Brandon S. Allbery KF8NH wrote:
On Oct 19, 2007, at 12:11 , Sebastian Sylvan wrote:
On 19/10/2007, Kalman Noel [EMAIL PROTECTED] wrote:
data ExistsNumber = forall a. Num a = Number a
I'm without a Haskell compiler, but shouldn't that be exists a.?
The problem is that exists is not
Peter Hercek wrote:
When 'exists' is not a keyword, why 'forall' is needed at all?
Isn't everything 'forall' qualified by default?
“forall” isn't a keyword in Haskell 98. As an extension to the language,
however, it makes certain types expressible that can not be written in H98, for
example
On Oct 21, 2007, at 6:41 , Peter Hercek wrote:
Brandon S. Allbery KF8NH wrote:
On Oct 19, 2007, at 12:11 , Sebastian Sylvan wrote:
On 19/10/2007, Kalman Noel [EMAIL PROTECTED] wrote:
data ExistsNumber = forall a. Num a = Number a
I'm without a Haskell compiler, but shouldn't that be
