Taral wrote:
On 9/11/06, Bulat Ziganshin [EMAIL PROTECTED] wrote:
Expr Bool = Eq (Expr t) (Expr t) | forall t . Eq t
Still confusing, but less so.
The problem is that it's really backwards. The symbol being defined
is Eq.
Eq (Expr t) (Expr t) | Eq t = Expr Bool
but that doesn't fit
Taral wrote:
On 9/11/06, Bulat Ziganshin [EMAIL PROTECTED] wrote:
Expr Bool = Eq (Expr t) (Expr t) | forall t . Eq t
Still confusing, but less so.
The problem is that it's really backwards. The symbol being defined
is Eq.
Eq (Expr t) (Expr t) | Eq t = Expr Bool
but that doesn't fit
On 9/11/06, Brian Hulley [EMAIL PROTECTED] wrote:
data
Expr t = If (Expr Bool) (Expr t) (Expr t)
Expr Bool = Eq (Expr t) (Expr t) | Eq t
Expr Int = Lit Int
Meh. I'm still not big on it, since in a normal function, the guard is
based on a
