http|https|ftp)://' Order allow,deny Deny from all /LocationMatch is that regex correct? Will egrep use the exact same regex syntax (so i can use it to check?) I think they're essentially the same, with the exception of some classes (like [:punct:] or [\d]). egrep may need some extra escaping so as not to confuse your shell. The best way to test is to use the real program, so see if you can get info out of your logs to help. hth, -- Iain Buchanan iaindb at netspace dot net dot au I tripped over a hole that was sticking up out of the ground. -- gentoo-user@lists.gentoo.org mailing list -- gentoo-user@lists.gentoo.org mailing list
Re: [gentoo-user] Regex question
On Wed, 2008-06-04 at 08:57 +0200, [EMAIL PROTECTED] wrote: Hi, I just wanted to comment something about Iain's suggestion: '^\?.*(http|https|ftp)://' If you add that '^' you're assuming that's the beginning of the string (as you may already know); the thing is I cannot see the cases where your URL starts with '?', the characters, and finally protocol and rest of URL. I mean, I can understand you found that string somewhere in the URL, but I don't see it being like that from the very beginning. I was indeed assuming ? was at the beginning when I added the ^... Perhaps I missed something by the way, can you guys enlight me? -- Iain Buchanan iaindb at netspace dot net dot au The difference between a good haircut and a bad one is seven days. -- gentoo-user@lists.gentoo.org mailing list
RE: [gentoo-user] Regex question
I just wanted to comment something about Iain's suggestion: '^\?.*(http|https|ftp)://' If you add that '^' you're assuming that's the beginning of the string (as you may already know); the thing is I cannot see the cases where your URL starts with '?', the characters, and finally protocol and rest of URL. I mean, I can understand you found that string somewhere in the URL, but I don't see it being like that from the very beginning. Thanks guys. I know ^ and will omit it as the ? Is not at the beginning of the string. I'll try '\?.*(http|https|ftp)://' -- gentoo-user@lists.gentoo.org mailing list
Re: [gentoo-user] Regex question
Adam Carter wrote: Thanks guys. I know ^ and will omit it as the ? Is not at the beginning of the string. I'll try '\?.*(http|https|ftp)://' You can squeeze that up a bit more... \?.*(https?|ftp):// 'https?' means 'http' followed by an optional (0 or 1) 's'. Cheers, -Bruce -- gentoo-user@lists.gentoo.org mailing list
Re: [gentoo-user] Regex question
Hi, On Tue, 2008-06-03 at 17:39 +1000, Adam Carter wrote: I want to filter the strings; ? something http:// or ? something? https:// or ? something ftp:// from URLs in apache. I know i need to escape ? but i'm not sure about / / needs to be escaped in perl if your regex delimiters are / as well, but here you use ' so I would _hope_ that you don't need \/\/ sort of syntax. YMMV. and i've used '(something|otherthing|whatever)' to make the 'or's work. I usually do perl, but it should be the same... Actually on reading further, Apache uses Perl Compatible Regular Expressions provided by the PCRE library. Neat. You should be viewing this with a fixed width font too :) LocationMatch '(\?.*http:\/\/|\?.*https:\/\/|\?.*ftp\/\/)' typo here==^ how about taking the common bits out of the () '\?.*(http|https|ftp)://' and it's good practise to use ^ if that's what you're expecting: '^\?.*(http|https|ftp)://' Order allow,deny Deny from all /LocationMatch is that regex correct? Will egrep use the exact same regex syntax (so i can use it to check?) I think they're essentially the same, with the exception of some classes (like [:punct:] or [\d]). egrep may need some extra escaping so as not to confuse your shell. The best way to test is to use the real program, so see if you can get info out of your logs to help. hth, -- Iain Buchanan iaindb at netspace dot net dot au I tripped over a hole that was sticking up out of the ground. -- gentoo-user@lists.gentoo.org mailing list
