Hi Slavomir,
Slavomir Kaslev wrote:
inter x [] = [[x]]
inter x yys@(y:ys) = [x:yys] ++ map (y:) (inter x ys)
perm [] = [[]]
perm (x:xs) = concatMap (inter x) (perm xs)
I was surprised to find that not only my version is much simpler from the one
in Data.List but it also performs better.
Thank you for the comprehensive reply Yitzchak.
On Wed, Aug 5, 2009 at 2:22 PM, Yitzchak Galeg...@sefer.org wrote:
Hi Slavomir,
Slavomir Kaslev wrote:
inter x [] = [[x]]
inter x yys@(y:ys) = [x:yys] ++ map (y:) (inter x ys)
perm [] = [[]]
perm (x:xs) = concatMap (inter x) (perm xs)
I
