Dear Steven,
I am working at a single frequency in optical range. i am interested
in getting the reflectivity and transmitivity for a geometry. for this
i am using the add-flux function as explained in the meep-tutorial.
(define refl ;reflected flux
(add-flux 1.53233 df nfreq
(make flux-region
(center (- -1.136 hc) -0.805 0) (size 0 0.05))))
(define trans ;transmitted flux
(add-flux 1.53233 df nfreq
(make flux-region
(center (- -1.136 hc) 0.805 0) (size 0 0.05))))
this gives reflected spectrum at frequencies specified by the 'nfreq'.
since i am working at single frequency, can i give df=0 and nfreq=1?
this gives output only at the frequency 1.53323. can i accept this
value to be correct?
if i am to change the df= 2 and nfreq=10; then i get the following output:
flux1:, 0.53233, -0.009760152348413, -2.77467380731901e-4
flux1:, 0.754552222222222, -0.0282921647987324, -6.22401047402754e-4
flux1:, 0.976774444444444, 0.0307616314391254, -5.80801342515952e-4
flux1:, 1.19899666666667, -0.342825072839894, 0.0185655167756471
flux1:, 1.42121888888889, -1.56261527963199, -0.0529434687230871
flux1:, 1.64344111111111, -0.375459332301051, 0.103835929891208
flux1:, 1.86566333333333, -0.321363960668525, -0.0270822765490963
flux1:, 2.08788555555556, -0.0769738566986278, -0.0154287635671085
flux1:, 2.31010777777778, 4.46446856076942e-4, -0.00169755116977234
flux1:, 2.53233, -0.0257220634760312, 0.00667896692508168
but i am working at single frequency. i expect the the spectrum to
show amplitude only near my operating frequency.
kindly explain.
Thank you for your time.
regards
Ajay
--
Ajay Ram S K S M
MSc(Physics)
Sri Sathya Sai University
Prasanthi Nilayam
India.
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