Re: [NTG-context] \dh in ConTeXt

2004-09-15 Thread Charles Doherty
On 14 Sep 2004, at 12:17, Taco Hoekwater wrote: Howth {\em H\k{o}f\eth i} / {\em H\k{o}f\eth a}, (LaTeX 'dh' = [eE]th, 'th'= [tT]horn, 'ng' = [eE]ng) Greetings, Taco Dear Taco, Thank you very much for your reply. I get ? when I use the above. But I just chanced mathmode {\em H\k{o}f$\eth$i} /

Re: [NTG-context] \dh in ConTeXt

2004-09-15 Thread Mari Voipio
On Wed, 15 Sep 2004, Charles Doherty wrote: On 14 Sep 2004, at 12:17, Taco Hoekwater wrote: Howth {\em H\k{o}f\eth i} / {\em H\k{o}f\eth a}, (LaTeX 'dh' = [eE]th, 'th'= [tT]horn, 'ng' = [eE]ng) Thank you very much for your reply. I get ? when I use the above. I get ? if I try with the

Re: [NTG-context] \dh in ConTeXt

2004-09-14 Thread Taco Hoekwater
Hi Charles, Try this: Howth {\em H\k{o}f\eth i} / {\em H\k{o}f\eth a}, (LaTeX 'dh' = [eE]th, 'th'= [tT]horn, 'ng' = [eE]ng) Greetings, Taco On Mon, 13 Sep 2004 12:18:29 +0100 Charles Doherty [EMAIL PROTECTED] wrote: Dear all, Using the following input in LaTeX I could get the output