Re: Question about eval-string

So many greetings guys, you' ve solved a lot of my problems. Both solutions work very well. Thanks again and all the best. Paolo Il giorno sab 2 mar 2019 alle ore 13:41 Aaron Hill ha scritto: > On 2019-03-02 4:38 am, Malte Meyn wrote: > > Am 02.03.19 um 13:34 schrieb Aaron Hill: > >>

Re: Question about eval-string

On 2019-03-02 4:38 am, Malte Meyn wrote: Am 02.03.19 um 13:34 schrieb Aaron Hill:   $@(map eval-string '("voiceA" "voiceB")) That should work too, I think. Wow, that’s cool! I think I have seen $@ in the past but I didn’t know what it does ;) That should be enclosed in << >>

Re: Question about eval-string

Am 02.03.19 um 13:34 schrieb Aaron Hill:   $@(map eval-string '("voiceA" "voiceB")) That should work too, I think. Wow, that’s cool! I think I have seen $@ in the past but I didn’t know what it does ;) That should be enclosed in << >> though for Paolo’s use case: << $@(map

Re: Question about eval-string

On 2019-03-02 4:30 am, Malte Meyn wrote: Am 02.03.19 um 13:06 schrieb Paolo Cantamessa: %this doesn't work <<   $(map eval-string '("voiceA" "voiceB")) >> The map returns a list which means that the 'elements of the SequentialMusic (produced by << >>) is a list of lists instead of a list.

Re: Question about eval-string

Am 02.03.19 um 13:06 schrieb Paolo Cantamessa: %this doesn't work <<   $(map eval-string '("voiceA" "voiceB")) >> The map returns a list which means that the 'elements of the SequentialMusic (produced by << >>) is a list of lists instead of a list. Try the following and have a look at

Question about eval-string

Hello guys, anyone has a suggest about this problem? Many thanks. Cheers %this work << $(eval-string "voiceA") $(eval-string "voiceB") >> %this doesn't work << $(map eval-string '("voiceA" "voiceB")) >> [image: Mailtrack]