LaTeX offers the following way to write a cube root: $\sqrt[3]{x}$. Is
there a way to do this in ConTeXt other than the TeX way of $\root 3\of x$?
Also, Hans, if there isn't a direct way to do this, the following code is
pretty much how LaTeX implements it, with an extra line at the top to
Brooks Moses wrote:
LaTeX offers the following way to write a cube root: $\sqrt[3]{x}$.
Is there a way to do this in ConTeXt other than the TeX way of $\root
3\of x$?
Also, Hans, if there isn't a direct way to do this, the following code
is pretty much how LaTeX implements it, with an
At 01:25 PM 7/31/2005, Hans Hagen wrote:
\let\normalsqrt\sqrt % \dohandlemathtoken {sqrt}
\def\sqrt{\doifnextcharelse[\notsosqrt\normalsqrt}
\def\notsosqrt[#1]{\root#1\of}
$\sqrt[3]{10}$
Do you want this in the kernel?
I'd like to have it there, yes. Thanks!
- Brooks
