You might want to look at http://www.research.ibm.com/showdown
specifically http://www.research.ibm.com/dx/showdown/ds4html/ds4.html for netcdf
multiresolution datasets and http://w3.pppl.gov/vde2000/data/OPENDX/ds4/ for
the
nets/macros .
Pete
Thomas Wolfanger wrote:
Hello,
I´m new to
The bummer is that this means that the code for the divergence and curl
assume a cartesian coordinate system.
no, not correct. they only assume the coordinate system axes are
orthogonal to each other in that coordinate system. so they can
be [r,phi,z] and it all just works. you compute curl
Nancy,
I'm afraid I don't understand how to do this. How can I convert a
position (r,phi=0,z) to a circular line in (x,y,z)? Right, to display
cylindrically symmetric data originally described in the (r,z) plane as a
full 3-D cylindrically symmetric object, I would need to map the position
say
it is true that dx won't draw curved lines between 2 vertices;
the spacing of the vertices will indeed control how smooth your
curve plots, but my point is that if you do your computation before
you convert from [r,z] to cartesian, it won't matter. it will be
doing a real linear interpolation in
This discussion is becoming painful. What we have here is a failure to
communicate.
Nancy is talking about a transform of coordinates that would, for
example, take a 2D rectangle and wrap it around a cylinder (form the
outside surface of a coffee can perhaps). This is a surface to surface
