HaloO,
Luke Palmer wrote:
On 8/3/05, Aankhen [EMAIL PROTECTED] wrote:
On 8/3/05, Piers Cawley [EMAIL PROTECTED] wrote:
So how *do* I pass an unflattened array to a function with a slurpy parameter?
Good question. I would have thought that one of the major gains from
turning arrays and
HaloO,
Piers Cawley wrote:
By the way, if flattening that way, what's the prototype for zip? We can after
all do:
zip @ary1, @ary2, @ary3, ... @aryn
How about
sub zip( List [EMAIL PROTECTED] ) {...}
a slurpy List of Array of List. The return value is a
not yet iterated Code object
Luke Palmer [EMAIL PROTECTED] writes:
On 7/26/05, Ingo Blechschmidt [EMAIL PROTECTED] wrote:
Hi,
are the following assumptions correct?
sub foo ([EMAIL PROTECTED]) { @args[0] }
say ~foo(a, b, c); # a
Yep.
my @array = a b c d;
say ~foo(@array);# a b c d (or
On 8/3/05, Piers Cawley [EMAIL PROTECTED] wrote:
So how *do* I pass an unflattened array to a function with a slurpy parameter?
Good question. I would have thought that one of the major gains from
turning arrays and hashes into references in scalar context is the
ability to specify an
On 8/3/05, Aankhen [EMAIL PROTECTED] wrote:
On 8/3/05, Piers Cawley [EMAIL PROTECTED] wrote:
So how *do* I pass an unflattened array to a function with a slurpy
parameter?
Good question. I would have thought that one of the major gains from
turning arrays and hashes into references in
[EMAIL PROTECTED] wrote:
So how *do* I pass an unflattened array to a function with a slurpy parameter?
I don't ~~ @larry, but my guess(es) would be bar([EMAIL PROTECTED]) or
bar([EMAIL PROTECTED])
Miro
Luke Palmer [EMAIL PROTECTED] writes:
On 8/3/05, Aankhen [EMAIL PROTECTED] wrote:
On 8/3/05, Piers Cawley [EMAIL PROTECTED] wrote:
So how *do* I pass an unflattened array to a function with a slurpy
parameter?
Good question. I would have thought that one of the major gains from
Ingo Blechschmidt wrote:
Hi,
ReHi,
are the following assumptions correct?
I don't know in general. But see my assumptions below
for comparison. They are derived from my type theoretic
approach and as such might collide with Perl6's referential
semantics. In particular with the
On 7/26/05, Ingo Blechschmidt [EMAIL PROTECTED] wrote:
Hi,
are the following assumptions correct?
sub foo ([EMAIL PROTECTED]) { @args[0] }
say ~foo(a, b, c); # a
Yep.
my @array = a b c d;
say ~foo(@array);# a b c d (or a?)
say ~foo(@array, z); # a b c
Hi,
are the following assumptions correct?
sub foo ([EMAIL PROTECTED]) { @args[0] }
say ~foo(a, b, c); # a
my @array = a b c d;
say ~foo(@array);# a b c d (or a?)
say ~foo(@array, z); # a b c d (or a?)
say ~foo([EMAIL PROTECTED]); # a
say
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