Dear Gurus !
Lots of thanks to everybody who replied.
I've got numerous great solutions from U - now i need to choose one among
them ;-)
This is a great list with genius people subscribed !
I love to belong to Oracle DBAs brotherhood.
Thank U all very much & have a great day !
-----Original Message-----
Sent: Wednesday, August 15, 2001 5:02 PM
To: Multiple recipients of list ORACLE-L
Yes, so the maximum is 3, between 12:25 and 12:30. To explicitly show the
maximum (and a little histogram) you could amend it as follows: -
declare
l_count pls_integer := 0;
l_max_count pls_integer := 0;
begin
for rec in (
select call_start time, 1 incr from table
union all
select call_end time, -1 incr from table
order by 1
) loop
l_count := l_count + rec.incr;
if( l_count > l_max_count ) then
l_max_count := l_count;
end if;
dbms_output.put_line( to_char(rec.time) || ' - ' || l_count
|| ' ' || lpad('*',l_count) )
end loop;
dbms_output.put_line( 'Maximum concurrent calls = ' ||
to_char(l_max_count) );
end;
Regards
David Lord
> -----Original Message-----
> From: Thomas, Kevin [mailto:[EMAIL PROTECTED]]
> Sent: 15 August 2001 15:07
> To: Multiple recipients of list ORACLE-L
> Subject: RE: An SQL question , not easy ;-)
>
>
> David,
>
> Here's the output from your suggestion based on a table
> with the following rows;
>
> CALL_START CALL_END
> ----------------- -----------------
> 01-AUG-2001 12:10 01-AUG-2001 12:40
> 01-AUG-2001 12:15 01-AUG-2001 12:30
> 01-AUG-2001 12:25 01-AUG-2001 12:55
> 01-AUG-2001 12:45 01-AUG-2001 12:47
>
> ---------------------
>
> 01-AUG-2001 12:10 - 1
> 01-AUG-2001 12:15 - 2
> 01-AUG-2001 12:25 - 3
> 01-AUG-2001 12:30 - 2
> 01-AUG-2001 12:40 - 1
> 01-AUG-2001 12:45 - 2
> 01-AUG-2001 12:47 - 1
> 01-AUG-2001 12:55 - 0
>
>
>
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Author: Andrey Bronfin
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