On 10/30/07, Felipe Lessa [EMAIL PROTECTED] wrote:
On 10/30/07, Tim Chevalier [EMAIL PROTECTED] wrote:
ppos = pi/len2; pi and len2 are both Ints, so dividing them gives you
an Int. To convert to a Double, write ppos = fromIntegral (pi/len2).
(Type :t fromIntegral in ghci to see what else
On Tue, 30 Oct 2007, noa wrote:
I have the following function:
theRemainder :: [String] - [String] - Double
theRemainder xs xt = sum( map additional (unique xs) )
where
additional x = poccur * (inf [ppos,pneg]) --inf takes [Double]
where
xsxt = zip
On 10/30/07, noa [EMAIL PROTECTED] wrote:
Hi!
I have the following function:
theRemainder :: [String] - [String] - Double
theRemainder xs xt = sum( map additional (unique xs) )
where
additional x = poccur * (inf [ppos,pneg]) --inf takes [Double]
where
On 10/30/07, Tim Chevalier [EMAIL PROTECTED] wrote:
ppos = pi/len2; pi and len2 are both Ints, so dividing them gives you
an Int. To convert to a Double, write ppos = fromIntegral (pi/len2).
(Type :t fromIntegral in ghci to see what else fromIntegral can be
used for.)
You mean pi /
Hi!
I have the following function:
theRemainder :: [String] - [String] - Double
theRemainder xs xt = sum( map additional (unique xs) )
where
additional x = poccur * (inf [ppos,pneg]) --inf takes [Double]
where
xsxt = zip xs xt
pi =
On 10/30/07, Tim Chevalier [EMAIL PROTECTED] wrote:
On 10/30/07, noa [EMAIL PROTECTED] wrote:
Hi!
I have the following function:
theRemainder :: [String] - [String] - Double
theRemainder xs xt = sum( map additional (unique xs) )
where
additional x = poccur * (inf
