On Mon, May 4, 2009 at 12:31 AM, Chris Colbert sccolb...@gmail.com wrote:
this actually sort of worked. Thanks for putting me on the right track.
Here is what I ended up with.
this is what I ended up with:
def hist3d(imgarray):
histarray = N.zeros((16, 16, 16))
temp =
Neal Becker wrote:
Suggestion for efficient way to apply a table lookup to each element of an
integer array?
import numpy as np
_cos = np.empty ((2**rom_in_bits,), dtype=int)
_sin = np.empty ((2**rom_in_bits,), dtype=int)
for address in xrange (2**12):
_cos[address] = nint
2009/5/4 Neal Becker ndbeck...@gmail.com:
Turns out that if A is an np.array and B is an np.array, then
A[B] will do exactly what I wanted.
Is this mentioned anywhere in the documentation?
http://docs.scipy.org/numpy/docs/numpy-docs/reference/arrays.indexing.rst/#arrays-indexing
Stéfan
David Cournapeau wrote:
On Mon, May 4, 2009 at 1:24 AM, Dag Sverre Seljebotn
da...@student.matnat.uio.no wrote:
David Cournapeau wrote:
On Fri, Apr 24, 2009 at 4:49 PM, Dag Sverre Seljebotn
One thing somebody *could* work on rather independently for some hours
is proper PEP
Neal Becker wrote:
Charles R Harris wrote:
On Fri, May 1, 2009 at 7:39 PM, Charles R Harris
charlesr.har...@gmail.comwrote:
On Fri, May 1, 2009 at 7:24 PM, Neal Becker ndbeck...@gmail.com wrote:
Charles R Harris wrote:
On Fri, May 1, 2009 at 1:02 PM, Neal
Hello list,
is there a possibility to scale an array by interpolation,
automatically? For illustration a 1D-example would be an array of size
5, which is scaled to size 3:
before: [ 1, 2, 3, 4, 5 ]
1/1 2/3
1/3 1 1/3
2/3 1
after : [
scipy.ndimage.zoom (and related interpolation functions) would be a
good bet -- different orders of interpolation are available, too,
which can be useful.
Zach
On May 4, 2009, at 11:40 AM, Johannes Bauer wrote:
Hello list,
is there a possibility to scale an array by interpolation,
Hi,All:
My first post! I am very excited to find out structured array (record array) in
Python. Since I do data manipulation every day, this is truly great. However, I
typically download data using pyodbc, the default output is a big list. So I am
wondering how to convert that big list into a
Hi all,
How can I define a stop criterion for an alternating
series ?
Any pointer would be appreciated.
Nils
from numpy import loadtxt, arange
from pylab import plot, show
A = loadtxt('alternate.dat')
m = len(A)
x = arange(0,m)
plot(x,A)
show()
alternate.dat
Description: MPEG movie
On Mon, May 4, 2009 at 10:48 AM, Nils Wagner
nwag...@iam.uni-stuttgart.dewrote:
Hi all,
How can I define a stop criterion for an alternating series ?
Any pointer would be appreciated.
Where does the series come from and what are you trying to do?
Chuck
On Mon, 4 May 2009 10:52:59 -0600
Charles R Harris charlesr.har...@gmail.com wrote:
On Mon, May 4, 2009 at 10:48 AM, Nils Wagner
nwag...@iam.uni-stuttgart.dewrote:
Hi all,
How can I define a stop criterion for an alternating
series ?
Any pointer would be appreciated.
Where does the
Zachary Pincus schrieb:
scipy.ndimage.zoom (and related interpolation functions) would be a
good bet -- different orders of interpolation are available, too,
which can be useful.
Thanks a lot - exactly what I was looking for!
Kind regards,
Johannes
Neal Becker wrote:
In [3]: n=-7
In [4]: (np.linspace (0, 1023,1024).astype(np.uint64)*n).dtype
Out[4]: dtype('float64')
what would you like (expect) to happen when you multiply an unsigned
type by a negative number?
-Chris
--
Christopher Barker, Ph.D.
Oceanographer
Emergency Response
On Mon, May 4, 2009 at 10:59 AM, Nils Wagner
nwag...@iam.uni-stuttgart.dewrote:
On Mon, 4 May 2009 10:52:59 -0600
Charles R Harris charlesr.har...@gmail.com wrote:
On Mon, May 4, 2009 at 10:48 AM, Nils Wagner
nwag...@iam.uni-stuttgart.dewrote:
Hi all,
How can I define a stop
On Mon, May 4, 2009 at 7:00 AM, josef.p...@gmail.com wrote:
On Mon, May 4, 2009 at 12:31 AM, Chris Colbert sccolb...@gmail.com
wrote:
this actually sort of worked. Thanks for putting me on the right track.
Here is what I ended up with.
this is what I ended up with:
def
i'll take a look at them over the next few days and see what i can hack out.
Chris
On Mon, May 4, 2009 at 3:18 PM, David Huard david.hu...@gmail.com wrote:
On Mon, May 4, 2009 at 7:00 AM, josef.p...@gmail.com wrote:
On Mon, May 4, 2009 at 12:31 AM, Chris Colbert sccolb...@gmail.com
Hello,
I'm new to numpy, and considering using loadtxt() to read a data file.
As a starter, I tried the example of the doc page (
http://docs.scipy.org/doc/numpy/reference/generated/numpy.loadtxt.html) :
from StringIO import StringIO # StringIO behaves like a file object
c = StringIO(0
On Mon, May 4, 2009 at 3:06 PM, bruno Piguet bruno.pig...@gmail.com wrote:
Hello,
I'm new to numpy, and considering using loadtxt() to read a data file.
As a starter, I tried the example of the doc page (
http://docs.scipy.org/doc/numpy/reference/generated/numpy.loadtxt.html) :
from
On Mon, May 4, 2009 at 4:00 PM, Chris Colbert sccolb...@gmail.com wrote:
i'll take a look at them over the next few days and see what i can hack out.
Chris
On Mon, May 4, 2009 at 3:18 PM, David Huard david.hu...@gmail.com wrote:
On Mon, May 4, 2009 at 7:00 AM, josef.p...@gmail.com wrote:
Hi,
Is there a simple way to compare each element of an object array to a
single object? objarray == None, for example, gives me a single
False. I couldn't find any reference to it in the documentation, but
I'll admit, I wasn't quite sure where to look.
David
On Mon, May 4, 2009 at 3:55 PM, David Warde-Farley d...@cs.toronto.eduwrote:
Hi,
Is there a simple way to compare each element of an object array to a
single object? objarray == None, for example, gives me a single
False. I couldn't find any reference to it in the documentation, but
I'll
On Mon, May 4, 2009 at 2:02 PM, Ryan May rma...@gmail.com wrote:
On Mon, May 4, 2009 at 3:55 PM, David Warde-Farley d...@cs.toronto.edu
wrote:
Hi,
Is there a simple way to compare each element of an object array to a
single object? objarray == None, for example, gives me a single
False. I
The following code:
from scipy import *
from scipy import linalg
m = matrix( [ [1,1,0,0],
[1,1,0,0],
[0,0,1,1],
[0,0,1,1] ] )
u,s,v = linalg.svd( m )
fails with the following message:
Traceback (most recent call last):
File boo.py,
I have been working on a open source face recognition demo tool called
FaceL for the past few months. FaceL is a simple and fun face
processing and labeling tool that labels faces in a live video from an
iSight camera or webcam. It uses OpenCV for face detection, ASEF
correlation
Hi Philipp
2009/5/5 Philipp K. Janert pyt...@beyondcode.org:
If I see this correctly, my SciPy version
is 0.6.0; running on 64bit Suse 11.
SciPy 0.6 is quite old, and it is likely that the problem was fixed in
the mean time.
On SciPy 0.7 I see:
In [31]: u,s,v = linalg.svd(m)
In [32]: u
2009/5/5 David Bolme bolme1...@comcast.net:
I have been working on a open source face recognition demo tool called
FaceL for the past few months. FaceL is a simple and fun face processing
and labeling tool that labels faces in a live video from an iSight camera or
webcam.
That's really neat
Thanks for the quick reply. I'll try upgrading.
Best,
Ph.
On Monday 04 May 2009 04:21:29 pm Stéfan van der Walt wrote:
Hi Philipp
2009/5/5 Philipp K. Janert pyt...@beyondcode.org:
If I see this correctly, my SciPy version
is 0.6.0; running on 64bit Suse 11.
SciPy 0.6
Hi,
I'm trying to fix a bug in the scipy matlab loading routines, and this
requires me to somehow represent an empty structured array.
Do you need the struct to be empty (size is 0) or to have no fields ?
What would you expect np.zeros((), dtype=np.dtype([])) to return, for
example ?
Yes,
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