On Sun, 2024-04-21 at 15:06 +1200, Justin Israel wrote:
> And really I wasn't even commenting on the nature of the channel.
> Only the scheduling of the goroutines. Buffered or not, they would
> still be random order right?
Absolutely. Your answer was spot on. The issue is the ordering of the
On Sun, Apr 21, 2024, 2:07 PM 'Dan Kortschak' via golang-nuts <
golang-nuts@googlegroups.com> wrote:
> On Sat, 2024-04-20 at 18:55 -0700, Robert Solomon wrote:
> > channels are not queues, as Justin said
>
> They can be; buffered channels are queues.
>
> From https://go.dev/ref/spec#Channel_types
On Sat, Apr 20, 2024 at 7:34 PM Ron Hermsen wrote:
>
> compiling go-1.22.2 and go-1.21.9 fail due to timeout during test of net/http
> package
>
> I tried a number of earlier releases but looks only the latest two fail.
> (each build takes about 40min, so didn't try more options)
>
>
> ok
compiling go-1.22.2 and go-1.21.9 fail due to timeout during test of
net/http package
I tried a number of earlier releases but looks only the latest two fail.
(each build takes about 40min, so didn't try more options)
ok net 8.598s
panic: test timed out after 9m0s
running tests:
FAIL
On Sat, 2024-04-20 at 18:55 -0700, Robert Solomon wrote:
> channels are not queues, as Justin said
They can be; buffered channels are queues.
>From https://go.dev/ref/spec#Channel_types
> Channels act as first-in-first-out queues. For example, if one
> goroutine sends values on a channel and a
channels are not queues, as Justin said
On Saturday, April 20, 2024 at 8:18:18 PM UTC-4 Justin Israel wrote:
> On Sunday, April 21, 2024 at 11:18:24 AM UTC+12 Taňryberdi Şyhmyradow
> wrote:
>
> Hello guys,
> For the following lines, I wanted to print numbers in ordered, but
> couldn't. Could
On Sunday, April 21, 2024 at 11:18:24 AM UTC+12 Taňryberdi Şyhmyradow wrote:
Hello guys,
For the following lines, I wanted to print numbers in ordered, but
couldn't. Could you please help me and explain the reason
Thanks in advance
```
numbers := []int{1, 2, 3, 4, 5}
// Create a buffered
Hello guys,
For the following lines, I wanted to print numbers in ordered, but
couldn't. Could you please help me and explain the reason
Thanks in advance
```
numbers := []int{1, 2, 3, 4, 5}
// Create a buffered channel to handle multiple values
printed := make(chan int, len(numbers))
for _, n
Also, Staticcheck catches this:
$ curl -Os https://go.dev/play/p/oIKGb_uyLb3.go
$ staticcheck oIKGb_uyLb3.go
oIKGb_uyLb3.go:9:38: the integer division '1 / 13' results in zero (SA4025)
--
You received this message because you are subscribed to the Google Groups
"golang-nuts" group.
To
This has nothing to do with the math.Pow function. Dividing two ints (1/13)
is not the same as dividing a float by an int (1.0/13). Replace your two
`fmt.Printf()` calls with
println(1 / 13)
println(1.0 / 13)
and observe the difference. The fact that both `math.Pow` arguments are of
type
On Fri, 2024-04-19 at 22:51 -0700, DrGo wrote:
> ```
> package main
>
> import (
> "fmt"
> "math"
> )
>
> func main() {
> fmt.Printf("%g\n", 1-(math.Pow(0.6, 1/13))) //result=0
> fmt.Printf("%g\n", 1-(math.Pow(0.6, 1.0/13))) //
> result=0.038532272011602364
> }
> ```
11 matches
Mail list logo
