On 3/26/07, Eric Firing <[EMAIL PROTECTED]> wrote:
> Popping the 'a' entry inside the function did not affect the dictionary
> that was passed in; it evidently gets copied automatically.
>
> Am I missing something?  Or should I go ahead and strip out the extra
> copies and modify the corresponding advice in CODING_GUIDE?

Well, that was certainly a surprise to me -- yep all the copying of
**kwargs can be eliminated and the CODING_GUIDE updated.  Thanks for
discovering this and pointing it out!

JDH

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