You can use Data.Sequence.fromList to go [a] - Seq a, though.
So given
f :: Monad m = a - m b
you have
import Data.Traversable as T
import Data.Sequence as S
g :: Monad m = [a] - m (S.Seq b)
g = T.mapM f . S.fromList
- ryan
On Wed, Sep 28, 2011 at 6:20 PM, Marc Ziegert co...@gmx.de wrote:
Hi Thomas,
this should be on the haskell-cafe or haskell-beginners mailing list.
Haskell@... is mainly for announcements.
You have:
f :: Monad m =
a - m b
Data.Traversable.mapM :: (Monad m, Traversable t) =
(a - m b) - t a - m (t b)
So, if you define g with
g
