Hi,
I ran a coxph model and in the summary the independent variables are
reported highly significant. However, if I run anova() on that model, some
of the variables are reported to explain basically no deviance and other
variables which are reported insignificant in the model summary are
On Wed, 2007-10-17 at 19:57 -0600, James wrote:
On Oct 17, 2007, at 4:36 PM, James wrote:
On Oct 17, 2007, at 10:18 AM, Waterman, DG ((David)) wrote:
I agree. Avoid the lines like:
iv = c( iv, min(i, j) )
I had code that was sped up by 70 times after fixing the size of my
Hello all lattice experts!
I'm currently trying to plot inset figures in my lattice graphics. The
plot is composed out of two panels and in each panel I want to show an
inset figure which is a closeup of the data in each panel. Thus in each
panel I call xyplot again to plot the inset which I
Hello,
Let me describe what I have and what I want to do:
I have two (7x6) matrices (call them A and B) that have same row and
column names (rows=species, columns=variables) but contain numerical
values that differ (same experiment done twice and values calculated
and put in different matrices).
In mgcv::gam smooths are represented using basis functions. The `k' argument
of `s' specifies the number of basis functions to use. Its default value is
10. If you have fewer than k unique covariate values then the basis can not
be set up. So you need to reduce k to at most the number of
Dear R-helpers
I would like to do a fit of the form: y = a (x+c)**b, where a, b and c
are unknown.
Does anybody know how to do it?
Thanks
Thomas
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PLEASE do read the
Dear useRs,
a new version of the 'relations' package has appeared on CRAN. New
features include:
o support for fuzzy relations added
o support for sets moved to separate 'sets' package
o new SD fitters for the S (symmetric) and M (matches) families
o fitters for Cook-Seiford
On 10/17/07, Ravi Varadhan [EMAIL PROTECTED] wrote:
What if simultaneously maximizing f(x,y) and g(x,y) is an incompatible
objective?
Modifying Duncan's example slightly, What if:
f(x,y) = -(x-y)^2 and
g(x,y) = -(x-2)^2-(y-x-1)^2?
Here:
(1) = x = y
(2) = y = x + 1
(3) =
Sergey Goriatchev wrote:
Hello,
Let me describe what I have and what I want to do:
I have two (7x6) matrices (call them A and B) that have same row and
column names (rows=species, columns=variables) but contain numerical
values that differ (same experiment done twice and values calculated
Hi,
A have small technical question about the calculation of R-squared
using lm().
In a study case with experimental values, it seems more logical to
force the regression line to pass through origin with lm(y ~ x +0).
However, R-squared values are higher in this case than when I
compute
Dear David and Gilles,
Currently, Anova() in the car package doesn't handle lmer objects. I'm
working on a default method for Anova that will work with objects that
respond to coef() and vcov() and produce Wald-like tests. This should
almost work for lmer objects, replacing coef() with fixef(),
On 18/10/2007 7:02 AM, Etienne Toffin wrote:
Hi,
A have small technical question about the calculation of R-squared
using lm().
In a study case with experimental values, it seems more logical to
force the regression line to pass through origin with lm(y ~ x +0).
However, R-squared
On Thu, 18 Oct 2007, Toffin Etienne wrote:
Hi,
A have small technical question about the calculation of R-squared
using lm().
In a study case with experimental values, it seems more logical to
force the regression line to pass through origin with lm(y ~ x +0).
However, R-squared values are
Ist there a possibility to write a R-Script using something like
#!/usr/bin/R
and then alle the requestet commands?
Of course R CMD BATCH exists, but there was (for me) no
possibility to write something like a HERE-script.
regards
erkan
--
über den grenzen muß die freiheit wohl wolkenlos
[erkan yanar]
Ist there a possibility to write a R-Script using something like
#!/usr/bin/R
and then alle the requestet commands?
You could use:
#!/usr/bin/env Rscript
(or if you happen to be sure of the location of the program):
#!/usr/local/bin/Rscript
See ?Rscript for more
Thx
erkan
--
über den grenzen muß die freiheit wohl wolkenlos sein
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and provide commented,
I found a great site with many Perl/tk examples (it's in German):
http://gd.tuwien.ac.at/languages/perl/Hajji-Perlkurs/part4/tkperl.html
It's quite simple to convert these examples to R's tcltk. One
that gave me some trouble was:
# (please open the file to get the context)
# (...)
# a
Dear R-helpers,
I need to insert an R (2.6.0) generated plot containing semi-transparent colors
into PowerPoint (2002). When I directly paste it from the clipboard or insert
it as (enhanced) Metafile (I'm on Windows XP) the semi-transparent colors don't
show. When I insert it at as a Bmp, Png
On 18-Oct-07 11:56:48, erkan yanar wrote:
Ist there a possibility to write a R-Script using something like
#!/usr/bin/R
and then alle the requestet commands?
Of course R CMD BATCH exists, but there was (for me) no
possibility to write something like a HERE-script.
regards
erkan
Hmmm
Just saw this in the Windows Secret blog:
Get official and unofficial fixes for Excel
By Brian Livingston
Despite the hotfix that Microsoft recently released for Excel 2007, as
I described on Oct. 11, some math errors that you should know about
still lurk in both Excel 2007 and Excel 2003.
Juan Lewinger lewinger at usc.edu writes:
Also, 1) for the emf generated image look at the little circles at the
bottom of each boxplot: the fill color
has bled out. Why?
2) From the console menu I cannot save a plot as PDF (no file is saved when
I try)
In re to 2) I didn't mention
I think there is reason to be surprised, I am, too. ...
What am I missing?
Read the formula and ?summary.lm more closely. The denominator,
Sum((y[i]- y*)^2)
is very large if the mean value of y is substantially nonzero and y*
set to 0 as the calculation implies for a forced zero intercept. In
Dear R stat experts,
I am looking for an R function/code that can perform the EM algorithm to
estimate the parameters of a mixture of two negative binomial distributions.
I know that there are functions written that use the EM to estimate a
mixture of normal distributions and also within the
I have tried to print a table of greek alphabet names and symbols
without success. I can print one character at a time but can't seem to
find a way to automate an entire list of the symbols. Some of the code I
have tried is below. I have searched on help, worked the examples in the
December 2002 R
I have the following R code to create a plot with two y axes. I am
essentially trying to
plot a price series with a volume series on the same graph. (i.e. to
compare price with volume). I can label the first
y axis successfully, but the problem is in labeling the 2nd y-axis.
Essentially,
Hi Liviu,
Thank you very much for the response! I knew that would work within
R, but was just wondering why
R CMD INSTALL nlme
does not work on the shell terminal. Any clue?
Thanks,
Gang
On Oct 17, 2007, at 6:27 PM, Liviu Andronic wrote:
On 10/17/07, Gang Chen [EMAIL PROTECTED] wrote:
Please do check the archives: this has been mentioned several times,
including yesterday, with a workaround (and it is fixed in R-patched).
And I presume you meant the *graphics device* menu, not the console menu.
On Thu, 18 Oct 2007, Juan Lewinger wrote:
Juan Lewinger lewinger at usc.edu
Any suggestions?
When generating a bitmap (png is then the best solution) you can
control the resolution with width and height parameters (in
pixels):
png(myimage.png,width=1800,height=1800)
Then you just need to raster yor graph in an adequate resolution (more
pixels means bigger file, of
Prof Brian Ripley ripley at stats.ox.ac.uk writes:
Please do check the archives: this has been mentioned several times,
including yesterday, with a workaround (and it is fixed in R-patched).
And I presume you meant the *graphics device* menu, not the console menu.
Thank you and yes, I
S Ellison, Donnerstag, 18. Oktober 2007:
I think there is reason to be surprised, I am, too. ...
What am I missing?
Read the formula and ?summary.lm more closely. The denominator,
Sum((y[i]- y*)^2)
is very large if the mean value of y is substantially nonzero and y*
set to 0 as the
On 10/18/07, John Theal [EMAIL PROTECTED] wrote:
I have the following R code to create a plot with two y axes. I am
essentially trying to
plot a price series with a volume series on the same graph. (i.e. to
compare price with volume). I can label the first
Why not use a scatterplot? You
Hi all,
I was trying to convert a data frame to a zoo object so I can use some
time series functions like lag(). But it seems then everything became a
factor, so I have to convert it back to numeric to run the correct
regressions. Is there a way to avoid it? Here is an example:
Thomas Hoffmann wrote:
Dear R-helpers
I would like to do a fit of the form: y = a (x+c)**b, where a, b and c
are unknown.
Does anybody know how to do it?
If they did but didn't answer, would it matter?
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
***
XLSolutions Corporation R/Splus Training: November-December, 2007
***
NOVEMBER-DECEMBER: we added 7 new courses to our R/Splus training
webpages
See full
I haven't followed this thread very closely, but it sounds like it may be
related to the somewhat arcane idea of Desirability functions for multiple
responses (mostly in th e experimental design context, as I recall). There
were some papers on this in TECHNOMETRICS a couple of decades ago. The
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/98227.html
Your Rprofile has the setting
options(stringsAsFactors = TRUE)
If you override it globally by using
options(stringsAsFactors = FALSE)
it will give you what you want but observe Gabor's
caveat. I don't know of the other solution re
A zoo variable is a vector or matrix with an index so you can't
mix types (factors and numeric) in a single zoo variable; however,
you can represented the factor numerically:
library(zoo)
set.seed(1)
a - data.frame(
nn = letters[1:4],
dd = as.Date(2007-08-01) + 1:4,
x =
Yes, a scatterplot would be better. But for the sake of interest, is
it possible to
get the label for the secondary y-axis to appear? I have been
playing around with
it all day in an attempt to get it to work and have been
unsuccessful. I would like
to know if it is possible and/or what
Two follow up questions from post regarding bootstrapping contrasts
for a RM ANOVA:
1. Because my data are repeated measures, isn't it true that I want to
shuffle my column heading individually for each subject (row) by
resampling WITHOUT replacement?
2. For my DV (latency) I have 3 columns of
All,
I have been digging around in the help files and found bsamsize in
Hmisc, but I am wondering if i am using it right.
So, here is the question: given a binomial response (success/failure)
for 2 groups (treatment/control) and I want to estimate the necessary
sample size (n) to determine
On Thu, 18 Oct 2007, Ralf Goertz wrote:
S Ellison, Donnerstag, 18. Oktober 2007:
I think there is reason to be surprised, I am, too. ...
What am I missing?
Read the formula and ?summary.lm more closely. The denominator,
Sum((y[i]- y*)^2)
is very large if the mean value of y is
One of the examples here shows two Y axes each with a label:
library(zoo)
example(plot.zoo)
On 10/18/07, John Theal [EMAIL PROTECTED] wrote:
I have the following R code to create a plot with two y axes. I am
essentially trying to
plot a price series with a volume series on the same graph.
Hi,
I am wondering which classification algorithms in R have implemented
class weight for imbalanced data prediction?
Thanks.
--
Weiwei Shi, Ph.D
Research Scientist
GeneGO, Inc.
Did you always know?
No, I did not. But I believed...
---Matrix III
__
You want a symbol, so
for (i in 1:10) text(7, order[i], as.name(greeks[i]))
(or as.symbol) gets you from character string to symbol.
BTW1: please check the code you post: yours doesn't work.
BTW2: the o is omicron: you can see a list of the names at
Hi Sir
How to perform cluster analysis using Ward's method and K- means clustering?
Regards
--
AMINA SHAHZADI
Department of Statistics
GC University Lahore, Pakistan.
[[alternative HTML version deleted]]
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I am trying to compute bootstrap confidence intervals for a sample
using R 2.5.1 for Windows.
I can get Normal, Basic, Percentile, BCa and ABC from
boot.ci() and boot() in the Davison Hinkley boot package.
But I can't figure out how to use tilt.boot() to get
On 10/18/07, amna khan [EMAIL PROTECTED] wrote:
Hi Sir
How to perform cluster analysis using Ward's method and K- means clustering?
For beginning, try to perform it using the GUI Rcmdr.
Regards,
Liviu
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Dear Prof. Ripley,
You are right. I failed to pay attention to the following remark in the
help page:
Note that the storage used by DQRDC and DGEQP3 differs.
Although this does not matter for solving a linear system (i.e. qr.solve()),
the Q and R representations are indeed different.
Thanks
Hi,
I am looking for an algorithm (better if it is implemented in R) which
can do the following:
from the following list:
a,b,c,d
a,b,c
b,c
a,b,c,d,e
to calculate
a,b,c,d: 2
a,b,c: 3
a,b: 3
a,c: 3
b,c: 4
b,c,d:2
here, the order is not important.
Thanks.
--
Weiwei Shi, Ph.D
Research
It would be helpful if you explained what the numbers mean.
On 10/18/07, Weiwei Shi [EMAIL PROTECTED] wrote:
Hi,
I am looking for an algorithm (better if it is implemented in R) which
can do the following:
from the following list:
a,b,c,d
a,b,c
b,c
a,b,c,d,e
to calculate
a,b,c,d: 2
What is 'foo'? It appears that foo does not take 2 arguments:
foo - function(x) x
foo(1,2)
Error in foo(1, 2) : unused argument(s) (2)
On 10/18/07, Aydemir, Zava (FID) [EMAIL PROTECTED] wrote:
Hi
what does this mean when i get above error? When I call function foo(),
specifying
hie
i'm tryimg to generate two survival data using the following code (I know
its ugly ) but it seems to repeat two of the variables can any one tell me
whats the porblem.
n=20
n1=n/2
n2=n/4
a11=1 ;a12=1.4 ;a21=16 ;a22=a12 * a21
t1-array(1,c(n1))
Dear all,
I have a question with respect to counting process formulation of the
coxph(survival) model.
I have two groups of observations for which I have partitioned each
observation into two distinct time intervals, namely, entry day till day 13,
and day 13 till death or censorship day (of
I'm a little confused about what I'm doing wrong using the setSqlTypeInfo
function to modify character size output:
setSqlTypeInfo(MySQL,
+ list(double=double,
+ integer=integer,
+ character=varchar(30),
+
Jim Lemon wrote:
Hi Paul,
It looks like you have a 1548 bar histogram, which means that you
can't even resolve the bars on the standard display, much less
annotate them.
umm yes but I know that I only want to see everything from 0 : 150 so
it's ends up only being 300bar's which I agree is
Here is an approach that will work as long as there are less than 32
unique characters in the strings. It uses logical operations to make
the comparison
library(bitops)
x - scan(textConnection('a,b,c,d
+ a,b,c
+ b,c
+ a,b,c,d,e'), sep='\n', what='')
Read 4 items
x - strsplit(x, ',')
x
[[1]]
The rule is search on any combinations whose size is more than 1, like
ab, ac, abc, ...
The storage can be like b2
b2
[[1]]
[1] a b c d
[[2]]
[1] a b c
[[3]]
[1] b c
[[4]]
[1] a b c d e
On 10/18/07, Nordlund, Dan (DSHS/RDA) [EMAIL PROTECTED] wrote:
-Original Message-
From:
Hi Paul,
Why do you want to do that? Maybe you could publish table along side
your graph if you want people to be able to read the raw numbers.
Hadley
On 10/16/07, H. Paul Benton [EMAIL PROTECTED] wrote:
Dear all,
Just a quick one, hopefully. I have a histogram made from the method
for example,
a,b: 3 which means a and b appear together 3 times in my input list.
On 10/18/07, jim holtman [EMAIL PROTECTED] wrote:
It would be helpful if you explained what the numbers mean.
On 10/18/07, Weiwei Shi [EMAIL PROTECTED] wrote:
Hi,
I am looking for an algorithm (better if
the naive way is to exhausive search, but too bad for large and real situation.
On 10/18/07, Weiwei Shi [EMAIL PROTECTED] wrote:
for example,
a,b: 3 which means a and b appear together 3 times in my input list.
On 10/18/07, jim holtman [EMAIL PROTECTED] wrote:
It would be helpful if you
Dear R People:
I am trying to put Rmpi with R-2.6.0 on an Ubuntu operating system.
When I do the installation, all is well.
But when I go into R and fire up the library, this is what I get:
library(Rmpi)
Error in dyn.load(file, ...) :
unable to load shared library
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