Damian Stewart wrote:
is there a pure Pd way to remove NaNs? i can't use expr with rjdj..
i thought expr is part of the RjDj distro...
but then: you can test while i cannot.
and this might be one of the later this week licensing things.
fgmasdr
IOhannes
Hallo,
IOhannes m zmoelnig hat gesagt: // IOhannes m zmoelnig wrote:
Damian Stewart wrote:
is there a pure Pd way to remove NaNs? i can't use expr with rjdj..
i thought expr is part of the RjDj distro...
Only the BSD parts of Pd are included in RjDj at the moment, so you
cannot use expr -
Frank Barknecht wrote:
Hallo,
IOhannes m zmoelnig hat gesagt: // IOhannes m zmoelnig wrote:
Damian Stewart wrote:
is there a pure Pd way to remove NaNs? i can't use expr with rjdj..
i thought expr is part of the RjDj distro...
Only the BSD parts of Pd are included in RjDj at the moment,
Damian Stewart wrote:
Frank Barknecht wrote:
Hallo,
IOhannes m zmoelnig hat gesagt: // IOhannes m zmoelnig wrote:
Damian Stewart wrote:
is there a pure Pd way to remove NaNs? i can't use expr with rjdj..
i thought expr is part of the RjDj distro...
Only
On Wed, 29 Oct 2008 17:55:00 +0100
Gunter Geiger [EMAIL PROTECTED] wrote:
Only the BSD parts of Pd are included in RjDj at the moment, so you
cannot use expr - which is tricky, as in fact there are several math
functions missing now in RjDj's Pd, for example no [pow~] yet - but
this will
On Wed, Oct 29, 2008 at 11:55 AM, Gunter Geiger [EMAIL PROTECTED] wrote:
Adding this functionality would be trivial, if you want you can add
a ticket on track regarding the issue. In the long run the correct solution
would be to try to figure out why there are NaN's ... and fix it there.
My best guess is that NaN's come from underflow, under normal
circumstances. I wish there would be an easy way to change this
behavior via a compiler flag, but I don't think there is.
It seems to be a more pervasive problem, and it's unreasonable to
expect to add NaN handlers in application
Charles Henry wrote:
My best guess is that NaN's come from underflow, under normal
circumstances. I wish there would be an easy way to change this
behavior via a compiler flag, but I don't think there is.
It seems to be a more pervasive problem, and it's unreasonable to
expect to add
is there a pure Pd way to remove NaNs? i can't use expr with rjdj..
d
--
damian stewart | skype: damiansnz | [EMAIL PROTECTED]
frey | live art with machines | http://www.frey.co.nz
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David Brynjar Franzson wrote:
the expr works fine with expr (isnan($f1), 0, $f1). The route f method
doesn't work since NaN is treated as a valid floating point number.
on pd-0.40-3-extended (osx intel) trying to use this i get :
expr: syntax error: illegal comma
,
0
,
$f1
error: expr:
Damian Stewart wrote:
David Brynjar Franzson wrote:
the expr works fine with expr (isnan($f1), 0, $f1). The route f method
doesn't work since NaN is treated as a valid floating point number.
on pd-0.40-3-extended (osx intel) trying to use this i get :
expr: syntax error: illegal comma
Hi,
is there any simple way to replace all NaN values with Zeros or
to filter them out?
thanks,
David Brynjar
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David Brynjar Franzson wrote:
Hi,
is there any simple way to replace all NaN values with Zeros or
to filter them out?
If you do not have lists, then route should do the trick:
[route f]
| |
| [0(
cu Thomas
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Prisons are needed only to provide the illusion that courts and
[expr] contains a function 'isnan'.
Not sure how to use it though.
can someone give an example ?
Tim
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the expr works fine with expr (isnan($f1), 0, $f1). The route f method
doesn't work since NaN is treated as a valid floating point number.
thanks for the help,
David Brynjar
On Sat, Sep 13, 2008 at 11:05 AM, tim [EMAIL PROTECTED] wrote:
[expr] contains a function 'isnan'.
Not sure how to use
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