Hi
If I use $snippet = ; and escape the quotes in the block then it
works. But if I use it as is below, it fails with no useful error
message. Why?
Thanks,
Peter
function GetAddCommentSnippet($args) {
$topic_id = $args[id];
$return_page =
on 2/4/02 11:32 AM, Peter J. Schoenster at [EMAIL PROTECTED] wrote:
Hi
If I use $snippet = ; and escape the quotes in the block then it
works. But if I use it as is below, it fails with no useful error
message. Why?
not sure if this is it or not, but from the manual
On Mon, 2002-02-04 at 10:32, Peter J. Schoenster wrote:
Hi
If I use $snippet = ; and escape the quotes in the block then it
works. But if I use it as is below, it fails with no useful error
message. Why?
Thanks,
Peter
This function cut-and-pasted? If so, then you may have fallen
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