(with yesterday's git head and R46)
$ mksh -c 'IFS=; [[ $* = ab ]]; echo $?' sh a b
1
$ mksh -c 'IFS=; [[ $* = a ]]; echo $?' sh a b
0
Expected the reverse.
It works ok with [[ $* = ab ]].
Also:
$ mksh -c 'IFS=; [[ $@ = a ]]; echo $?' sh a b
0
$ mksh -c 'IFS=; case $@ in a) echo a; esac'
sh a
Stephane Chazelas dixit:
(with yesterday's git head and R46)
Hm, I changed some things wrt. unquoted $* to be more bash-like,
but… apparently, there is still loads to do.
Not that I'd expect anyone to use anything but [[ $* = ... ]].
Indeed.
(R46 gave a a there.)
Ah, that is probably the
