[jQuery] Re: Multiple Events

'), $('#FormID'), $('#display-div') - ricardo On Oct 29, 10:19 am, Tallu [EMAIL PROTECTED] wrote: I am trying to show and hide a div once some data is processed by the php.but the second event is not working.What am i doing wrong?     $(document).ready(function(){         //alert(Document

[jQuery] Multiple Events

I am trying to show and hide a div once some data is processed by the php.but the second event is not working.What am i doing wrong? $(document).ready(function(){ //alert(Document is Ready); $(form#FormID).submit(function(){ //alert(Form is submitted);

[jQuery] Re: Problem with JQuery - Ajax

Java script code. $(document).ready(function(){ alert(Document is Ready); $(form#FormID).submit(function(){ alert(Form is submitted); $.post(process.php,{keyword:$(#keyword).val()},function(data) { alert(Data Loaded: +

[jQuery] Problem with JQuery - Ajax

I am trying to use the ajax functions of JQuery but its not working all the normal functions of jQuery are working as expected.What could i be doing wrong. Thanks!!