Uri Guttman skribis 2004-05-19 0:08 (-0400):
J 1;0 [EMAIL PROTECTED]:~$ perl -MBenchmark=cmpthese -e'my @foo = (1..16,
J 1..10); cmpthese -1, { a = sub { my %foo; $foo{$_}++ for @foo; }, i
J b = sub { my %foo; $_++ for @[EMAIL PROTECTED]; } }'
J Rate a b
J
I use over and over this idiom in perl5:
$a{$_}++ for @a;
This is nice and perlish but it gets easily pretty boring
when dealing with many list/arrays and counting hashes.
I thought overloading the += operator
%a += @a;
Probably that operator should be smart enough to be fed with
a
On Tue, 18 May 2004, Stéphane Payrard wrote:
I use over and over this idiom in perl5:
$a{$_}++ for @a;
In perl6, using a hash slice and a hyper(increment)operator:
[EMAIL PROTECTED];
JW == John Williams [EMAIL PROTECTED] writes:
JW On Tue, 18 May 2004, Stéphane Payrard wrote:
I use over and over this idiom in perl5:
$a{$_}++ for @a;
JW [EMAIL PROTECTED];
i see dead languages (apl :)
uri
--
Uri Guttman -- [EMAIL PROTECTED]
St?phane Payrard skribis 2004-05-18 23:14 (+0200):
I use over and over this idiom in perl5:
$a{$_}++ for @a;
This is nice and perlish but it gets easily pretty boring
when dealing with many list/arrays and counting hashes.
A3 says something about tr being able to return a histogram (a hash
John Williams skribis 2004-05-18 16:07 (-0600):
$a{$_}++ for @a;
[EMAIL PROTECTED];
That's not a bad idea, even in Perl 5:
1;0 [EMAIL PROTECTED]:~$ perl -MBenchmark=cmpthese -e'my @foo = (1..16,
1..10); cmpthese -1, { a = sub { my %foo; $foo{$_}++ for @foo; }, i
b = sub {
Stphane Payrard writes:
I use over and over this idiom in perl5:
$a{$_}++ for @a;
This is nice and perlish but it gets easily pretty boring
when dealing with many list/arrays and counting hashes.
I thought overloading the += operator
%a += @a;
Though that would like to mean
On Tue, 2004-05-18 at 18:16, Juerd wrote:
St?phane Payrard skribis 2004-05-18 23:14 (+0200):
I use over and over this idiom in perl5:
$a{$_}++ for @a;
This is nice and perlish but it gets easily pretty boring
when dealing with many list/arrays and counting hashes.
I never saw the
-Original Message-
From: Luke Palmer
%a += @a;
Is the operator you want. But, after all that,
++ [EMAIL PROTECTED]
Was probably the best way to do it all along.
Hmm. For junctions I was thinking:
++ all([EMAIL PROTECTED]);
Which is almost readable.
Perl 6
Austin Hastings wrote:
Hmm. For junctions I was thinking:
++ all([EMAIL PROTECTED]);
Which is almost readable.
But unfortunately not correct. Junctions are value, not lvalues.
This situation is exactly what hyperoperators are for:
++ [EMAIL PROTECTED];
Damian
-Original Message-
From: Damian Conway [mailto:[EMAIL PROTECTED]
Sent: Tuesday, 18 May, 2004 08:09 PM
To: [EMAIL PROTECTED]
Subject: Re: idiom for filling a counting hash
Austin Hastings wrote:
Hmm. For junctions I was thinking:
++ all([EMAIL PROTECTED]);
Which
Damian Conway writes:
Austin Hastings wrote:
Hmm. For junctions I was thinking:
++ all([EMAIL PROTECTED]);
Which is almost readable.
But unfortunately not correct. Junctions are value, not lvalues.
This situation is exactly what hyperoperators are for:
++ [EMAIL
On Tue, May 18, 2004 at 06:32:28PM -0600, Luke Palmer wrote:
: Damian Conway writes:
: Austin Hastings wrote:
:
: Hmm. For junctions I was thinking:
:
:++ all([EMAIL PROTECTED]);
:
: Which is almost readable.
:
: But unfortunately not correct. Junctions are value, not lvalues.
:
On Tue, May 18, 2004 at 11:14:30PM +0200, Stéphane Payrard wrote:
I thought overloading the += operator
%a += @a;
There's been lots of discussion of this, but:
Probably that operator should be smart enough to be fed with
a mixed list of array and hashes as well:
%a += ( @a, %h); #
Luke asked:
Er, did the hyper operator's direction flip? I thought it was:
++ [EMAIL PROTECTED];
My bad. 'Tis indeed.
Damian
Austin Hastings asked:
Junctions are value, not lvalues.
Why not bundle lvalues together?
Because, although this would mean what it says:
all($x, $y, $z)++;
None of these would:
any($x, $y, $z)++;
one($x, $y, $z)++;
none($x, $y, $z)++;
We're trying to avoid
J == Juerd [EMAIL PROTECTED] writes:
J John Williams skribis 2004-05-18 16:07 (-0600):
$a{$_}++ for @a;
[EMAIL PROTECTED];
J That's not a bad idea, even in Perl 5:
J 1;0 [EMAIL PROTECTED]:~$ perl -MBenchmark=cmpthese -e'my @foo = (1..16,
J 1..10); cmpthese -1, { a =
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