Hi,
I am trying to create a plot with pairs()
using a gplot.hexbin() for each pair.
For pairs I can provide a custom upperPanel function:
pairs(iris[1:4], panel=mypanel)
and mypanel() calls plot.hexbin():
library(hexbin) # Bioconductor
mypanel - function(x, ...){
hb -
The R graphics model is low-level, and the problem is CorelDraw's limited
capabilities (Adobe Illustrator seems to do rather better with postscript
generated by R). The XFig and SVG drivers may produce output that is more
easily editable, but ultimately the problem is that R graphics is done
See findGlobals in the codetools package.
On 10/19/07, Moshe Olshansky [EMAIL PROTECTED] wrote:
Please forgive me if my question is answered in Help
FAQ no. 23481739...
In language like C every variable must be declared
before it can be used.
In VBA, if a variable has not been declared it
2007/10/19, Frede Aakmann Tøgersen [EMAIL PROTECTED]:
If you carefully read the man for boxplot (?boxplot) you can see in the
examples that you can put in a ylim as an argument to the boxplot function:
boxplot(3:5, 2:4,4:6, ylim = c(0, 8))
See also ?bxp.
best regards
Frede
Thank you
Thanks for the quick and nice reply.
I must apologise twice:
1-I should have reported I am using R 2.5.1 on Windows;
2- It was a spelling error on my part (rigth instead of right).
Pedro
At 11:27 2007/10/19, you wrote:
Works for me with current R-2.6.0 (but you haven't told us about
your R
Hi
[EMAIL PROTECTED] napsal dne 19.10.2007 15:58:43:
Sorry if this is already answered somewhere, but I could not find it.
I have two vectors, x,y, of different length, and I want to recycle
the smaller one (whichever one it is) until they have the same
length. I was wondering if there is
John:
I agree: the Docs are not clear on this. VR's MASS (p.84 in the 4th
edition) gives an explanation:
Positions in the plot region may also be specified in absolute **user
coordinates**. Initially user coordinates and relative coordinates
[..relative to the unit square of the enclosing
Thanks Katharine,
for the moment I'm not on a PC on which VisIt is installed, but it should do
the trick.
By the way: to use 2 variables when creating the cdf file:
ncnew - create.ncdf(filename=file.cdf, vars = list(x1,x2))
That was one of the things that was working within the 2 hours ;-).
Bert et al,
A point of clarification. If one reads ?par, one will note [emphasis
added]:
There are several parameters can **only** be set by a call to par():
* ask,
* fig, fin,
* lheight,
* mai, mar, mex, mfcol, mfrow, mfg,
* new,
* oma, omd, omi,
*
Because it does. I should have looked ahead a few chapters in the book
before I asked the question. However, I can't seem to reproduce the values
of the hat matrix given by R for the weighted fit example I gave. Any
suggestions (other than looking ahead a few more chapters)?
Tom
# Hello
# I have a question regarding pairwise calculations of a matrix using a
for-loop.
# Below I have a matrix X with 8 columns. These are genotypic data so
Column1 Column2 is
# a unit, Column3 Column4 is a unit, Column5 Column6 is a unit, and
Coulmn7 8 is a unit.
# I have a loop designed
Thanks for the suggestions. The factor function on the RYEAR column worked
well.
I need to clarify my question about the order of the plot. as.table appears
to be concerned with the order that each panel is plotted. Is that correct?
I'm interested in controlling the order of the elements
A little different solution, but it gives you the matches and the
columns in a more compact form. You can always take the data and use
it to put into your array.
# creation of the data matrix
c1- c(1,4,3,2,4,1,3,2,4,3)
c2- c(2,4,3,4,4,3,4,1,3,2)
c3- c(1,3,2,4,4,3,4,4,2,2)
c4-
Jim Lemon wrote:
Jan M. Wiener wrote:
hello,
I am trying to rescale a matrix according to one column in the matrix.
Imagine having two matrices with 2 columns each:
mat1:
12.1
22.2
3 2.2
4 2.4
5 2.7
6 2.9
mat2:
11.9
22.0
3 2.1
4 2.2
5 2.4
6 3.0
7. 2.8
Jan M. Wiener wrote:
hello,
I am trying to rescale a matrix according to one column in the matrix.
Imagine having two matrices with 2 columns each:
mat1:
12.1
22.2
3 2.2
4 2.4
5 2.7
6 2.9
mat2:
11.9
22.0
3 2.1
4 2.2
5 2.4
6 3.0
7. 2.8
On 10/19/07, Allison Bailey [EMAIL PROTECTED] wrote:
Thanks for the suggestions. The factor function on the RYEAR column worked
well.
I need to clarify my question about the order of the plot. as.table appears
to be concerned with the order that each panel is plotted. Is that correct?
You have this sequence of code in your script:
for (a in seq(1,(ncol(X)-3), by=2)){
for (b in seq(3,(ncol(X)-1), by=2)){
for (i in a){
j - a+1
for (k in b){
l - b+1
The 'for (i in a){' appears to meaningless since 'a' is just a single
value. What did you think this is supposed to do?
Tom La Bone wrote:
I understand that the hat matrix is a function of the predictor variable
alone. So, in the following example why do the values on the diagonal of the
hat matrix change when I go from an unweighted fit to a weighted fit? Is the
function hatvalues giving me something other
# Hello
# I have a question regarding pairwise calculations of a matrix using a
for-loop.
# Below I have a matrix X with 8 columns. These are Genotypic data so
Column1 Column2 is
# a unit, Column3 Column4 is a unit, Column5 Column6 is a unit, and
Coulmn7 8 is a unit.
# I have a loop designed
Virus Folder Summary Digest for [EMAIL PROTECTED] sent on Friday, October 19,
2007
The emails listed below have been placed by MailMarshal in your Virus Folder.
They will be automatically deleted after 7 days.
To view your quarantine mails go to http://mail5.smarthome.com/SpamConsole
From:
I'd like to fit a linear model on a subset of a data frame with given weights.
I am curious how the lm() works when both subset and weights argument
is specified.
Let me give an example: filter is a boolean vector of length the same
as one column of df, my dataframe. What I want is the linear
I wrote: [note to self: I must stop this schizophrenic habit
of replying to self. note to self II: I must also stop making
notes to self]
I am struck here. What magic inchantation is required with tkmenubutton?
(...)
# HERE!!! What is the magic inchantation that I must use here?
#
#
Hi.
A colleague of mine figured out how to get the RMySQL 0.6 package to load
properly in our environment with MySQL 5.0.45. Every time I tried to load
the RMySQL library in R 2.5.1 I was getting an error message:
LoadLibrary failure: Invalid access to memory location.
We did the
On 10/19/07, Allison Bailey [EMAIL PROTECTED] wrote:
I'm just learning to work with R, and am having some difficulty controlling
the output of my dotplot.
The default order of the function dotchart seems to be the largest value on
the bottom and the smallest on the top. I wanted it in the
I have been trying to figure out how Hadley Wickhams
reshape package works and I tried it on what may be
your problem. Here is my example. Does it do
something like what you want?
===
# Test Data
zz - subj cond t1 t2 t3
A1 4 5 7
A2
Below is an example R - netCDF - R for rows of a dataframe that are
numeric vectors --note however that your dataframe includes character
vectors. I can't look into that case at the moment - maybe it's easy to
solve, or maybe you have to do some hashing.
## begin ex.
library(ncdf)
dat -
I'm just learning to work with R, and am having some difficulty controlling the
output of my dotplot.
The default order of the function dotchart seems to be the largest value on the
bottom and the smallest on the top. I wanted it in the opposite order (which
is how my data frame is currently
On Thu, 18 Oct 2007, Moshe Olshansky wrote:
Please forgive me if my question is answered in Help
FAQ no. 23481739...
If it were, we might well not forgive you -- the faq isn't *that* long. But it
isn't.
In VBA one can use a special statement (Option
Explicit) which does not allow using
Dear List,
I have a data frame containing reaction times of participants in some
experiment.
As usual each line is single trial in the experiment. Two factors denote the
conditions in the experiment. Each participant completes different trials for
each condition.
Now, the question:
I want
Peter,
what a quick response!
But unfortunately, yes I tried the ncdf package, I looked at the examples,
but after 2 hours trying and many, many errors, I gave up.
Bart
- Original Message -
From: Peter Dalgaard [EMAIL PROTECTED]
To: Bart Joosen [EMAIL PROTECTED]
Cc: [EMAIL
frequent itemset, yeah.. I did not use that for a while
thanks.
On 10/19/07, Gad Abraham [EMAIL PROTECTED] wrote:
Weiwei Shi wrote:
Hi,
I am looking for an algorithm (better if it is implemented in R) which
can do the following:
from the following list:
a,b,c,d
a,b,c
b,c
Bart Joosen wrote:
Hello,
Is there anyone porting R data to VisIt (http://www.llnl.gov/visit/)?
Altough VisIt accepts 5 dozen of data formats, I can't get my data into VisIt.
I currently ran a simulation which gave me a data frame, which I wanted to
import into VisIt to further explore the
Hello,
I am looking for a way to extract fitted values of a 2-level generalized
linear mixed model using lme4-package.
As it is a Poisson-model, I have to use lmer(.), e.g.:
(y ~ x1 + x2 + (1|PtID), data = mydata, family = poisson, method = ML)
If it was a linear mixed model with normally
I am not sure if this is what you want but to re-direct the results to a
file
see ?sink
good luck
AA.
- Original Message -
From: Ashish Jha [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, October 17, 2007 2:46 AM
Subject: [R] How to save association rules generated by arules
Sorry if this is already answered somewhere, but I could not find it.
I have two vectors, x,y, of different length, and I want to recycle
the smaller one (whichever one it is) until they have the same
length. I was wondering if there is a anything better than something
like:
x-1:3
y-1:10
I'm no expert in R but I think that read.table simply will not start a variable
with a numeric. If you really want
the names to be as listed below you can assign them after import by using :
names(mydata) - c(name, 20_1_TT_Z_e4 20_2_TT_Z_e4)
name is a factor as far as I can see because that is
What you have is a slightly more subtle variant of the following:
library(survival)
data(lung)
mydata - cbind(lung, newvar =2)
coxph(Surv(time, status) ~ ph.karno + newvar, mydata)
coef exp(coef) se(coef) z p
ph.karno -0.0164 0.984 0.00585 -2.81
Maybe I had to write that the original data what I read are
name 20_1_TT_Z_e4 20_2_TT_Z_e4
A1 10222
A2 10321
A3 10720
Thatk you!
Neuer Arkadasch [EMAIL PROTECTED] schrieb:
Hi everyone, I read the following
Hello all
Simple question for the gurus. I'm trying to interactively label curves
on a single plot. The labcurve() function from Hmisc seems like the way
to do this (?). I just can't seem to get it to work. Toy example:
x - 1:10
y1 - x^2
y2 - 2*x
plot(x,y1)
lines(x,y2)
Dear UserRs,
I draw filled contour plot with filled.contour function.
By default, colors of filled.contour is terrain.colors which alters
from green (the lowest level) to white (the highest level).
I want the colors to alter from white (the lowest level) to green
(the highest level).
How
Perhaps:
z - matrix(1:10, nrow=1)
image(z, col=rev(terrain.colors(10)))
On 19/10/2007, Dong-hyun Oh [EMAIL PROTECTED] wrote:
Dear UserRs,
I draw filled contour plot with filled.contour function.
By default, colors of filled.contour is terrain.colors which alters
from green (the lowest
On 19-Oct-07 09:36:52, raymond chiruka wrote:
sorry but how do i accsess r archives
If you mean the archive of postings to the R-help list,
then:
http://stat.ethz.ch/pipermail/r-help/
For a general search through R-related material (including
R-help):
Works for me with current R-2.6.0 (but you haven't told us about your R
version!):
cut(1:5, 1:5)
[1] NA (1,2] (2,3] (3,4] (4,5]
Levels: (1,2] (2,3] (3,4] (4,5]
cut(1:5, 1:5, right=FALSE)
[1] [1,2) [2,3) [3,4) [4,5) NA
Levels: [1,2) [2,3) [3,4) [4,5)
Uwe Ligges
Pedro de Barros wrote:
raymond chiruka wrote:
sorry but how do i accsess r archives
Which archives, R version? Package versions? Mailing list archives
Uwe Ligges
__
[[alternative HTML version deleted]]
Aydemir, Zava (FID) wrote:
Hi
what does this mean when i get above error? When I call function foo(),
specifying parameters a and b as below
a-5
b-6
y - foo(a,b)
Error in foo(a, b) : unused argument(s) (6)
Hi Zava,
As the other Jim noted, it looks like foo() is declared with only
2007/10/19, Frede Aakmann Tøgersen [EMAIL PROTECTED]:
So where is the reproducable example?
How can we know that you're not doing
boxplot(1:10)
abline(h = 400, col = red)?
best regards
Frede
You are right, a reproducable example should have been there.
I don't know what I mistyped
sorry but how do i accsess r archives
__
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting
The Fondation De France(FDF) ( http://www.fdf.org), would
like to notify you that you have been chosen by the Board of Trustees as one of
the final recipients of a Cash Grant/Donation for your Personal, Educational,
and Business Development.
The Fondation De France(FDF) was conceived with the
Dear All,
I am trying to use cut() to produce intervals open on the right, but
it seems to ignore the argument right=F, contrary to what is
indicated on the help for cut.
Can anyone help?
Thanks,
Pedro
__
R-help@r-project.org mailing list
G'day Ralf,
On Fri, 19 Oct 2007 09:51:37 +0200
Ralf Goertz [EMAIL PROTECTED] wrote:
Thanks to Thomas Lumley there is another convincing example. But still
I've got a problem with it:
x-c(2,3,4);y-c(2,3,3)
[...]
That's okay, but neither [...] nor [...]
give the result of
Which marketers have used to hype the internet as a seamless part of everyday
life.
Already achieved universal access thanks to the 6000 UK Online centres that
have.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
So where is the reproducable example?
How can we know that you're not doing
boxplot(1:10)
abline(h = 400, col = red)?
best regards
Frede
Fra: [EMAIL PROTECTED] på vegne af Klaus Friis Østergaard
Sendt: fr 19-10-2007 09:55
Til: Gabor Grothendieck
It works for me. Perhaps you could make the line thicker.
abline(h = 4, col = red, lwd = 3)
On 10/19/07, Klaus Friis Østergaard [EMAIL PROTECTED] wrote:
2007/10/19, Gabor Grothendieck [EMAIL PROTECTED]:
Try this:
boxplot(1:10)
abline(h = 4, col = red)
Have tried it, I only get the
I would like to do a fit of the form: y = a (x+c)**b, where a, b and c
are unknown.
The popular method of fitting a linear model to log-log transformed data was
already mentioned. ALthough this works in many situations, it is
considered to be somewhat biased an not very robust. I suggest to
2007/10/19, Gabor Grothendieck [EMAIL PROTECTED]:
Try this:
boxplot(1:10)
abline(h = 4, col = red)
Have tried it, I only get the boxplot, no red line.
It works on the plotte images.
That is why I asked the question here on the list.
--
Klaus F. Østergaard, farremosen(at)gmail dot com
What exactly are you trying to determine? You can look at the help
page for a function to see what, if any, value is returned.
If you are 'try'ing to catch an error, then the following might help:
x - plot(0)
x
NULL
x - plot()
Error in plot() : argument x is missing, with no default
x
NULL
Hello,
Is there anyone porting R data to VisIt (http://www.llnl.gov/visit/)?
Altough VisIt accepts 5 dozen of data formats, I can't get my data into VisIt.
I currently ran a simulation which gave me a data frame, which I wanted to
import into VisIt to further explore the dataframe.
Let's say I
If you carefully read the man for boxplot (?boxplot) you can see in the
examples that you can put in a ylim as an argument to the boxplot function:
boxplot(3:5, 2:4,4:6, ylim = c(0, 8))
See also ?bxp.
best regards
Frede
Fra: Klaus Friis Østergaard
Hi
[EMAIL PROTECTED] napsal dne 19.10.2007 11:24:23:
2007/10/19, Frede Aakmann Tøgersen [EMAIL PROTECTED]:
So where is the reproducable example?
How can we know that you're not doing
boxplot(1:10)
abline(h = 400, col = red)?
best regards
Frede
You are right, a
Now my Windows machine is back online again, I have been able to do some
work on this.
You can download the latest ODBC drivers from download.microsoft.com
(select Office as the product, search for ODBC and you will get to
AccessDatabaseEngine.exe). You don't need any version of Office
Try this:
boxplot(1:10)
abline(h = 4, col = red)
On 10/18/07, Klaus Friis Østergaard [EMAIL PROTECTED] wrote:
Hi,
Is it possible to add horizontal lines to a boxplot.
I want to add these lines in ordre to indicate where tolerance limits on the
boxplot.
--
Klaus F. Østergaard,
mydata[is.na(mydata)] - NaN
should work
--- Samor Gandhi [EMAIL PROTECTED] wrote:
Hi, Is it possible to do the following
mydata
yx
1 0.3 1
2 0.8 NA
3 NA 0
4 0.2 1
I would like to solve
mydata - replace(mydata, NA, NaN)
Thanks!
See ?make.names, specifically the Details section which notes:
A syntactically valid name consists of letters, numbers and the dot or
underline characters and starts with a letter or the dot not followed by
a number. Names such as .2way are not valid, and neither are the
reserved words.
The
On Fri, 19 Oct 2007, Ralf Goertz wrote:
=
Thanks to Thomas Lumley there is another convincing example. But still
I've got a problem with it:
x-c(2,3,4);y-c(2,3,3)
1-2*var(residuals(lm(y~x+1)))/sum((y-mean(y))^2)
[1] 0.75
That's okay, but neither
64 matches
Mail list logo