On Mon, 28 Oct 2002 13:09:37 -0800 (PST), Larry Wall [EMAIL PROTECTED] wrote:
How do your read $a ! $b ! $c?
Neither $a nor $b nor $c.
What? Aren't you able to see this invisible neither operator just at
the front? ;-)
/L/e/k/t/u
Scott Duff wrote:
Actually, I think we need a universal method on scalars that
gives the eigenstates of that value. It might be C$val.eigenstates
or maybe just C$val.states. The method would work on non-superimposed
values as well, in which cases it would just return a list containing
the value
On Sunday, October 27, 2002, at 12:57 PM, Michael Lazzaro wrote:
.= .|= .\= = = - (depending on operants)
s/operants/operands/
Sorry bout that. Typing too fast.
MikeL
On Sun, 27 Oct 2002, Michael Lazzaro wrote:
: If \ meant xor, and some of the other discussed changes:
I mislike \ for xor, primarily because it doesn't fit into the current
escape mystique of \.
Larry
Since xor is really low frequency, why not make xor mean xor?
$zero = $a xor $a;
$a xor= $b;
$b xor= $a xor= $b xor= $a; # Swap'em
@a ^xor= @b; # Is this right?
=Austin
--- Larry Wall [EMAIL PROTECTED] wrote:
On Sun, 27 Oct 2002, Michael Lazzaro wrote:
: If \ meant xor, and some of the
On Mon, Oct 28, 2002 at 09:41:37AM -0800, Larry Wall wrote:
On Sun, 27 Oct 2002, Michael Lazzaro wrote:
: If \ meant xor, and some of the other discussed changes:
I mislike \ for xor, primarily because it doesn't fit into the current
escape mystique of \.
Does xor really need the
On Monday, October 28, 2002, at 09:58 AM, Jonathan Scott Duff wrote:
Does xor really need the punctuation? Does xor really need to be a
primitive?
Though bitwise xor is seldom used for most people, other versions are
likely to be more frequent: the 'superpositional' flavor, for example,
is
On Mon, Oct 28, 2002 at 10:11:43AM -0800, Michael Lazzaro wrote:
Though bitwise xor is seldom used for most people, other versions are
likely to be more frequent: the 'superpositional' flavor, for example,
is likely to have significant meaning. Same with 'none', I expect.
| \
On Mon, 28 Oct 2002, Michael Lazzaro wrote:
: On Monday, October 28, 2002, at 09:58 AM, Jonathan Scott Duff wrote:
: Does xor really need the punctuation? Does xor really need to be a
: primitive?
:
: Though bitwise xor is seldom used for most people, other versions are
: likely to be more
Larry Wall:
# and then I looked crosseyed at the // vs \\ proposals, and I
# realized we have a superposition of / and \ that is spelled X. :-)
use Perl::Caseless;
print foo x 6;#?!?
--Brent Dax [EMAIL PROTECTED]
@roles=map {Parrot $_} qw(embedding regexen Configure)
On Mon, Oct 28, 2002 at 11:55:24AM -0800, Larry Wall wrote:
Well, I don't believe in none since it's really easy to say !any()
Does that have any implications for unless?
--
Paul Johnson - [EMAIL PROTECTED]
http://www.pjcj.net
On Mon, 28 Oct 2002, Paul Johnson wrote:
: On Mon, Oct 28, 2002 at 11:55:24AM -0800, Larry Wall wrote:
:
: Well, I don't believe in none since it's really easy to say !any()
:
: Does that have any implications for unless?
No. unless reads well in English. How do your read $a ! $b ! $c?
(When
On Monday, October 28, 2002, at 01:09 PM, Larry Wall wrote:
No. unless reads well in English. How do your read $a ! $b ! $c?
nor? Maybe it's $a nor $b?
MikeL
If you guys start trying to reserve punctuation for XNOR, the next perl
cruise is going to be through the Bermuda Triangle...
=Austin
--- Jonathan Scott Duff [EMAIL PROTECTED] wrote:
On Mon, Oct 28, 2002 at 01:19:05PM -0800, Michael Lazzaro wrote:
On Monday, October 28, 2002, at 01:09 PM,
On Mon, Oct 28, 2002 at 03:30:54PM -0600, Jonathan Scott Duff wrote:
On Mon, Oct 28, 2002 at 01:19:05PM -0800, Michael Lazzaro wrote:
On Monday, October 28, 2002, at 01:09 PM, Larry Wall wrote:
No. unless reads well in English. How do your read $a ! $b ! $c?
nor? Maybe it's $a
[EMAIL PROTECTED] (Larry Wall) writes:
: On Mon, Oct 28, 2002 at 11:55:24AM -0800, Larry Wall wrote:
: Well, I don't believe in none since it's really easy to say !any()
:
: Does that have any implications for unless?
No. unless reads well in English. How do your read $a ! $b ! $c?
You
Scott Duff asked:
How do we get at the eigenstates of a superposition?
We obviously need another operator! ducks
Actually, I think we need a universal method on scalars that
gives the eigenstates of that value. It might be C$val.eigenstates
or maybe just C$val.states. The method would work
On Tue, Oct 29, 2002 at 03:58:57PM +1100, Damian Conway wrote:
Actually, I think we need a universal method on scalars that
gives the eigenstates of that value. It might be C$val.eigenstates
or maybe just C$val.states. The method would work on non-superimposed
values as well, in which cases it
If \ meant xor, and some of the other discussed changes:
unary (prefix) operators:
\ - reference to
* - list flattening
? - force to bool context
! - force to bool context, negate
not - force to bool context, negate
+ - force to numeric context
- - force
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