On Monday 12 September 2011 22:51:54 Reid Thompson wrote:
test=# select distinct on (val1) val1, val2, val3 from (SELECT
max(val3) OVER (PARTITION BY val1), * FROM sampledata) as sq where val3
= max order by val1;
Other things I've tried (was limited to PG8.3 so no OVER (PARTITION...)
Reid,
where any one of these 3
11 2011-01-01
11 2011-01-01
13 2011-01-01
or any one of these 2
31 2011-01-05
32 2011-01-05
are suitable for val = 1, val = 3 respectively.
Can you please describe in words what you are trying to
On Tue, 2011-09-13 at 16:39 +0200, Hannes Erven wrote:
Reid,
where any one of these 3
11 2011-01-01
11 2011-01-01
13 2011-01-01
or any one of these 2
31 2011-01-05
32 2011-01-05
are suitable for val = 1, val = 3
I'm sorry Reid, driving back home I realized that the previous query I
suggested didn't do what I was expecting, cause it would compute all of val2
for each val1, even if they belonged to another group (not for a particular
val1/date pair), or in other words, to another date.
I've considered this
On 9/12/2011 9:54 PM, Reid Thompson wrote:
Ack -- i flubbed the subject and sample.
The sample data should be
val val2date
11 2011-01-01
22 2011-01-02
33 2011-01-03
41 2011-01-04
52 2011-01-05
53 2011-01-01
41 2011-01-02
Ack -- i flubbed the subject and sample.
The sample data should be
val val2date
11 2011-01-01
22 2011-01-02
33 2011-01-03
41 2011-01-04
52 2011-01-05
53 2011-01-01
41 2011-01-02
62 2011-01-03
43
