, because of the sprocket holes), but only 31104mm^2 are exposed and use
up the developer.
John
http://www.enteric.org/
- Original Message -
From: Richard M. Koolish kool...@bbn.com
To: pinhole-discussion@p at ???
Sent: Wednesday, April 17, 2002 2:02 PM
Subject: Re: [pinhole-discussion
neither of us are right. 24x36x36 =31,104mm2
8(x2.5)x 10(2.5) = 50,000 mm2
Richard Heather
The film is 35 mm wide not 24 mm, and the frame spacing is
38 mm not 36.
35 x 38 x 36 = 47880
Unexposed area does not use up any developer.
Richard Heather
G.Penate wrote:
- Original Message -
From: Richard Heather rheat...@slonet.org
neither of us are right. 24x36x36 =31,104mm2
8(x2.5)x 10(2.5) = 50,000 mm2
Richard Heather
Richard,
Remember that the
In a message dated 4/15/2002 5:25:34 AM Central Daylight Time,
rheat...@slonet.org writes:
neither of us are right. 24x36x36 =31,104mm2
35 mm film is 35 mm wide not 24 mm, also there is about 200 mm of leader.
Brings the result a lot closer to 8x10.
utu168
- Original Message -
From: Richard Heather rheat...@slonet.org
neither of us are right. 24x36x36 =31,104mm2
8(x2.5)x 10(2.5) = 50,000 mm2
Richard Heather
Richard,
Remember that the actual length of film allows for 36 frames +
leading and trailing portions of film
Richard, I have to correct you; 1 roll of 36 mm x 36 is exactly equal to 1
sheet of 8x 10 - 80 square inches. Check Kodak developer tech bulletins.
Ian McKee
One 8x10 neg has way more surface area than 2 rolls of 135x36. 3 to 4 oz of
dilute developer is a bargain. Nobody does 8x10 for the
