And?
el
On 2020-06-19 14:37 , Rich Shepard wrote:
> On Fri, 19 Jun 2020, Dr Eberhard Lisse wrote:
>
>> Start using R :-)-O
>
> el,
>
> I thought of suggesting this, but R would require the same two steps:
> calculate decimal minutes into a fourth vector in the dataframe, then plot
> what's
On Fri, 19 Jun 2020, Dr Eberhard Lisse wrote:
Start using R :-)-O
el,
I thought of suggesting this, but R would require the same two steps:
calculate decimal minutes into a fourth vector in the dataframe, then plot
what's needed.
Regards,
Rich
--
lyx-users mailing list
On Fri, 19 Jun 2020, Wolfgang Engelmann wrote:
the minutes (3rd column) are divided by 60 and added to the hour (2nd
column). They are plotted against time (1st column) and I get a correct
graph.
How can I obtain the column of data with the hours and decimalized minutes,
e.g. 00 30 > 00.50 ?
Am 19.06.20 um 09:53 schrieb Wolfgang Engelmann:
I run this:
gnuplot> plot "file.txt" using 0:($1 + $2/60.)
with data in file.txt like
1 00 01
2 00 04
3 00 07
4 00 11
.. up to 256
the minutes (3rd column) are divided by 60 and added to the hour (2nd
column).
Start using R :-)-O
el
On 2020-06-19 09:53 , Wolfgang Engelmann wrote:
> I run this:
>
> gnuplot> plot "file.txt" using 0:($1 + $2/60.)
> with data in file.txt like
>
> 100 01
> 200 04
> 300 07
> 400 11
> .. up to 256
>
> the minutes (3rd column) are divided by
I run this:
gnuplot> plot "file.txt" using 0:($1 + $2/60.)
with data in file.txt like
1 00 01
2 00 04
3 00 07
4 00 11
.. up to 256
the minutes (3rd column) are divided by 60 and added to the hour (2nd
column). They are plotted against time (1st column) and I get
