You usually don't need to worry about it. Just keep in mind that if you happen
to get a strange type error concerning an (overloaded) function *without type
signature*, it sometimes helps to add a signature.
/ Emil
On 2007-12-04 15:52, Rafael wrote:
I don't know about monomorphis
Hi... I give this error using hugs for the code:
---
f = foldl (\x y - add x y) 0 [1,2,3]
add x y = return (x + y)
---
I try:
f = foldl (\x y - counter x y) (return 0) [1,2,3]
but it dont solve, and
Hi,
Depending on what you want, you should either remove 'return' or change to
'foldM' (from Control.Monad). If you choose the latter, you also need to add a
type signature to f (because of the monomorphism restriction).
/ Emil
On 2007-12-04 14:43, Rafael wrote:
Hi... I give this error
Rafael skrev:
Hi... I give this error using hugs for the code:
---
f = foldl (\x y - add x y) 0 [1,2,3]
add x y = return (x + y)
---
I try:
f = foldl (\x y - counter x y) (return 0) [1,2,3]
but it
Hi Emil, I'm beginning in monad area...
I don't know about monomorphis restriction, but foldM works, a lot of thanks...
Matias tnks too, i'm conscious about return in the monadic chain.
thnks.
On Dec 4, 2007 12:00 PM, Emil Axelsson [EMAIL PROTECTED] wrote:
Hi,
Depending on what you
