S. Alexander Jacobson wonders:
If you have a statement like:
result= a || b || c
does Haskell guarantee that a gets evaluated before b?
Indeed it does, for see the standard Prelude definition of (||):
True || _ = True
False || x = x
Hope that helps.
Slainte,
Alex.
If you have a statement like:
result= a || b || c
does Haskell guarantee that a gets evaluated before b?
If it does then I only have to protect against pattern match failure in
one place, a.
Yes; if a is true, b and c won't be evaluated. That's part of
the defn of ||
Simon
If you have a statement like:
result= a || b || c
does Haskell guarantee that a gets evaluated before b?
If it does then I only have to protect against pattern match failure in
one place, a.
-Alex-
___
S. Alexander Jacobson
