Hi
David Winsemius wrote:
C.J.Albers [EMAIL PROTECTED] wrote in
news:[EMAIL PROTECTED]:
Hi all,
(Apologies if this has been asked before; I tried to search for it in
the archives, but searching for terms like 'N' yields too many hits)
Is it possible to display symbols like 'R' (the
C.J.Albers wrote:
Hi all,
(Apologies if this has been asked before; I tried to search for it in the
archives, but searching for terms like 'N' yields too many hits)
Is it possible to display symbols like 'R' (the set of real numbers, so with
an additional vertical line on the left) in
Try something like:
pdf(file=filename.pdf)
plot(...)
dev.off();
works with other formats as well. Type ?Devices
Hope that helps,
John
On Wednesday 21 November 2007 21:45:38 Maura E Monville wrote:
I recently installed R 2.6 on Linux/SuSE
When I was running the previous version on Windows I
Hi
[EMAIL PROTECTED] napsal dne 20.11.2007 09:36:32:
Hi Thanks for the reply.
I implemented your solution to my problem but ...
For some of my column there is not enough data to do t-test so it gives
me
error and stops the for loop, is any graceful way to check for error msg
and
say
I have a numeric vector of lenth 1. I am trying to use it inside
a function just by giving its name, rather than specifying it as
an argument to the function. I am aware that there is an attach
function which you need to call. The attach function will accept a
list. However, I don't seem to be
On Thu, 2007-11-22 at 03:16 -0500, Thomas L Jones, PhD wrote:
I have a numeric vector of lenth 1. I am trying to use it inside
a function just by giving its name, rather than specifying it as
an argument to the function. I am aware that there is an attach
function which you need to call. The
amna khan wrote:
Dear Sir
grDevices package is not found in packages list?
It is a base package that ships with R.
Uwe Ligges
Thank You
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PLEASE do read the
Maura,
The following worked for me. Hope it helps.
I did a plot, the graphics showed up on my screen. Then I did
dev.copy2eps(), the graphics was saved to a file called Rplot.eps.
I tried dev.copy(pdf) or dev.copy(png), but for some reason they generated 0
sized files for me. I didn't figure
Hi Sirs:
This is Ping-Shan Chen from ProMOS Technologies in Taiwan.
I have a installation problem that needs your supports.
Some error messages as follows occured while installing R on Unix server.
Anyone could tell me how to fix this issue?
The OS version is Enterprise Linux AS release 4
Dear R developers
I encountered a slight problem with instalation of new R versions. Up to
2.6.0 allwas OK. R 2.6.1rc and 2.7.0dev do not install due to inability to
write C:\Documents..\PikalP\*.tmp file. I am not sure if it is a change of
some MS instalation routines or if it is a change in
Hello
I can construct a correlation matrix from an (ordered) vector of
correlation coefficients as follows:
x - c(0.1,0.2,0.3,0.4,0.5)
n - length(x)
cmat - diag(rep(0.5,n))
cmat[lower.tri(cmat,diag=0)] - x
cmat - cmat+t(cmat)
But how to do the reverse operation, i.e. produce x from cmat?
Hallo
From a variable x that defines, say, four classes, I would like to define
the matrix mat of dummy variables indicating the classes, i.e.
x - c(1,1,1,1,2,2,2,3,3,3,4,4)
mat - matrix(c(1,0,0,0,
1,0,0,0,
1,0,0,0,
1,0,0,0,
0,1,0,0,
0,1,0,0,
0,1,0,0,
0,0,1,0,
0,0,1,0,
0,0,1,0,
0,0,0,1,
affy snp wrote:
Hi friends,
I used heatmap(as.matrix(y2),col=rainbow(256),scale = column) to
generate the heatmap. But it did not show the code that which
color correspond the value. Is there any parameter for this in
heatmap()?
Hi Allen,
If you want colors corresponding to the values
Hi;
I have a R script that includes a call to genoud(); genoud process lasts
about 4 seconds, what would be OK if I hadn't have to call it about 2000
times. This yields about 2 hours of processing.
And I would like to use this script operationally; so that it should be
run twice a day. It seems to
hi,
is there a way of calculating of measuring dependence between two
categorical variables. i tried using the chi square test to test for
independence but i got error saying that the lengths of the two
vectors don't match. Suppose X and Y are two factors. X has 5 levels
and Y has 7 levels. This
Serguei Kaniovski wrote:
Hello
I can construct a correlation matrix from an (ordered) vector of
correlation coefficients as follows:
x - c(0.1,0.2,0.3,0.4,0.5)
n - length(x)
cmat - diag(rep(0.5,n))
cmat[lower.tri(cmat,diag=0)] - x
cmat - cmat+t(cmat)
But how to do the reverse
Thomas,
I have a numeric vector of lenth 1. I am trying to use it inside
a function just by giving its name, rather than specifying it as
an argument to the function. I am aware that there is an attach
function which you need to call. The attach function will accept a
list. However, I don't
There have been several constructive responses to John Sorkin's
comment, but none of them are fully satisfactory. Of course, if you
know the name of the function you are looking for, there are lots of
ways to search provided that everyone calls the function by a name
that matches your
Hello,
I have a vector, lets say
x - 1:50
I would like it to be cut at certain points, being for example 1:5,
6:11, 12:17, ...
How can I do it? I have tried the cut() function, but I don not know how
to place the cutting points properly.
Best regards,
Dani
--
Daniel Valverde Saubí
Grup de
Hi
you shall be more specific. Do you want to split your vector according
some pionts
split(x, findInterval(x, c(6,12,16)))
if you want to make a factor from your x vector, then you can use
findInterval or cut
cut(x, breaks = c(0,6,12,17, +Inf))
Or something else?
Regards
Petr
[EMAIL
Try Heatmap.2 in the gplots package.
BW,
Marco
-Oorspronkelijk bericht-
Van: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Namens Jim Lemon
Verzonden: donderdag 22 november 2007 11:21
Aan: affy snp
CC: r-help@r-project.org
Onderwerp: Re: [R] Heatmap problem
affy snp wrote:
Hi friends,
Hello,
I have a question about using extreme
value distribution in R.
I have two variables, X and Y, and have pairs
of points (X1,Y1),(X2,Y2), (X3,Y3) etc.
When I plot X against Y, it looks
like the maximum value of Y (for a particular X) is
correlated with X.
Indeed, when I bin the data by
Here is another way of doing it:
x - 1:50
split(x, as.integer(seq(0, by=1, length=length(x))/5))
$`0`
[1] 1 2 3 4 5
$`1`
[1] 6 7 8 9 10
$`2`
[1] 11 12 13 14 15
$`3`
[1] 16 17 18 19 20
$`4`
[1] 21 22 23 24 25
$`5`
[1] 26 27 28 29 30
$`6`
[1] 31 32 33 34 35
$`7`
[1] 36 37 38 39 40
Forget the last message. I hit return before understanding the
question. Its too early on Thanksgiving and I just put the turkey in
the oven. I would have an excuse if I were already sampling the
punch.
On Nov 22, 2007 8:15 AM, jim holtman [EMAIL PROTECTED] wrote:
Here is another way of doing
Thank you Jim Holtman and Mark Leeds for your help.
Original question:
How do I do the following more concisely?
Bout[is.na(Bout$bd.n), 'bd.n'] - 0
Bout[is.na(Bout$ht.n), 'ht.n'] - 0
Bout[is.na(Bout$dbh.n), 'dbh.n'] - 0
. . .
Solution:
for (i in c('bd.n', 'ht.n', 'dbh.n'))
Hi,
I'm new about R. My problem is:
I have 2 lists of proteins and I would compare them. I import the 2
lists like 2 different matrixs and I would that the first entry in the
matrix 1 match with all entries of the matrix 2, then the second entry
of the matrix 1 matchs with all entries of the
Hi Javier
The Rmpi or snow packages might help, e.g., mpi.parLapply; you need to
pay attention to what gets (explicitly or implicitly) shared with
other nodes.
Martin
[EMAIL PROTECTED] writes:
Hi;
I have a R script that includes a call to genoud(); genoud process lasts
about 4 seconds, what
If you want to 'cut' the vector into equal lengths of 4, for example,
then the following would work:
split(x, as.integer((seq_along(x) - 1) / 4))
On Nov 22, 2007 9:44 AM, Dani Valverde [EMAIL PROTECTED] wrote:
Hello,
That's very useful. I think the cut() function is the key. However, in
my
Hello,
That's very useful. I think the cut() function is the key. However, in
my real vector I have 13112 points. I would like the function to cut the
vector every certain number of points (ie 4). Is there a way to specify
this without the need of writing each cutting point? For example, I do
peter360 wrote:
Maura,
The following worked for me. Hope it helps.
I did a plot, the graphics showed up on my screen. Then I did
dev.copy2eps(), the graphics was saved to a file called Rplot.eps.
I tried dev.copy(pdf) or dev.copy(png), but for some reason they generated 0
sized files for
Could you calculate the log values of the two
sections, fit the line, and use lines() to draw them?
--- Joren Heit [EMAIL PROTECTED] wrote:
Hi,
I have processed measurements of a rough surface to
a heigh-height
correlation plot. What the meaning of this exactly
is, is not important.
Can you provide an example of the input data and what you would like
the output to be. When you say first entry is this a single cell,
or the whole row? So an example would help to understand what you are
after.
On Nov 22, 2007 8:45 AM, Marco chiapello [EMAIL PROTECTED] wrote:
Hi,
I'm new
Hi,
I noticed recently when installing the GDD package for R under
GNU/Linux that it required the gd library (http://libgd.org/) for
generating graphics.
The resolution of this was to simply install the library on my system,
and then GDD successfully installed without any complaints.
However,
On Thu, 2007-11-22 at 17:30 +0800, [EMAIL PROTECTED] wrote:
Hi Sirs:
This is Ping-Shan Chen from ProMOS Technologies in Taiwan.
I have a installation problem that needs your supports.
Some error messages as follows occured while installing R on Unix server.
Anyone could tell me how to
The SystemRequirements field on the DESCRIPTION file is used
to document the system requirements. For example, the DESCRIPTION
file for Ryacas (which requires yacas) is shown below.
Package: Ryacas
Version: 0.2-8
Date: 2007-08-22
Title: R interface to the yacas computer algebra system
Author:
Dear usRs,
Is there any conference for usR in US next year?
Happy Turkey day!
wensui
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and
Hi Jim,
The problem with color2D.matplot is that it cannot
do dendrogram which I want.
Thanks!
Allen
On 11/22/07, Jim Lemon [EMAIL PROTECTED] wrote:
affy snp wrote:
Hi friends,
I used heatmap(as.matrix(y2),col=rainbow(256),scale = column) to
generate the heatmap. But it did not
Hi Marco,
Thanks! I actually tried heatmap.2 earlier but I observed
dot line along each column generated as well.
Allen
On 11/22/07, Boks, M.P.M. [EMAIL PROTECTED] wrote:
Try Heatmap.2 in the gplots package.
BW,
Marco
-Oorspronkelijk bericht-
Van: [EMAIL PROTECTED]
On Thu, 2007-11-22 at 11:58 -0500, Wensui Liu wrote:
Dear usRs,
Is there any conference for usR in US next year?
Happy Turkey day!
wensui
R related conferences, at least those officially related to the R
Foundation, are listed here:
http://www.r-project.org/conferences.html
This past
Thank you so much, Marc!
So if I understand correctly, there is no conference related to R in
US in the coming yr2008. Am I correct?
On 11/22/07, Marc Schwartz [EMAIL PROTECTED] wrote:
On Thu, 2007-11-22 at 11:58 -0500, Wensui Liu wrote:
Dear usRs,
Is there any conference for usR in US next
None sponsored by the R Foundation.
There may be others, offered by the various companies who offer R/S-PLUS
training. They do periodically post e-mails about them on these lists.
Regards,
Marc
On Thu, 2007-11-22 at 12:44 -0500, Wensui Liu wrote:
Thank you so much, Marc!
So if I understand
At 09:58 22/11/2007, Serguei Kaniovski wrote:
Hello
I can construct a correlation matrix from an (ordered) vector of
correlation coefficients as follows:
x - c(0.1,0.2,0.3,0.4,0.5)
n - length(x)
cmat - diag(rep(0.5,n))
cmat[lower.tri(cmat,diag=0)] - x
cmat - cmat+t(cmat)
cmat
[,1] [,2]
t(combn(4,2)) in the package *combinat* produce this function.
Xiaohui
Michael Wolf wrote:
Dear all,
Is there a function that computes all binomial combinations.
I am aware of the function choose(n, k) which computes the
number of such combinations, but not the actual combinations
I'm trying to bootstrap some regression coefficients so that I can
estimate confidence intervals, but boot is not producing results. Can
anybody suggest what I'm doing wrong here?
SpecPress - ts(rnorm(501))
Returns - ts(rnorm(501))
BootData - data.frame(cbind(SpecPress, Returns))
Dear all,
Is there a function that computes all binomial combinations.
I am aware of the function choose(n, k) which computes the
number of such combinations, but not the actual combinations
themselves, e.g.:
choose(4, 2)
[1] 6
So I am looking for function that would give me the following
Dear Listers,
Sorry for bothering you on Thxgiving.
I am just curious how to build a saturated model for logistic
regression or other kinds of regression.
Thank you so much!
wensui
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R-help@r-project.org mailing list
I am running Ubuntu 7.10 and R-2.6.0, and I am having trouble updating
packages. There appears to be a problem involving gfortran. For example, here
is the output of an attempt to update the Hmisc package.
* Installing *source* package 'Hmisc' ...
** libs
gfortran -fpic -g -O2 -c cidxcn.f
Hi,
I am trying to run an R program ( linux ) from php to create a graph and
other things for a webpage.
The R program is stored in /tmp and to create a graph I use the png function
i.e.
png(filename = /tmp/trialcsvt8wafB.png, width = 720, height = 480)
But when the userid apache ( which is what
On Wed, 21-Nov-2007 at 01:10PM -0800, Correia, James wrote:
| All-
| I have rhel4 and just installed R2.6.0. The error suggests it cant find the
font library. I have failed to trouble shoot. Can anyone help me?
| Thanks
I'm interested to know about your experience. I use rhel3 and ran
into a
Hi,
I'm trying to figure out how anova works in R by translating the
examples in Sokal And Rohlf's (1995 3rd edition) Biometry. I've hit a
snag with planned comparisons, their box 9.4 and section 9.6. It's a
basic anova design:
treatment - factor(rep(c(control, glucose, fructose,
Dear All,
I'm currently doing a project about unsupervised learning, and I'll be using
R to analyse a few network traffic datasets downloaded off Andrew Moore's
website
(http://www.cl.cam.ac.uk/Research/SRG/netos/nprobe/data/papers/sigmetrics/index.html).
Could anyone shed some light on how to
On 23/11/2007, at 8:36 AM, Wensui Liu wrote:
Dear Listers,
Sorry for bothering you on Thxgiving.
This is a world-wide list, not just a U.S. one. Many of us
are not particularly ``bothered''!
I am just curious how to build a saturated model for logistic
regression or other
Been through the mill on this one ;)
Prof Ripley found a workaround:
http://tolstoy.newcastle.edu.au/R/e2/help/07/05/17402.html
Still haven;t found the right fonts though ;)
-Original Message-
From: [EMAIL PROTECTED] on behalf of Patrick Connolly
Sent: Thu 22/11/2007 7:33 PM
To:
Tyler
For balanced data like this you might find aov() gives an output which
is more comparable to Sokal and Rohlf (which I don't have):
trtCont - C(sugars$treatment, matrix(c(-4,1,1,1,1, 0,-1,3,-1,-1), 5,
2))
sugarsAov - aov(length ~ trtCont, sugars)
summary(sugarsAov,
Antony Unwin [EMAIL PROTECTED] [Thu, Nov 22, 2007 at 12:43:07PM CET]:
There have been several constructive responses to John Sorkin's
comment, but none of them are fully satisfactory. Of course, if you
know the name of the function you are looking for, there are lots of
ways to search ?
Hi all,
I want to invert the y axis of a plot, how can I do that in an easy way?
Thanks in advance,
Juan Pablo
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Hi all
Is there any compiler for R ? By compiler, I mean something that check
the cleanliness of the code : if we declare all the variables we use, if
we don't use external variable from a function and so on...
For exemple, something that will ring a bell on the following code
(saying line 4 :
Lafiesta המסיבה - פורטל האירועים של ישראל
האירוע שלכם מתחיל כאן
www.lafiesta.co.il
תעבירו הלאה __
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Juan Pablo Fededa wrote:
Hi all,
I want to invert the y axis of a plot, how can I do that in an easy way?
Thanks in advance,
Plot x vs. y, then rotate paper 90 degrees clockwise? ;-)
Seriously, switching the endpoint as in ylim=c(ymax,ymin) should do the
trick. Or maybe
On 22/11/2007 5:12 PM, Christophe Genolini wrote:
Hi all
Is there any compiler for R ? By compiler, I mean something that check
the cleanliness of the code : if we declare all the variables we use, if
we don't use external variable from a function and so on...
For exemple, something that
Dear Contributors:
I have the next matrix:
X Y Z
1 2 526
2 5 723
310 110
4 7 1110
5 9 34
6 8 778
7 1 614
8 4 876
9 6 249
10 3 14
I want to order the matrix from bigest Z (1110) to lower Z (14).
Then I
I'm running rle() on a long vector, and get a result which looks like
uc
Run Length Encoding
lengths: int [1:16753] 1 1 1 1 1 1 1 1 1 1 ...
values : int [1:16753] 29462748 22596107 18322820 14323315
12684505 9909036 7296916 6857692 5884755 5883697 ...
I can print uc$names or uc$levels
One way to do this may be to create the right image
and show it. I have never user R for image processing
so I can not provide any details, but I would have
done the following:
Create a 100x100 (or 1000x1000) white image. Then
(assuming that it is a 100x1000 image), for each pair
of your (x,y) you
See the codetools package:
library(codetools)
checkUsage(power)
anonymous: local variable 'p' assigned but may not be used
findGlobals(power)
[1] ^ { - pp return
On Nov 22, 2007 5:12 PM, Christophe Genolini [EMAIL PROTECTED] wrote:
Hi all
Is there any compiler for R ? By
Hi,
When testing whether random variables X and Y are
independent the usual assumption is that you have n
pairs of outcomes - (X1,Y1), (X2,Y2), ... , (Xn,Yn)
and you are basically checking whether the value of X
affects the value of Y.
If you have 7 observations of X and 5 separate
observations
Hi,
I have used the function choose(n, k) sometimes, and i realized that it
doesn't work properly for n 0. For example, if one tries choose(-1, 3), it
should be returned the value (-1)^3 = -1, since choose (-1, 3) =
(-1)*(-2)*(-3)/3! = (-1)^3, but indeed R returns the value 0. I am using
Hi Juan,
Assuming that your data frame is named df, something like the
following should work:
library(ggplot)
qplot(X, Y, data = df, colour = Z, label = Z, geom = text) +
scale_colour_continuous(low=orange, high = blue)
You can find out more about ggplot2 at http://had.co.nz/ggplot2.
Hadley
On 22/11/2007 8:11 PM, Benilton Carvalho wrote:
well,
choose(n, k) should actually return:
factorial(n)/(factorial(n-k)*factorial(k))
That's not how the docs define it. They say
Note that 'choose(n,k)' is defined for all
real numbers n and integer k. For k = 1 as n(n-1)...(n-k+1)
I have a numeric vector of length 1. I am trying to use it inside
a function just by giving its name, rather than specifying it as
an argument to the function. I am aware that there is an attach
function which you need to call. The attach function will accept a
list. However, I don't seem to be
Not the most efficient way would be to use a loop
If x is your rel object, you can do the following:
for (i in 1:length(x$values))
{
cat((,x$values[i],,,x$lengths[i],) )
if (i %% 10 == 0) cat(\n)
}
cat(\n)
--- Alexy Khrabrov [EMAIL PROTECTED] wrote:
I'm running rle() on a long vector,
Hi, I'm trying to install the R language interpreter on a shared
webhost, OpenSolaris platform.
The installing is going fine except that the compiler runs into
forking limits.
g77: fork: Resource temporarily unavailable
Is there a way to keeping the compiler from forking too much? Or does
well,
choose(n, k) should actually return:
factorial(n)/(factorial(n-k)*factorial(k))
R-2.6.0 works just fine for me so does R-2.5.1 so does
R-2.4.1
b
On Nov 22, 2007, at 8:04 PM, Luis Salasar wrote:
Hi,
I have used the function choose(n, k) sometimes, and i realized
Is this what you want?
i - 3
f - function() get(i, parent.frame())
f() # 3
On Nov 22, 2007 10:38 PM, Thomas L Jones, PhD [EMAIL PROTECTED] wrote:
I have a numeric vector of length 1. I am trying to use it inside
a function just by giving its name, rather than specifying it as
an argument to
On Thu, 22-Nov-2007 at 08:50PM -, michael watson (IAH-C) wrote:
| Been through the mill on this one ;)
|
| Prof Ripley found a workaround:
|
| http://tolstoy.newcastle.edu.au/R/e2/help/07/05/17402.html
That's a different mill. :-(
My locale is en-NZ which I thought would have not had that
Thanks for the clarifcation, Duncan.
Best,
B
On Nov 22, 2007, at 8:32 PM, Duncan Murdoch [EMAIL PROTECTED]
wrote:
On 22/11/2007 8:11 PM, Benilton Carvalho wrote:
well,
choose(n, k) should actually return:
factorial(n)/(factorial(n-k)*factorial(k))
That's not how the docs define it.
Apropos this issue, the R Foundation has had an offer to host useR 2009
from a European based group rather than a North American based one. My
understanding is that no decision has yet been taken, though. If other
groups had an interest in hosting useR 2009, it might not be a bad idea
to
On 22/11/2007 8:04 PM, Luis Salasar wrote:
Hi,
I have used the function choose(n, k) sometimes, and i realized that it
doesn't work properly for n 0. For example, if one tries choose(-1, 3), it
should be returned the value (-1)^3 = -1, since choose (-1, 3) =
(-1)*(-2)*(-3)/3! =
Or even
print(paste((,y$values,,,y$lengths,)
,sep=),quote=FALSE)
--- Gabor Grothendieck [EMAIL PROTECTED]
wrote:
Try this:
x - c(a, a, b, b, b) # test input
with(rle(x), paste(values, lengths))
[1] a 2 b 3
On Nov 22, 2007 7:32 PM, Alexy Khrabrov
[EMAIL PROTECTED] wrote:
I'm
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