On 2007-10-12, Dan Weston <[EMAIL PROTECTED]> wrote: > applyNtimes f n | n > 0 = f . applyNtimes f (n-1) > | otherwise = id
Why not some variant of: applyNtimes f n = foldl' (.) id (replicate n f) -- Aaron Denney -><- _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe