Apropos of nothing...

2001-12-13 Thread Piers Cawley
In the following code fragment, what context is foo() in? @ary[0] = foo() the following code @ary= foo() obviously evaluates @foo in a list context, but in the first I'm no longer sure. -- Piers It is a truth universally acknowledged that a language in possession of a

Re: Apropos of nothing...

2001-12-13 Thread Ted Ashton
Thus it was written in the epistle of Piers Cawley, In the following code fragment, what context is foo() in? @ary[0] = foo() Scalar, I would think. Just my guess, Ted -- Ted Ashton ([EMAIL PROTECTED]) | From the Tom Swifty collection: Southern Adventist University| Multiplication

Re: Apropos of nothing...

2001-12-13 Thread Mark J. Reed
On Thu, Dec 13, 2001 at 12:12:14PM -0500, Ted Ashton wrote: Thus it was written in the epistle of Piers Cawley, In the following code fragment, what context is foo() in? @ary[0] = foo() Scalar, I would think. I assume that the following would make the assignment a slice and

RE: Apropos of nothing...

2001-12-13 Thread Brent Dax
Piers Cawley: # In the following code fragment, what context is foo() in? # # @ary[0] = foo() The short answer is scalar context. The long answer is below. Note that the long answer is only the way I think of it. You may think differently. I like to think of it as 'one context'.

Re: Apropos of nothing...

2001-12-13 Thread Damian Conway
In the following code fragment, what context is foo() in? @ary[0] = foo() Scalar context. @ary[0] is a single element of @ary. To call foo() in list context use any of the following: (@ary[0]) = foo(); # Assign @ary[0] the first element returned

Re: Apropos of nothing...

2001-12-13 Thread Graham Barr
On Fri, Dec 14, 2001 at 06:39:02AM +1100, Damian Conway wrote: In the following code fragment, what context is foo() in? @ary[0] = foo() Scalar context. @ary[0] is a single element of @ary. To call foo() in list context use any of the following: (@ary[0]) =

Re: Apropos of nothing...

2001-12-13 Thread Damian Conway
@ary[0] =()= foo(); # Hm, thats a change from perl5. In perl5 that would assign the number of elements returned from foo(). Is there a good reason for this change ? Firstly, Larry may have to rule on which behaviour actually *is* invoked

Re: Apropos of nothing...

2001-12-13 Thread Piers Cawley
Brent Dax [EMAIL PROTECTED] writes: Piers Cawley: # In the following code fragment, what context is foo() in? # # @ary[0] = foo() The short answer is scalar context. The long answer is below. Note that the long answer is only the way I think of it. You may think differently. I