John Williams wrote:
Back in October I suggested that $a ^+= b would act like reduce,
but in discussion
it was decided that it would act like length
I now pose the question: Is ^+= a hyper assignment operator or an
assignment hyper operator?
with a scalar involved
the method and
Apologies for trying to resuscitate this old horse, but a new idea
occurred to me.
Back in October I suggested that $a ^+= b would act like reduce,
but in discussion
it was decided that it would act like length, by the interpretation:
$a ^+= b
$a = $a ^+ b
$a = ($a, $a, $a, ...)
