On Thu, 24 Jun 2004 10:55:26 -0700, Larry Wall [EMAIL PROTECTED] wrote:
Well, any operator or function that knows how to call a closure can
function as a short-circuit operator. The built-in short-circuit
operators are a bit special insofar as they're a kind of macro that
treats the right side
AFAIR, I've seen in some Apocalypse that lexical scope boundaries will be
the same as boundaries of block, in which lexical variable was defined.
so, my question is, what the scope of variables, defined in Cif and
Cloop conditions?
in perl5:
my $a=first\n;
if (my $a=second\n) {print $a}
Alexey Trofimenko writes:
On Thu, 24 Jun 2004 10:55:26 -0700, Larry Wall [EMAIL PROTECTED] wrote:
Well, any operator or function that knows how to call a closure can
function as a short-circuit operator. The built-in short-circuit
operators are a bit special insofar as they're a kind of
Alexey Trofimenko writes:
AFAIR, I've seen in some Apocalypse that lexical scope boundaries will be
the same as boundaries of block, in which lexical variable was defined.
Yep. Except in the case of routine parameters, but that's nothing new.
so, my question is, what the scope of
