Hello Hans,
On 2020-05-04 09:31, Hans Hagen wrote:
On 5/4/2020 8:47 AM, cont...@vivaldi.net wrote:
Hello,
compare placing "3" in the following examples:
\starttext
$\sqrt[3]{5}$ % (1)
\par
$\sqrt[3~]{5}$ % (2)
\stoptext
In the first case, the "3"
Hello,
compare placing "3" in the following examples:
\starttext
$\sqrt[3]{5}$ % (1)
\par
$\sqrt[3~]{5}$ % (2)
\stoptext
In the first case, the "3" is placed naturally by ConTeXt and placed
more in the centre of "V" part of the square sign.
On Mon, 4 May 2020, Hans Hagen wrote:
On 5/4/2020 8:47 AM, cont...@vivaldi.net wrote:
Hello,
compare placing "3" in the following examples:
\starttext
$\sqrt[3]{5}$ % (1)
\par
$\sqrt[3~]{5}$ % (2)
\stoptext
In the first case, the "3" is placed
On 5/4/2020 8:47 AM, cont...@vivaldi.net wrote:
Hello,
compare placing "3" in the following examples:
\starttext
$\sqrt[3]{5}$ % (1)
\par
$\sqrt[3~]{5}$ % (2)
\stoptext
In the first case, the "3" is placed naturally by ConTeXt and placed
more in th
time and it is not inefficient.
In what sense? Runtime? Even moving the definitions doesn't really save
cpu cycles. MP runtime is normally not the bottleneck in a run.
\startMPextensions
vardef findPointD(expr C, Q, r) =
numeric dist, ang;
pair X, Y;
dist := r**2/sqrt((xpart Q
.
Is there a way to draw the base figure once, and draw the points only at each
frame?
Thank you.
Best regards,
Dalyoung
\startuseMPgraphic{inversionPoint}{n}
vardef findPointD(expr C, Q, r) =
numeric dist, ang;
pair X, Y;
dist := r**2/sqrt((xpart Q - xpart C)**2 + (ypart Q - ypart C)**2
\startuseMPgraphic{inversionPoint}{n}
vardef findPointD(expr C, Q, r) =
numeric dist, ang;
pair X, Y;
dist := r**2/sqrt((xpart Q - xpart C)**2 + (ypart Q - ypart C)**2);
ang := angle(Q - C);
Y := C + dir(ang)*dist;
Y
enddef;
numeric radius, now, move;
pair A,B,C,P,Q;
path p,q;
radius
findPointD(expr C, Q, r) =
numeric dist, ang;
pair X, Y;
dist := r**2/sqrt((xpart Q - xpart C)**2 + (ypart Q - ypart C)**2);
ang := angle(Q - C);
Y := C + dir(ang)*dist;
Y
enddef;
numeric radius, now, move;
pair A,B,C,P,Q;
path p,q;
radius := 2cm;
C := origin;
p
What you probably mean is that Swedish, German, Dutch and English are
Indo-European Germanic languages which have much in common.
This cannot be expressed in terms of blends, products or square roots from one
another.
What they do have is a common root, like
\sqrt(indo-european) $x$ w
On 2019-02-01 07:58, "Mikael P. Sundqvist" wrote:
> this is what I learned from the list to use. I'm sorry, but the names
> sound a bit Swedish, but I'm sure you can change that.
The Swedish is not a problem. Swedish, like Dutch, seems to be (English
+ German)/2. Or sqr
; I have generalized my rewrite of the MP graph macros to handle any
> arbitrary mapping from data space to drawing (2D) space. At present, I
> have only considered the simple functions of log (and sqrt) scales as
> well as polar coordinates (x,y) = f(theta,r) with f(theta,r) = (r sin
>
ng (2D) space. At present, I
have only considered the simple functions of log (and sqrt) scales as
well as polar coordinates (x,y) = f(theta,r) with f(theta,r) = (r sin
theta, r cos theta) as I have real use cases for these.
I also consider a simple 3D->2D mapping.
It would be very ea
raw((-.1,0) -- (2,0), arrow=Arrow(TeXHead));
draw((0,-.1) -- (0,2), arrow=Arrow(TeXHead));
draw((0,0) .. (1,1) .. (2,sqrt(2)));
\stopASY
\stopplacefigure
\stoptext
___
If your question is of interest to others as well,
k
>> \startitemize[a,columns,three,joinedup][grid=line]
>> \item \math{f(-0,5)} et \math{f(0,5)} ;\par
>> \item \math{f(-1)} et \math{f(2)} ;\par
>> \item \math{f(-2)} et \math{f(\sqrt{2})}.\par
>> \stopitemize
>>
>> \stopitemize
>>
>> \stop
images :
\blank
\startitemize[a,columns,three,joinedup][grid=line]
\item \math{f(-0,5)} et \math{f(0,5)} ;\par
\item \math{f(-1)} et \math{f(2)} ;\par
\item \math{f(-2)} et \math{f(\sqrt{2})}.\par
\stopitemize
\stopitemize
\stoptext
you can experiment with
\setupitemgroup
[\c!grid=\v!tolerant:10
][grid=line]
\item \math{f(-0,5)} et \math{f(0,5)} ;\par
\item \math{f(-1)} et \math{f(2)} ;\par
\item \math{f(-2)} et \math{f(\sqrt{2})}.\par
\stopitemize
\stopitemize
\stoptext
___
If your question is of interest
Fabcdef}\NC\m{\red ΑΒΓΔΕΘαβγδεθ}\NC\NR
\NC italic: \NC \emph{ABCDEFabcdef}\NC\emph{ΑΒΓΔΕΘαβγδεθ}\NC\NR
\NC \NC \NC \NC\NR
\NC Greek theta: \NC\NC \emph{θ}\NC\NR
\stoptabulate
\m{\sqrt{34y\frac{12\alpha^2}{98.0 x_2}}Δθ}
\m{{{sin^2 α + cos^2 β}\over{2}} = \frac{1}{2}}
\showbodyfont
\stoptext
ons.
MnSymbol font consists of following files in several design sizes:
- MnSymbolA*.tfm - arrows
- MnSymbolB*.tfm - negated (stroked) arrows
- MnSymbolC*.tfm - binary operators
- MnSymbolD*.tfm - relations
- MnSymbolE*.tfm - brackets, braces, parens, sqrt, overbrace, widehat,...
- MnSymbolF*.tfm -
On 6/7/2017 5:12 PM, Otared Kavian wrote:
Hi,
Indeed using \frac yields a weird result in the example sent by Mikael.
Compare the output of the three formulas below, with or without
\setupmathradical[sqrt][alternative=default].
The results are correct using \over in both cases, while
Hi,
Indeed using \frac yields a weird result in the example sent by Mikael.
Compare the output of the three formulas below, with or without
\setupmathradical[sqrt][alternative=default].
The results are correct using \over in both cases, while the first one is weird
when using \frac
them).
>
> /Mikael
>
> \setupbodyfont[lucidaot]
>
> \starttext
>
> \startTEXpage[offset=2pt]
> \startformula
> \sqrt{1+x^2}\neq \frac{1}{\sqrt{1+x^2}}
> \stopformula
>
> %the default setting for mathradical seems to be "normal". We change
> it to "normal&qu
hat normal should mean,
but I think the alternative=default looks better. (The lucida fonts
are loaded in this example, since the effect is more clear for them).
/Mikael
\setupbodyfont[lucidaot]
\starttext
\startTEXpage[offset=2pt]
\startformula
\sqrt{1+x^2}\neq \frac{1}{\sqrt{1+x^2}}
\s
cript from the distribution work for anyone? MnWE:
\usetypescriptfile[type-imp-cambria]
\setupbodyfont[cambria,rm,10pt]
\starttext
This is Cambria {\it italic} {\bf bold} {\bi bold italic} and some
\m{\sqrt{123}^4/5 math}.
\stoptext
This example also fails with a math error:
Hi Michael,
Thanks, it's ok.
Fabrice
2017-02-02 22:02 GMT+01:00 Rogers, Michael K <mrog...@emory.edu>:
> This seems to work in place of 0.866cm: sqrt(3)/2*cm
>
> Michael
>
> On Feb 2, 2017, at 3:54 PM, Fabrice Couvreur <fabrice1.couvr...@gmail.com>
> wrote:
>
>
This seems to work in place of 0.866cm: sqrt(3)/2*cm
Michael
On Feb 2, 2017, at 3:54 PM, Fabrice Couvreur
<fabrice1.couvr...@gmail.com<mailto:fabrice1.couvr...@gmail.com>> wrote:
Hello,
I wanted to use sqrt(3)/2 but without success. Instead, I replaced this value
with an appro
Hello,
I wanted to use sqrt(3)/2 but without success. Instead, I replaced this
value with an approximate value 0.866
How should it be done ?
Thank you
Fabrice
\starttext
\startMPcode
draw fullcircle scaled 1cm withcolor magenta ;
draw fullcircle scaled 1cm shifted (1cm,0) withcolor
\startformula
\frac{ \ONLY 1 \phantom {-b \ONLY 2 \phantom {{}\pm \sqrt{b^2 - 4ac}} }}
{ 2a }
\stopformula
\StopStepping
\stoptext
gives the attached pdf file. If you want to use them to step through math,
then it may be better to create a wrapper around \ONLY n \phantom to save
some typing
\pm\sqrt{b^{2}-4ac \FlushStep
}}{\FlushStep
2a} \FlushStep
\stopformula
\StopSteps
\stoptext
I have looked around for more information on that module and related commands I
could try but in vain. I was hoping I could figure things out and not need to
bug you folks so
\bTD Cas où \math{a\leqslant 0} \eTD
\eTR
\bTR
\bTD\math{\Delta >0} \eTD
\bTD admet deux solutions distinctes :
\startformula
x_1=\frac{-b-\sqrt{\Delta}}{2a}\quad \rm{et} \quad
x_2=\frac{-b+\sqrt{\Delta}}
kael
>
> just a note and a small follow-up question. The \noindent implied a
> problem if the \startabc \stopabc was inside another itemize (which it
> usually is, since it is a) b) c) exercises), since then the space
> specified in after= in both environments added up. The solution was to
> use
is a) b) c) exercises), since then the space
specified in after= in both environments added up. The solution was to
use \noindentation instead of \noindent. I don't know why, though.
The small problem: In the file below, the text below is too close to
the integrals (this only happens if o
ce what you are after.
>>
>> \starttext
>>
>> \startformula
>> E = mc^2
>> \stopformula
>>
>> \startformula
>> \startalign[m=3,align={middle},distance=0pt plus 1 fil]
>>\NC \rlap{\text{Text1}}\NC\NC E=mc^2 \NR
>>
}\NC\NC E=mc^2 \NR
>\NC \rlap{\text{This is an explanation}} \NC\NC
> E=\sqrt{p^2c^2+m^2c^4} \NR
>\NC \rlap{\text{This is a longer explanation}} \NC\NC \left(\beta
> mc^2+c\left(\sum _{n=1}^3 \alpha_n p_n \right)\right) \psi(x,t) = i \hbar
> \fra
{This is an explanation}} \NC\NC
E=\sqrt{p^2c^2+m^2c^4} \NR
\NC \rlap{\text{This is a longer explanation}} \NC\NC \left(\beta
mc^2+c\left(\sum _{n=1}^3 \alpha_n p_n \right)\right) \psi(x,t) = i \hbar
\frac{\partial \psi(x,t)}{\partial t} \NR
\stopalign
\stopformula
\stoptext
The inner
ke √ U+221A for \sqrt.
If you want, you can collect such mappings in a separate module.
That would be a good idea if it should become a part of a ConTeXt distribution.
I could not make your code working - does it require a later LuaTex version
(than 0.80.0)?
Here is a complete work
> On 13 May 2016, at 17:51, Aditya Mahajan <adit...@umich.edu> wrote:
>
> On Fri, 13 May 2016, Hans Åberg wrote:
>
>> There may not be so many symbols: the “large operators" in the Tex Book, p.
>> 435, though Unicode have more, and some others like √ U+221A f
On Fri, 13 May 2016, Hans Åberg wrote:
There may not be so many symbols: the “large operators" in the Tex Book,
p. 435, though Unicode have more, and some others like √ U+221A for
\sqrt.
If you want, you can collect such mappings in a separate module.
I could not make your code wo
ruct' (tex often has many
> commands for the same symbol doing different things)
Currently, there is a problem with the lack of efficient Unicode input methods:
symbol table and copy-paste are slow. But perhaps in the future, more might
want to use it.
There may not be so man
]
\startxrow
\startxcell[width=5cm] \m{\displaystyle \gamma=\frac{1}{\sqrt{1-\left
(\frac{v}{c}\right )^2}}}\stopxcell
\startxcell[width=4cm] Reaktionsprinzip\stopxcell
\stopxrow
\stopxtable
\stoptext
\gamma isn't aligned with the text "Reaktionsprinzip".
Please tell me what I have
the `d` in calculus should be
typeset. There are also \differentiald and \differentialD that map to
unicode slots.
\definemathcommand[arsinh][nolop]{\mathlabel{arsinh}}
\starttext
$\arsinh z = \ln\bigl(z + \sqrt{z^2 + 1}\bigr)$\par
$\rho_{\mathlabel{air}} = \frac{p}{R_{\mathlabel{specific}}T
and
consistent way to label its math objets (functions and variables with
subscripts):
\definemathcommand[arsinh][nolop]{\mathlabel{arsinh}}
\starttext
$\arsinh z = \ln\bigl(z + \sqrt{z^2 + 1}\bigr)$\par
$\rho_{\mathlabel{air}} = \frac{p}{R_{\mathlabel{specific}}T}$\par
\stoptext
Hans Hagen wrote
{}}
With this new \mathlabel command, the user now have a convenient and
consistent way to label its math objets (functions and variables with
subscripts):
\definemathcommand[arsinh][nolop]{\mathlabel{arsinh}}
\starttext
$\arsinh z = \ln\bigl(z + \sqrt{z^2 + 1}\bigr)$\par
$\rho_{\mathlabel{air
\rightarrow-2^{\mp}}{\arctan\frac{x}{2+x}}=\pm\frac{\pi}{2}
\stopformula
\startformula
f':\;y' = \frac{\sqrt{3}(1+x^2)}{(1-x^2)^2+3x^2}
\stopformula
\startformula
\lim\limits_{x\rightarrow 1^{\mp}}{\frac{x^2+1}{x-1}}=\mp\infty
\stopformula
\Startsmallformula
\lim\limits_{x\rightarrow-2^{\mp
On Fri, 2 Jan 2015, Context NTG wrote:
Here is an Asymptote example
unitsize(1cm);
draw((-.1,0) -- (2,0),
arrow=Arrow(TeXHead));
draw((0,-.1) -- (0,2), arrow =
Arrow(TeXHead));
draw((0,0) .. (1,1) .. (2,sqrt(2)));
Below is how I have started setting this up in Context. This creates a pdf
Here is an Asymptote example
unitsize(1cm);
draw((-.1,0) -- (2,0),
arrow=Arrow(TeXHead));
draw((0,-.1) -- (0,2), arrow =
Arrow(TeXHead));
draw((0,0) .. (1,1) .. (2,sqrt(2)));
Below is how I have started setting this up in Context. This creates a pdf
file with the drawing, but it is not included
placerat
eleifend leo. \quote{$y=\sqrt{6}+\sqrt{26}$}. The \quote{$\sqrt{2x}$}
Mauris placerat eleifend leo. \quote{$\sqrt{2}x$}. Mauris placerat
eleifend leo.\quote{$\sqrt{12}$}Mauris placerat eleifend leo.
\quote{$\sqrt{1/2}$}. Mauris placerat eleifend leo.
\quote{$x=-{1/2}-\sqrt{1/ 8}+\sqrt{{3/8
___
Hi,
what about
\starttext
\startitemize[columns,a,joinedup][stopper=)]
\item $f(0)$
\item $g(0,3)$
\item $f(\sqrt 2)$
\item $g(-4)$
\stopitemize
\stoptext
/Mikael
hi,
In the following code, the default stopper is the point.
\starttext
\startitemize[columns,a,joinedup]
\item $f(0)$
\item $g(0,3)$
\item $f(\sqrt 2)$
\item $g(-4)$
\stopitemize
\stoptext
How to have a break ?
Best regards,
Fabrice
hi,
In the following code, the default stopper is the point.
\starttext
\startitemize[columns,a,joinedup]
\item $f(0)$
\item $g(0,3)$
\item $f(\sqrt 2)$
\item $g(-4)$
\stopitemize
\stoptext
How to have a break ?
Best regards,
Fabrice
What do you mean by a « break »?
On 14 Oct 2014, at 02:24, Fabrice Couvreur fabrice1.couvr...@gmail.com wrote:
hi,
In the following code, the default stopper is the point.
\starttext
\startitemize[columns,a,joinedup]
\item $f(0)$
\item $g(0,3)$
\item $f(\sqrt 2)$
\item $g(-4
, sense desenvolupar, que els determinants següents són nuls:
\startitemize[a]
\item $\startdet[n=3]
\NC -\sqrt{3} \NC 3 \NR
\NC 5 \NC -\sqrt{3}\cdot 5 \NR
\stopdet$
\item $\startdet[n=3]
\NC 2 \NC 1 \NC 3 \NR
\NC 1 \NC 0 \NC 1 \NR
\NC -3 \NC 2 \NC -1 \NR
\stopdet$
\stopitemize
\stoptext
matrix2
Am 07.10.2014 um 09:20 schrieb Hans Hagen pra...@wxs.nl:
On 10/7/2014 7:33 AM, Mikael P. Sundqvist wrote:
On Mon, Oct 6, 2014 at 11:32 PM, Wolfgang Schuster
schuster.wolfg...@gmail.com wrote:
\setupmathradical[alternative=default]
Very good!
Hans, will the default be default in next
On 10/7/2014 7:33 AM, Mikael P. Sundqvist wrote:
On Mon, Oct 6, 2014 at 11:32 PM, Wolfgang Schuster
schuster.wolfg...@gmail.com wrote:
\setupmathradical[alternative=default]
Very good!
Hans, will the default be default in next beta? :)
no, but there will be different settings ... the
On Fri, Oct 3, 2014 at 1:30 PM, Mikael P. Sundqvist mic...@gmail.com wrote:
Hi!
Is this (see frac.pdf) the expected output of \frac and \tfrac in
combination with \sqrt? To me the \sqrt{3} looks too big in \tfrac.
I attach also the output from the corresponding latex document, having
On Mon, 6 Oct 2014, Mikael P. Sundqvist wrote:
On Fri, Oct 3, 2014 at 1:30 PM, Mikael P. Sundqvist mic...@gmail.com wrote:
Hi!
Is this (see frac.pdf) the expected output of \frac and \tfrac in
combination with \sqrt? To me the \sqrt{3} looks too big in \tfrac.
I attach also the output from
On Mon, Oct 6, 2014 at 11:32 PM, Wolfgang Schuster
schuster.wolfg...@gmail.com wrote:
\setupmathradical[alternative=default]
Very good!
Hans, will the default be default in next beta? :)
Best regards, Mikael
___
If
Hi!
Is this (see frac.pdf) the expected output of \frac and \tfrac in
combination with \sqrt? To me the \sqrt{3} looks too big in \tfrac.
I attach also the output from the corresponding latex document, having
the result I expect.
Best regards, Mikael
PS Compilation done with latest standalone
=table:initialize]
\bTR
\bTD \eTD
\bTD $\sqrt{25}$ \eTD
\bTD \eTD
\bTD Partie entière de $\pi$ \eTD
\bTD \eTD
\bTD $\frac{48}{8}$ \eTD
\bTD \eTD
\bTD \eTD
\bTD 5 augmenté de 40\,\% \eTD
\eTR
\bTR
-plaintex.tex
This is intended to test Plain \TeX\ from the ConTeXt stand-alone.
An elementary identity: $(a + b)^2 = a^2 + 2ab + b^2$.
And a well-known identity due to Leonhard Euler in which the five most
important numbers appear:
$$
{\rm e}^{{\rm i}\pi} + 1 = 0, \qquad \hbox{where }\; {\rm i} := \sqrt{-1
, \qquad \hbox{where }\; {\rm i} := \sqrt{-1}.
$$
\bye
%%% end test-plaintex.tex
Saying in the Terminal:
mtxrun --script plain basic-plaintex.tex
results in
mtx-plain | running command 'luatex --fmt=luatex-plain
basic-plaintex.tex »’
This is LuaTeX, Version beta-0.79.1 (TeX
root results in an empty dictionary key with corresponding value \Span. A
minimal example is:
\setuptagging[state=start]
\starttext
\startformula
\sqrt{A}
\stopformula
\stoptext
2. Structure element contains index of type real number:
According to the PDF Reference V 1.7 (see Table 10.10) a structure
to a corrupt RoleMap, e.g., the usage of a square
root results in an empty dictionary key with corresponding value \Span. A
minimal example is:
\setuptagging[state=start]
\starttext
\startformula
\sqrt{A}
\stopformula
\stoptext
2. Structure element contains index of type real number:
According
.
However, the settings don't seem to affect fractions inside square
roots. Here's an example (the 20pt setting is to exaggerate the
possible effect), using 2014.05.17 beta.
\starttext
\placeformula\startformula
\dfrac{ag}{bcd}\quad{ag\over bcd}
\stopformula
\placeformula\startformula
\sqrt{1\over
Hi,
Sorry to be a pain:
%%tst01.tex
Inline $\sqrt{1.2}$ math. % same for $\root n of x$
\end
%%
$ luatex --fmt luatex-plain tst01.tex
This is LuaTeX, Version beta-0.79.1 (TeX Live 2014/dev) (rev 4972)
(format=luatex-plain 2014.5.7) 7 MAY 2014 11:48
\write18 enabled.
**tst01.tex
8
On 5/7/2014 7:56 PM, Aíre Funvake wrote:
Inline $\sqrt{1.2}$ math. % same for $\root n of x$
\end
replace this in luatex-math.tex:
\def\sqrt {\Uroot 0 221A{}}
\def\root#1\of{\Uroot 0 221A{#1
On 2014-05-07, 21:32 , Hans Hagen wrote:
On 5/7/2014 7:56 PM, Aíre Funvake wrote:
Inline $\sqrt{1.2}$ math. % same for $\root n of x$
\end
replace this in luatex-math.tex:
\def\sqrt {\Uroot 0 221A{}}
\def\root#1\of{\Uroot 0 221A{#1}}
Worked like a charm, thank you
On 4/22/2014 1:53 AM, Sanjoy Mahajan wrote:
I have been trying out the newish
\setupmathradical[sqrt][alternative=mp], which has been very nice
because of the fine control over the radical sign.
I've noticed that it crunches the denominator in \sqrt{a\over b}
For example:
\starttext
Hans Hagen pra...@wxs.nl writes:
indeed. this is what (sort of) happens in case of a plugged in renderer:
\sqrt{#1} - ...\mathstylehbox{#1}... - ...\hbox{\stylecommand #1}...
when #a = a \over b the style gets applied to the a only as \over
creates two (pseudo) groups i.e. the \over
I have been trying out the newish
\setupmathradical[sqrt][alternative=mp], which has been very nice
because of the fine control over the radical sign.
I've noticed that it crunches the denominator in \sqrt{a\over b}
For example:
\starttext
\placeformula\startformula
\sqrt{k\over m}\quad \sqrt
:
$\sqrt{123}$
i've made that one also ignore notes (beta coming)
concerning the undefined commands (\command) ... ad \let\command\relax
to the preamble then ... there is no way we can predict all that and
we're in a different catcode regime at that point
Hans
Dear list,
I think the symbol of the angles is too close to the letters.
Is it possible to change this ?
\enablemode[pxmath]
\setupbodyfont[palatino,12pt]
\starttext
\startformula
\sin\widehat{PAM}
=\frac{AM}{PA}=\frac{\frac{\sqrt{2}}{4}}{\frac{\sqrt{6}}{2}}=\frac{\sqrt{2}}{4}\times\frac{2}{\sqrt
be thankful.)
\setupbodyfont[pagella]
\starttext
\startitemize[columns,two,packed]% with packed, it's also wrong, but in
another way
\item abc
\item $a^2$
\item xyz
\item $\frac12$
\item foo
\item bar
\item baz
\item $\sqrt{2}$% \smash-ing helps, but I'd prefer
]
\endgroup
\blank
\stopsetups
\starttext
\startitemize[columns,two,packed][before=\directsetup{itemize:before},after=\directsetup{itemize:after}]
\item abc
\item \math{a^2}
\item xyz
\item \math{\frac{1}{2}}
\item foo
\item bar
\item baz
\item \math{\sqrt{2}}
\item asdf
\item qwerty
\stopitemize
}
\item xyz
\item \math{\frac{1}{2}}
\item foo
\item bar
\item baz
\item \math{\sqrt{2}}
\item asdf
\item qwerty
\stopitemize
\stoptext
Thanks a lot! It did help (but only partially, see below). (I've also
put it into \setupitemize.)
One problem remains, however: it won't work
arrangements of variables (that
recur often in my book chapter on springs and piano strings). For
example, it goes away after changing the \rho to a b.
\starttext
\startformula
\sqrt{Tb^2\over \rho}.
\stopformula
\stoptext
I know that the big math symbols are constructed differently in MkIV
and MkII. Does
Hi,
\sqrt[12]{a^{11}}
produces me:
\sqrt[1]{2} a^{11}
What happens there?
Xan.
___
If your question is of interest to others as well, please add an entry to the
Wiki!
maillist : ntg-context@ntg.nl / http
Try braces about the “12” as in
\sqrt{12}{a^{11}}
Alan
On Mon, Sep 23, 2013 at 3:55 AM, Xan dxpubl...@telefonica.net wrote:
Hi,
\sqrt[12]{a^{11}}
produces me:
\sqrt[1]{2} a^{11}
What happens there?
Xan
Xan—I misunderstood. You are right. The latest beta does not allow
numerical roots higher than the 9th. Grouping the digits—as in
$\sqrt[{12}]{…}$ does not help.
Alan
On Mon, Sep 23, 2013 at 8:13 AM, Alan Bowen bowenala...@gmail.com wrote:
Try braces about the “12” as in
\sqrt{12}{a^{11
On 9/23/2013 5:43 PM, Alan Bowen wrote:
Xan—I misunderstood. You are right. The latest beta does not allow
numerical roots higher than the 9th. Grouping the digits—as in
$\sqrt[{12}]{…}$ does not help.
will be fixed but uploaded next week
to be *part* of the
distance between baselines, rather than an additional distance. But
maybe that's not important to the main issue.
\starttext
\showstruts \strut test \par \strut test
\showstruts \strut \ruledhbox{$\sqrt{test}$} \par \strut test
\stoptext
\lineskip (1pt by default) kicks in when
Dear Hans,
I‘m afraid that beta from today doesn’t compile what beta from tow days
ago compiled.
Here is the minimal sample:
\starttext
\startformula
\Bigl(\sqrt{\phi \sqrt{5}}-\phi\Bigr)
\stopformula
\stoptext
Many thanks for your help,
Pablo
--
http://www.ousia.tk
\start \setupalign[r2l] \setupmathematics[align=r2l] arabic: این یک
آزمایش است. \par text: 3+2=5 \par math: $3+2=5$ $\sqrt{3+2=5}$ \par \stop
\start \setupalign[l2r] \setupmathematics[align=l2r] latin: This
is a test.\par text: 3+2=5 \par math: $3+2=5$ $\sqrt{3+2=5}$\par \stop
] [default]
[direction=both,rscale=1.2]
\setuptypeface[dejavu]
\starttext
\start \setupalign[r2l] \setupmathematics[align=r2l] arabic: این یک
آزمایش است. \par text: 3+2=5 \par math: $3+2=5$ $\sqrt{3+2=5}$ \par \stop
\start \setupalign[l2r] \setupmathematics[align=l2r] latin
Hi,
How can I make the subfraction in the denominator of a fraction appear
smaller even though the nominator is very small? This gives basically
three equally long division lines:
\startfomula
\frac{\mu_{Z}}{\frac{\sqrt{\VAR{Z}}{\sqrt{N_{\text{segments}
\stopformula
:
\startfomula
\frac{\mu_{Z}}{\frac{\sqrt{\VAR{Z}}{\sqrt{N_{\text{segments}
\stopformula
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'cont-new.mkiv' loaded
(/home/maja/context/tex/texmf-context/tex/context/base/cont-new.mkiv
system beware: some patches loaded from cont-new.mkiv
)
system files jobname 'sqrt', input 'sqrt', result 'sqrt'
fontslatin modern fonts are not preloaded
languages
On 4/9/2013 9:02 PM, Xenia wrote:
Hi list,
I noticed that the sign for the square root does not adapt to the size
of a fraction as in the attached minimal example.
In what sense? Sqrt's grow in discrete steps.
Hans
-
On 09.04.2013 21:18, Hans Hagen wrote:
On 4/9/2013 9:02 PM, Xenia wrote:
Hi list,
I noticed that the sign for the square root does not adapt to the size
of a fraction as in the attached minimal example.
In what sense? Sqrt's grow in discrete steps.
Oh, I didn't know that. For my feelings,
On 4/9/2013 9:25 PM, Xenia wrote:
On 09.04.2013 21:18, Hans Hagen wrote:
On 4/9/2013 9:02 PM, Xenia wrote:
Hi list,
I noticed that the sign for the square root does not adapt to the size
of a fraction as in the attached minimal example.
In what sense? Sqrt's grow in discrete steps.
Oh, I
On Tue, 9 Apr 2013 21:25:16 +0200
Xenia yor...@googlemail.com wrote:
Oh, I didn't know that. For my feelings, all variables should have the
same size here (a,b and c).
In this case you should probably use:
a = \sqrt{b/c}
Alan
On 09.04.2013 22:39, Alan BRASLAU wrote:
On Tue, 9 Apr 2013 21:25:16 +0200
Xenia yor...@googlemail.com wrote:
Oh, I didn't know that. For my feelings, all variables should have the
same size here (a,b and c).
In this case you should probably use:
a = \sqrt{b/c}
Okay, but this was just
=script,color=red]
\definemathfraction[outerfrac][frac][alternative=outer,mathstyle=script,color=blue]
\starttext
\startformula
a = \frac{b}{c} = \sqrt{\frac{b}{c}} = \sqrt{{b}\over{c}}
a = \frac{b}{c} = \sqrt{\frac{b}{c}} = \sqrt{{b}\over{c}}
a = \outerfrac{a}{b
On 4/9/2013 10:39 PM, Alan BRASLAU wrote:
On Tue, 9 Apr 2013 21:25:16 +0200
Xenia yor...@googlemail.com wrote:
Oh, I didn't know that. For my feelings, all variables should have the
same size here (a,b and c).
In this case you should probably use:
a = \sqrt{b/c}
there was a wrong default
On Tue, Apr 09, 2013 at 10:39:25PM +0200, Alan BRASLAU wrote:
On Tue, 9 Apr 2013 21:25:16 +0200
Xenia yor...@googlemail.com wrote:
Oh, I didn't know that. For my feelings, all variables should have the
same size here (a,b and c).
In this case you should probably use:
a = \sqrt{b/c
) +
U(t-s)) + \frac{(S(u-t) +
U(t-s))^2}{(u-s)}}{2(t-s)(u-t)}}}{\sqrt{2\pi\frac{(t-s)(u-t)}{u-s}}}
\stopformula
Thanks,
Janne
Roland wrote:
With \dfrac it looks good.
With \fraction the minus sign is on the top of the fraction.
Best regards, Roland
, B_u = U}(x) = \frac{e^{-\frac{(u-s)x^2 - 2x(S(u-t) +
U(t-s)) + \frac{(S(u-t) +
U(t-s))^2}{(u-s)}}{2(t-s)(u-t)}}}{\sqrt{2\pi\frac{(t-s)(u-t)}{u-s}}}
\stopformula
Thanks,
Janne
OK !
So you need an expert, I'm just a newbie :)
I would be interested to know how to do that.
Best, Roland
formula I have is
\startformula
f_{B_t | B_s = S, B_u = U}(x) = \frac{e^{-\frac{(u-s)x^2 - 2x(S(u-t) +
U(t-s)) + \frac{(S(u-t) +
U(t-s))^2}{(u-s)}}{2(t-s)(u-t)}}}{\sqrt{2\pi\frac{(t-s)(u-t)}{u-s}}}
\stopformula
Thanks,
Janne
OK !
So you need an expert, I'm just a newbie :)
I would be interested
with
script-size or scriptscript-size (\xfrac, \xxfrac). The specific
formula I have is
\startformula
f_{B_t | B_s = S, B_u = U}(x) = \frac{e^{-\frac{(u-s)x^2 - 2x(S(u-t) +
U(t-s)) + \frac{(S(u-t) +
U(t-s))^2}{(u-s)}}{2(t-s)(u-t)}}}{\sqrt{2\pi\frac{(t-s)(u-t)}{u-s}}}
\stopformula
Thanks,
Janne
Using \type{\frac} gives:
\startformula
f_{B_t | B_s = S, B_u = U}(x) = \frac{e^{-\frac{(u-s)x^2 - 2x(S(u-t) +
U(t-s)) + \frac{(S(u-t) +
U(t-s))^2}{(u-s)}}{2(t-s)(u-t)}}}{\sqrt{2\pi\frac{(t-s)(u-t)}{u-s}}}
\stopformula
\blank
Using \type{\over} gives:
\startformula
f_{B_t | B_s = S, B_u = U}(x
the second is more or less what you want
\starttext
Using \type{\frac} gives:
\startformula
f_{B_t | B_s = S, B_u = U}(x) = \frac{e^{-\frac{(u-s)x^2 - 2x(S(u-t) +
U(t-s)) + \frac{(S(u-t) +
U(t-s))^2}{(u-s)}}{2(t-s)(u-t)}}}{\sqrt{2\pi\frac{(t-s)(u-t)}{u-s}}}
\stopformula
Formatting and temporary macros
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