On 2014-07-31, 14:49, Wolfgang Schuster wrote:
From what I can see in the code there is no option to disable the
stretch values.
Thanks for checking.
Kind regards,
Joshua
___
If your question is of interest to
On 26 Jul 2014, at 10:43, Hans Hagen pra...@wxs.nl wrote:
On 7/25/2014 4:31 PM, Gerben Wierda wrote:
Thanks all for the discussion. As a simple user, I think I must pass. All
this complexity in my document text and setup is too much trouble and it
seems risky (wjhat am I going to break?).
On 01 Aug 2014, at 13:30, Gerben Wierda gerben.wie...@rna.nl wrote:
[…]
I’ve tried to add this to my environment and product file, but even without
using it, it ends in an error:
(/usr/local/texlive/2014/texmf-dist/tex/context/base/spec-tpd.mkii
specials: loading definition file
Hello,
the command \os turns old-style numbers on.
How to turn it off (when being on initially)?
TIA.
Best regards,
Lukas
--
Ing. Lukáš Procházka [mailto:l...@pontex.cz]
Pontex s. r. o. [mailto:pon...@pontex.cz] [http://www.pontex.cz]
Bezová 1658
147 14 Praha 4
Tel: +420 241 096 751
Am 01.08.2014 um 18:39 schrieb Procházka Lukáš Ing. - Pontex s. r. o.
l...@pontex.cz:
Hello,
the command \os turns old-style numbers on.
How to turn it off (when being on initially)?
When you have a font which uses old style numerals by default you can disable
them by enabling lining
Here is Lua code that prints the first nine fibonacci numbers:
local function fib(n)
f={1,1}
for i=3,9 do
f[i]=f[i-1]+f[i-2]
end
return(f[n])
end
for n=1,9 do print(fib(n)) end
Here is Context+Lua that prints 3 x 3 table of the first nine natural numbers:
\starttext
On Sat, Aug 2, 2014 at 12:59 AM, John Kitzmiller k...@inradius.net wrote:
Here is Lua code that prints the first nine fibonacci numbers:
local function fib(n)
f={1,1}
for i=3,9 do
f[i]=f[i-1]+f[i-2]
end
return(f[n])
end
for n=1,9 do print(fib(n)) end
Here is Context+Lua
On Sat, 2 Aug 2014, luigi scarso wrote:
On Sat, Aug 2, 2014 at 12:59 AM, John Kitzmiller k...@inradius.net wrote:
Here is Lua code that prints the first nine fibonacci numbers:
local function fib(n)
f={1,1}
for i=3,9 do
f[i]=f[i-1]+f[i-2]
end
return(f[n])
end
for n=1,9 do
