Roger Hale wrote:
One set of cases that doesn't seem to have come up in discussion:
(1, 3, 2) - (83, 84, 81, 80, 85)
Should this give
(-82, -81, -79, -80, -85)
From an arithmetic point of view it should be exactly that. The
implementation might need to morph the code though, see below.
as
Thomas Sandla wrote:
John Williams wrote:
Good point. Another one is: how does the meta_operator determine the
identity value for user-defined operators?
Does it have to? The definition of the identity value---BTW, I like
the term neutral value better because identity also is a relation
between
John Williams wrote:
Good point. Another one is: how does the meta_operator determine the
identity value for user-defined operators?
Does it have to? The definition of the identity value---BTW, I like
the term neutral value better because identity also is a relation
between two values---is that
I found where Damain explains the rule as basically replicate dimensions,
extend lengths, using an identity value when extending the length.
http://www.mail-archive.com/perl6-language@perl.org/msg08304.html
On Wed, 13 Apr 2005, Thomas Sandlaß wrote:
Brent 'Dax' Royal-Gordon wrote:
IIRC, it's
On Thu, Apr 14, 2005 at 11:08:21AM -0600, John Williams wrote:
: Good point. Another one is: how does the meta_operator determine the
: identity value for user-defined operators?
:
: (1,2,3,4,5) my_infix_op (3,2,4)
:
: Maybe we should say that the excess length is simply copied unchanged.
:
David Christensen [EMAIL PROTECTED] wrote:
Example:
(1,2,3,4,5) + (1,2)
Is this equivalent to:
a) (1,2,3,4,5) + (1,2,undef,undef,undef) (undef padding)
b) (1,2,3,4,5) + (1,2,1,2,1) (repetition)
c) (1,2,3,4,5) + (1,2,2,2,2) (stretching)
d) (1,2) + (1,2) (truncation)
e) something
Brent 'Dax' Royal-Gordon wrote:
IIRC, it's f) (1,2,3,4,5) + (1,2,$identity,$identity,$identity),
where $identity's value is determined by a table something like this:
In the case of infix_circumfix_meta_operator:{'»','«'}:(List,List:op)
there's no upgrade---to use the S03 term. A simple apply op
Hey folks,
I wanted to delurk and address an issue that may need clarification in
regards to hyper operators.
Quoting S03:
If one argument is insufficiently dimensioned, Perl upgrades it:
(3,8,2,9,3,8) - 1; # (2,7,1,8,2,7)
Now in this example case, it's pretty clear that the scalar
