Hi,
I am using aggregate() to add up groups of data according to year and month.
It seems that the function aggregate() automatically sorts the levels of
factors of the grouping elements, even if the order of the levels of factors
is supplied. I am wondering if this is a bug, or if I missed
Hello the list,
I am trying to write a cleanProgramming function to test the
procedure I use. For example, I want to be sure that I am not using
globals variables. The function findGlobals detect that.
To list the globals used in function fun, the syntax is :
findGlobals(fun,FALSE)$variable
Its a FAQ
http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-can-I-turn-a-string-into-a-variable_003f
On Dec 16, 2007 9:25 AM, [EMAIL PROTECTED] wrote:
Hello the list,
I am trying to write a cleanProgramming function to test the
procedure I use. For example, I want to be sure that I am not
On 16/12/2007 9:25 AM, [EMAIL PROTECTED] wrote:
Hello the list,
I am trying to write a cleanProgramming function to test the
procedure I use. For example, I want to be sure that I am not using
globals variables. The function findGlobals detect that.
To list the globals used in function
This does look strange. Note that aggregate.zoo in the zoo package
would work here:
library(zoo)
aggregate(zoo(rnum, dts), as.yearmon, sum)
Jan 2001Feb 2001Mar 2001Apr 2001May 2001Jun 2001
4.43610085 0.49842227 7.52139932 1.47917343 10.64459923 -1.22530586
Jul
In fact, even ordinary aggegate works ok with zoo's as.yearmon:
aggregate(rnum, list(dts = as.yearmon(dts)), sum)
dts x
1 Jan 2001 4.43610085
2 Feb 2001 0.49842227
3 Mar 2001 7.52139932
4 Apr 2001 1.47917343
5 May 2001 10.64459923
6 Jun 2001 -1.22530586
7 Jul 2001
Hi,
I am constructing a contingency table using xtabs. The function works great:
mo
yr Sep Oct Nov Dec
1950 -7.164486e-02 3.152674e-02 -1.283389e-02 1.570382e-01
1951 3.054293e-02 4.665234e-02 -2.445499e-04 8.720204e-02
1952
Dear everybody!
Please find attached a tiny R-program. It returns:
[,1] [,2]
[1,] 53.55 NA
[2,] 53.55 NA
[3,] 53.55 NA
How can I manage the first column to show the second component not only
of the first list in küste but of the second component of every list in
küste respectively,
Is this what you want as output:
do.call('rbind', kaste)
[,1] [,2] [,3]
[1,] Bremerhaven 53.55 8.58
[2,] Cuxhaven53.87 8.7
[3,] Lübeck 53.87 10.69
On Dec 16, 2007 8:54 AM, Mag. Ferri Leberl [EMAIL PROTECTED] wrote:
Dear everybody!
Please find attached a tiny
Dear All,
It there a way of I read my data tab-separated on the own script, without read
from a external file and without type the data?
I would like something like
mydata- read.data(head=T, sep=\t)
freqesperado
117.5
147.5
47.5
17.5
##END OF DATA
Many thanks, miltinho
para
Try:
print(x, digits = 3)
On Dec 15, 2007 9:22 PM, tom soyer [EMAIL PROTECTED] wrote:
Hi,
I am constructing a contingency table using xtabs. The function works great:
mo
yr Sep Oct Nov Dec
1950 -7.164486e-02 3.152674e-02 -1.283389e-02
Thank you for the attempt.
On your advice I am working with lists to avoid the numbers (which are
geographical coordinates) becoming strings. The call you suggest does
not take care of that. Now I am trying to extract the coordinates from
the list efficiently. Of course I could make a loop, e.g.
You can use the following to get the data from that call:
x - do.call('rbind', kaste)
as.matrix(x[,2:3])
[,1] [,2]
[1,] 53.55 8.58
[2,] 53.87 8.7
[3,] 53.87 10.69
On Dec 16, 2007 10:54 AM, Mag. Ferri Leberl [EMAIL PROTECTED] wrote:
Thank you for the attempt.
On your advice I am
Ugly brute-force approach: col=1:16 . Jim Lemon's
approach with Plotrix is much nicer. You might also
want to have a look at RColorBrewer though I am not
sure how easily it can handle 16 different colours.
barplot(dft, beside = TRUE, main= Risk score by
assessment, xlab = Score, ylab =
On 12/16/07, Bob Green [EMAIL PROTECTED] wrote:
Hello,
Below is the code for a basic bar graph. I was seeking advice
regarding the following:
(a) For each time period there are values from 16 people. How I can
change the colour value so that each person has a different colour,
which
Milton Cezar Ribeiro milton_ruser at yahoo.com.br writes:
I would like to test if are there some significant orientation of frequencies
on a polar analysis.
Check packages CircStats and circular.
Dieter
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R-help@r-project.org mailing list
On 15 Dec 2007, you wrote in gmane.comp.lang.r.general:
If we can assume that the abstract is always the 4th paragraph then we
can try something like this:
library(XML)
doc -
xmlTreeParse(http://eutils.ncbi.nlm.nih.gov/entrez/eutils/erss.cgi?rss
Dear all,
Some very wise data entry person gave me about an hour of a headache, trying
to find out why a 2000x500 dataframe won't be read into R.
After much trial and error, I pinpointed the problem to an accidentally
inserted double quote into a string variable (some comments from an open
On Sunday 16 December 2007, Adrian Dusa wrote:
Dear all,
[...]
Given these examples, I have two questions:
1. What is the correct syntax to import the R-exported file
2. What can I do to prevent these situations from happening?
(besides whipping the data entry person :), I am referring to
On Dec 16, 2007 2:53 PM, David Winsemius [EMAIL PROTECTED] wrote:
# in the debugging phase I needed to set useInternalNodes = TRUE to see the
tags. Never did find a way to print them when internal.
I assume you mean FALSE. See:
?saveXML
__
Thanks Jim. I was using R 2.4.0, that must be the problem. After I upgraded
to 2.6.1, aggregate() generated the correct order of levels. Thanks!
On 12/16/07, jim holtman [EMAIL PROTECTED] wrote:
What version of R are you using? Here is the output I got with 2.6.1:
library(chron)
You can easily install ubuntu on it (although it might require
an external drive):
http://hup.hu/node/48116
So running R should not be problem.
G.
On Sun, Dec 16, 2007 at 12:56:39PM -0500, Burton Rothberg wrote:
I'm thinking of getting one of these lightweight linux laptops for
traveling. Does
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Hash: SHA1
David Winsemius wrote:
On 15 Dec 2007, you wrote in gmane.comp.lang.r.general:
If we can assume that the abstract is always the 4th paragraph then we
can try something like this:
library(XML)
doc -
ravi wrote:
I have the following code, where we need to solve for mu and sigma, when
we have mut and sdt. Can you suggest how to use a solve function in R to
do that? I am new to R and am not sure how to go from defining the
functions, to solving for them.
Thanks
truncated -
You can using the default Linux (Xandros, Debian Based) and enable
Debian Etch Repo in eeepc to install R via apt-get.
http://lnxg.ca/?Hardware:Asus_Eeepc_701:EeePC_Tips
I can install R, LaTeX.
Regards,
C
On Dec 17, 2007 4:37 AM, Gabor Csardi [EMAIL PROTECTED] wrote:
You can easily install
RSiteSearch(AUC)
would lead you to
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/46416.html
On Dec 13, 2007 12:38 PM, Armin Goralczyk [EMAIL PROTECTED] wrote:
Hello
Is there an easy way, i.e. a function in a package, to calculate the
area under the curve (AUC) for drug serum levels?
it's a package , not a library, please!
Sorry for using library instead package, but
library() is one command for using packages.
Therefore I (and it seems that i am not the only one) used library instead
package.
Knut
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