hi
The code below does almost what I want but not quite! It outputs...parseInt
12444a gives...
[(EInt 1,2444a),(EInt 2,444a),(EInt 4,44a),(EInt 4,4a),(EInt 4,a)]
What I want is: [(EInt 12444, a)]
data Expr = EInt {vInt :: Int} -- integer values | EBool {vBool :: Bool} --
boolean
Well, you're choosing to parse each digit of your integer as a separate
integer, so if you want to combine them after reading you'll need to
multiply by powers of two. Or, you can just read in all the digits in one
'read' command, like this:
parseInt :: String - (Expr, String)
parseInt xs
I mean powers of *ten* :)
On Dec 8, 2007 10:48 PM, Philip Weaver [EMAIL PROTECTED] wrote:
Well, you're choosing to parse each digit of your integer as a separate
integer, so if you want to combine them after reading you'll need to
multiply by powers of two. Or, you can just read in all the
