Re: Strange Question? Is compiler fault?

All: I will find the truth by ur help, I think follow code excute has 3 steps ==code= $i = 0; $i = $i++; ==code= 1. $i = 0; 2. $i = 1;( cause $i++ ) 3. $i = 0;( cause $i = $i ) the third step is strange, because $i = 1; why $i = $i get result 0, $i has 2 memory block to

RE: Strange Question? Is compiler fault?

: [EMAIL PROTECTED] Subject: Re: Strange Question? Is compiler fault? All: I will find the truth by ur help, I think follow code excute has 3 steps ==code= $i = 0; $i = $i++; ==code= 1. $i = 0; 2. $i = 1;( cause $i++ ) 3. $i = 0;( cause $i

Strange Question? Is compiler fault?

All: I excute follow code got some Strange result, Why? Why $i = 0 === $i = 0; $i = $i++; print $i\n; === ___ Perl-Win32-Users mailing list [EMAIL PROTECTED]

Re: Strange Question? Is compiler fault?

cloud wrote: although $i = $i run before $i++, But the increment should be work, so $i should be 1, isn't it? The precedence of ++ is higher than = , so the increment takes place making $i = 1 and then $1 is set to the orig $i before the increment. Replace $i = $i++; with just

Re: Strange Question? Is compiler fault?

$i=0;$i++;print$i\n; will return 1 Chris Lerma ~~~ Lerma New Media 661.319.2412 cel 661.387.0868 phone/fax [EMAIL PROTECTED] www.LermaNewMedia.com ___ Perl-Win32-Users mailing list [EMAIL PROTECTED]

Re: Strange Question? Is compiler fault?

- Original Message - From: cloud [EMAIL PROTECTED] To: Paul G. Weiss [EMAIL PROTECTED] Cc: '[EMAIL PROTECTED]' [EMAIL PROTECTED] Sent: Friday, June 15, 2001 1:59 PM Subject: Re: Strange Question? Is compiler fault? although $i = $i run before $i++, But the increment should be work

Re: Strange Question? Is compiler fault?

All: the precedence ++ is higer than =, thx -Paul, $Bill Luebkert I know my sample is strange, I just confuse by that why $x = $i++; $x = 1; but $i = $i++; $i = 0; although $i = $i run before $i++, But the increment should be work, so $i should be 1, isn't it? Hi, Your script can

Re: Strange Question? Is compiler fault?

All: I paest wrong sample, fllow is correct why $x = $i++; $i = 1; but $i = $i++; $i = 0; All: the precedence ++ is higer than =, thx -Paul, $Bill Luebkert I know my sample is strange, I just confuse by that why $x = $i++; $x = 1; but $i = $i++; $i = 0; although $i = $i run

Re: Strange Question? Is compiler fault?

Question? Is compiler fault? The expression $i++ has the *effect* of incrementing $i but its *value* is the value of $i before the increment. So the assignment $i = $i++; is a no-op, because you are assigning to $i the value that it had before the increment. -Paul On Fri, 15 Jun 2001

Re: Strange Question? Is compiler fault?

it? - Original Message - From: Paul G. Weiss [EMAIL PROTECTED] To: cloud [EMAIL PROTECTED] Cc: '[EMAIL PROTECTED]' [EMAIL PROTECTED] Sent: Friday, June 15, 2001 11:42 AM Subject: Re: Strange Question? Is compiler fault? The expression $i++ has the *effect* of incrementing $i but its