Alex Baugh wrote:
Hi Folks,
I have repeated measures for data on association time (under 2
acoustic condtions) in male and female frogs as they grow to adulthood
(6 timepoints). Thus, two within-subject variables (Acoustic
Condition: 2 levels, Timepoint: 6 levels) and one between-subject
Does your res.dat only have one row and you want this to one variable?
For read.table each new case has to start on a new line.
If your data are in a just one row for a variable format,
res - scan(C:/Documents and Settings/db/Desktop/res.dat)
will probably do what you want.
Debasish Roy wrote:
Here I am in a simulation study where I want to find different values
of x and y such that f(x,y)=c (some known constant) w.r.t. x, y 0,
y=x and x=c1 (another known constant). Can anyone please tell me how
to do it efficiently in R. One way I thought that I will draw
different random numbers from
I want to fit a nonlinear model of the form:
Y=A+B*X1+C*X2+log(X3/(X3+D))
I think that the best way is to use the plinear algorithm, but I don't
know how to specify the formula in the nls function.
I've tried:
Y~cbind(rep(1,times=length(Y)),X1,X2,log(X3/(X3+D)))
But this fits the model:
Are the pairs (x,y) belong to some lattice or can
change continuously?
Does f assume some discrete values (or is constant on
sets of positive measure)? If not then it will be hard
to randomly select x and y which satisfy the exact
equality (this still can happen since there are
finitely many
x, y are cont. variable, and f also have to be cont.. And your second
suggestion is correct of course, it actually should be |f(x,y) - c|
epsilon
Thanks
On Tue, Apr 29, 2008 at 12:34 PM, Moshe Olshansky [EMAIL PROTECTED] wrote:
Are the pairs (x,y) belong to some lattice or can
change
Hi everybody,
I am trying to make my mind about the use of R for Computational and
Statistical Approaches to Genomics.
I know this is a vaste field: this is the main reason why I am sending
this message to this always useful list! Any key/entry point to this
field will be extremely welcome!
To all those who helped with this problem (Ted, Jon, Marc and Prof. Ripley).
When I submitted the postscript files to the journal, I had given them the
extension .ps even though they were (of course) encapsulated postscript. I
decided to simply rename the files with the .eps extension and
That's a nice set of line types! I'll use these now.
I thought because there are so many sophisticated
color schemes there might be some line style schemes
as well.
Thanks for your help Jim and Richard,
Werner
--- Richard Pearson
[EMAIL PROTECTED] schrieb:
I've used the following to get a
Hello,
On 4/29/08, [Ricardo Rodriguez] Your XEN ICT Team [EMAIL PROTECTED] wrote:
I am trying to make my mind about the use of R for Computational and
Statistical Approaches to Genomics.
[..]
Please, could you help me to go in the right direction?
I am not sure what pointers you are
It's not really homework :)
It's just an a little extra I want to explore.
I allready compared the empirical null distribution and the theoritical null
distribution by comparing their quantiles. The results are clear... But I
just wondered if there isn't any way to make a graph of it...so you
Hello,
I'm french and I have some difficulties in carry out the semiones under R
with an aim to carry out an interpolation by krigeage. My goal is to obtain
a chart of the distribution of precipitations/temperatures in Europe
starting from 73 different stations (and, of course, distributed
Hello all
I am a newbie to R plotting maps. I am trying to plot over a world map a
layer of Biogeochemical provinces (BGCP) by A.R. Longhurst. Each ocean
region unfortunately are quite irregular in shape (not perfect squares). In
GIS this layer of ocean provinces would be a layer of polygons,
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__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read
I am a new R user, and not very good at statistics and maths
I find it difficult to find the minimum of this item:
((p*(b-1)-1)*(p+1)^(b-1)+1)/p^2
It seems that the method optim can find the minimum. I tried several
times , but R constanly tells that failure to find b or
Nicolas,
I think you better have a look at the gstat package.
install.packages(gstat)
library(gstat)
example(gstat)
?variogram
?krige
HTH,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek /
Em Seg 28 Abr 2008, Dumblauskas, Jerry escreveu:
Thx
I verified by typing in plot(1,1) at the R prompt -- sure enough an X
window popped up on my desktop.
Off to investigate Linux GUI front ends!
Thx again
Hi,
at this moment the best IDE to use R on Linux in my opinion are in sequence:
I'd also suggest you check out http://www.bioconductor.org - Bioconductor is an
open source and open development software project for the analysis and comprehension of
genomic data
Richard.
Liviu Andronic wrote:
Hello,
On 4/29/08, [Ricardo Rodriguez] Your XEN ICT Team [EMAIL PROTECTED]
I'm not sure what you are trying to do with R, but maybe you should take a
look at the Task Views and see if there is something you can use at your
field of work:
http://www.stats.bris.ac.uk/R/web/views/
Bart
Ricardo Rodríguez wrote:
Hi everybody,
I am trying to make my mind about the
*Hello all
**
I am a newbie to R plotting maps. I am trying to plot over a world map a
layer of Biogeochemical provinces (BGCP) by A.R. Longhurst. Each ocean
region unfortunately are quite irregular in shape (not perfect squares). In
GIS this layer of ocean provinces would be a layer of polygons,
On Sun, 27-Apr-2008 at 10:52AM -0700, [EMAIL PROTECTED] wrote:
| I am trying to install the rpm for R
| I using Red Hat 4 ES on a 64bit machine
| Kernel version is 2,6,9-67
| This is the error i get
| Failed Dependencies libg2c.so () ()(64bit) is needed by
| R-2.6.2-1.rh4.x86_64rpm
| I have
Dear R-help community,
I have searched through the archives and not been able ot find any advice
on how to plot a wind field with one arrow per grid square with the arrow
pointing in the direction of the wind and it's size proportional to the
wind strength.
I have the wind speed data in
Maria Jose Juan Jorda mjuanjorda at gmail.com writes:
Hello all
I am a newbie to R plotting maps. I am trying to plot over a world map a
layer of Biogeochemical provinces (BGCP) by A.R. Longhurst. Each ocean
region unfortunately are quite irregular in shape (not perfect squares). In
GIS
Thank you so much. All the answers lead me to BioConductor and Task
Views. Currently, I've not a precise task to solve, but I do need to
draw a landscape about this topic. Your messages have helped a lot.
I don't know why, but I don't reach BioConductor website by googling or
searchmashing.
On 28/04/2008 9:47 PM, Debasish Roy wrote:
I tried to read a dataset and then draw a histogram with a freqeuncy density curve fitted on the top of this.
I used the command
res - read.table(C:/Documents and Settings/db/Desktop/res.dat)
and found
res[1:5]
V1 V2 V3 V4
On 29/04/2008 4:13 AM, mad_bassie wrote:
It's not really homework :)
It's just an a little extra I want to explore.
I allready compared the empirical null distribution and the theoritical null
distribution by comparing their quantiles. The results are clear... But I
just wondered if there isn't
Dear Frank and rest of list, please accept my apologies for not giving
full details of my analysis in my previous email. I have been working
on this problem and I think my error comes from the class of my
variables and the way I defined the model, and I seemed to be able to
solve it...
Jenny Barnes wrote:
Dear R-help community,
I have searched through the archives and not been able ot find any
advice on how to plot a wind field with one arrow per grid square with
the arrow pointing in the direction of the wind and it's size
proportional to the wind strength.
I have the
Classification: UNCLASSIFIED
Caveats: NONE
Dear R users,
I could not open R2.4.1 this morning with error messages Error in loadName
space (name): There is no package called 'nlme' and Fatal error: unable to
restore saved data in .Rdata under the information box. It had been working
fine until
Hi Jim,
I would like to plot something like figure 2 on this webpage:
http://www.cnrfc.noaa.gov/storm_summaries/jan1997storms.php
My data is very large - covering the whole globe at 2.5deg resolution so
longitude=144 girds, latitude=73 grids and time=32 years - hard to give
you that
Jenny,
Have a look at the R Newsletter Volume 3/2, October 2003
Regards,
Sean
Jenny Barnes wrote:
Dear R-help community,
I have searched through the archives and not been able ot find any advice
on how to plot a wind field with one arrow per grid square with the arrow
pointing in
Thanks for your help, It is definitely that it is needed to me in finale, I
therefore did not use the package check. I am going to try to understand
step how is that now.
Still thanks for your help!
--
View this message in context:
Hi list,
When exporting to PDF a graph with a legend, in the final PDF, the text
is going beyond the legend box.
dev2bitmap(test.pdf, type=pdfwrite, h=6, w=6)
The legend looks OK on the screen.
I noticed that the size of the legend box depends on the size of the
screen window, which is not
An undergraduate here, so do not hesitate to let me know if you feel that
I'm heading in a wrong direction.
I have a data frame containing panel data across 10 years (hence 120
months). I want to be able to run regression separately for each month (or
year). The below shows how I ran the
Bonjour,
Je travail sur R pour la modélisation des copules et j'ai utilisé le package
fCopulae. Le problème est que j'ai pas les noms des copules utilisées:j'ai
utilisé la list de 1 jusqu'au 22 et j'ai réussi à avoir les paramètres.
S'il vous plaît, je demande votre aide là dessus.
Dans
When exporting to PDF a graph with a legend, in the final PDF, the
text is going beyond the legend box.
dev2bitmap(test.pdf, type=pdfwrite, h=6, w=6)
The legend looks OK on the screen. I noticed that the size of the
legend box depends on the size of the screen window,
As far as I
Chris Walker wrote:
To all those who helped with this problem (Ted, Jon, Marc and Prof. Ripley).
When I submitted the postscript files to the journal, I had given them the
extension .ps even though they were (of course) encapsulated postscript. I
decided to simply rename the files with the .eps
I'm using F-distributions :)
I allready found some things...I could plot the qqplot as you say and that
gives me clear results.
Allthough I still want a clear graphic and I 'll explain it as good as I
can...
I plotted 2 graphics
plot(density(rf(1,2,49)))
plot(density(disttest))
Copying between devices (as in dev2bitmap) is not a good way to produce
high-quality graphs, and especially not if you change the size.
What is wrong with
pdf(test.pdf, width=6, height=6)
re-run the plot commands
dev.off()
?
On Tue, 29 Apr 2008, Julien Roux wrote:
Hi list,
When
Check out:
http://addictedtor.free.fr/graphiques/RGraphGallery.php?graph=80
and
RSiteSearch(quiver)
On Tue, Apr 29, 2008 at 6:08 AM, Jenny Barnes [EMAIL PROTECTED] wrote:
Dear R-help community,
I have searched through the archives and not been able ot find any advice on
how to plot a wind
Hello R-user!
I am running R 2.7.0 on a Power Book (Tiger). (I am still R and
statistics beginner)
I try to find the most important variables to divide my dataset as
given in a categorical variable.
code:
Test.rf4-randomForest(Sex~.,na.action=na.roughfix, data=Subset4,
This is an example of two months of data from a twenty four month data set
that I would like to apply this too. These data are subsets of the same
stations throught time, but differing ones were included on different
sampling dates. I would like to subset these data and then put them
together as
Hello R-help,
I need to compute matrices of first derivatives of a covariance matrix C
with entries given by c_ij=theta*exp(-0.5* sum(eta*(x[i,]-x[j,])^2)), wrt to
elements of eta, a m-dimensional vector of parameters, given a n*m data
matrix x. So far, I have been computing matrices for each
On 29/04/2008 8:09 AM, mad_bassie wrote:
I'm using F-distributions :)
I allready found some things...I could plot the qqplot as you say and that
gives me clear results.
Allthough I still want a clear graphic and I 'll explain it as good as I
can...
I plotted 2 graphics
Thanks Jim - here is some data:
u - array(NA,c(5,8))
t - seq(from=0.5, to=0.11,length=15)
t2 - seq(from=(-0.7),to=(-0.1),length=25)
u[1:15] - t
u[16:40] - t2
v - array(NA,c(5,8))
y - seq(from=(-0.9), to=(-0.01),length=40)
v[1:40] - y
I've made up the data but it's similar magnitude and the
Hi Jim,
I forgot to say that I don't want to create curved arrows, just straight -
and I would like them to be proportional to the magnitude :o)
Thanks again for your time!
Jenny
On Tue, 29 Apr 2008, Jenny Barnes wrote:
Hi Jim,
I would like to plot something like figure 2 on this
I need to use R to model a large number of experiments (say, 1000). Each
experiment involves the random selection of 5 numbers (without replacement)
from a pool of numbers ranging between 1 and 30.
What I need to know is what *proportion* of those experiments contains two
or more numbers that
I have tried predict(coxout, newdata), it still gave me the fitted values
only.
Can anyone hlep me on how to do prediction for coxph? thank you very much!
I would suggest first reading the manual page
help(predict.coxph)
There are several things one can predict from a Cox model. You
On 29-Apr-08 12:09:39, Marc Schwartz wrote:
Chris Walker wrote:
To all those who helped with this problem (Ted, Jon, Marc and
Prof. Ripley).
When I submitted the postscript files to the journal, I had
given them the extension .ps even though they were (of course)
encapsulated postscript. I
Anthony28 wrote:
I need to use R to model a large number of experiments (say, 1000). Each
experiment involves the random selection of 5 numbers (without replacement)
from a pool of numbers ranging between 1 and 30.
What I need to know is what *proportion* of those experiments contains two
or
At 02:40 AM 4/29/2008, Arun Kumar Saha wrote:
Here I am in a simulation study where I want to find different values
of x and y such that f(x,y)=c (some known constant) w.r.t. x, y 0,
y=x and x=c1 (another known constant). Can anyone please tell me how
to do it efficiently in R. One way I thought
On Tue, Apr 29, 2008 at 01:49:01PM +0200, Philipp Pagel wrote:
When exporting to PDF a graph with a legend, in the final PDF, the
text is going beyond the legend box.
dev2bitmap(test.pdf, type=pdfwrite, h=6, w=6)
The legend looks OK on the screen. I noticed that the size of the
How about this
result - numeric(10)
for(i in 1:10){
x - sample(1:30, 5, replace = FALSE)
x - sort(x)
result[i] - any(diff(x) == 1)
}
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Anthony28
Sent: Tuesday, April 29, 2008 8:52 AM
To:
Hi,
I would like to use a weighted lm model to reduce heteroscendasticity. I am
wondering if the only way to generate the weights in R is through the
laborious process of trial and error by hand. Does anyone know if R has a
function that would automatically generate the weights need for lm?
Dear R-users,
I have problems specifying a model with nested random terms. I want to
reproduce a variance component model made in Mintab, the model
specification in Minitab is:
Response = Prod P Prod*P Sample(Prod P) Extract(Prod P Sample)
Random Prod Sample Extract
The dataset is
posted mailed
Johannes Graumann wrote:
Vioplots have great appeal to me, as they manage to squeeze so much
information into so little space ...
Now some evaluation has made me suspicious about the implementation in the
package vioplot and I would like to hear what you say about the appended
Is there any function to write a XML structure, after it was
read using xmlTreeParse?
Ex:
library(XML)
x - xmlTreeParse(Irpf2008/aplicacao/dados/12345678901/12345678901.xml)
# write it...
Alberto Monteiro
PS: please, brazilians, don't be offended by my foul language!
Hi list,
I created a function to plot my data:
plot_function(vector)
I want to write the name of the argument vector in the legend/title of
the plot.
For example if I call:
plot_function(my_vector)
I want my_vector to be written in the legend or title and so retrieve
the name of this object
You forgot to mention your version of R and your platform (and R has at
least 3 separate png() devices).
In 2.7.0, specify the size in inches and increase the resolution.
In earlier versions, try bitmap(). From NEWS for 2.7.0
o Considerable efforts have been made to make the default
By write, do you mean print?
In that case using the basic.xml file that comes with the XML package:
library(XML)
basic.xml - system.file(exampleData, basic.xml, package = XML)
# try this
con - xmlTreeParse(basic.xml)
root - xmlRoot(con)
root
# or if you are using internal nodes:
con -
Alberto Monteiro wrote on 04/29/2008 08:37 AM:
Is there any function to write a XML structure, after it was
read using xmlTreeParse?
Ex:
library(XML)
x - xmlTreeParse(Irpf2008/aplicacao/dados/12345678901/12345678901.xml)
# write it...
Calling:
library(help=XML) # or
help(package=XML)
s.d - structure(list(RiverMile = c(202L, 198L, 190L, 185L, 179L, 148L,
119L, 61L)), .Names = RiverMile, row.names = c(NA, -8L), class =
data.frame)
#s.d is all of the river miles that can occur in all of the data frames that
I want to put together
feb06 - structure(list(RiverMile = c(202L, 190L,
Gabor Grothendieck wrote:
By write, do you mean print?
No, I mean save to a file.
I solved the problem with this:
library(XML)
x - xmlTreeParse(Irpf2008/aplicacao/dados/12345678901/12345678901.xml)
sink(ihatetheirs.xls)
print(x)
sink()
and then I can edit the saved file to cut some extra
On Tue, Apr 29, 2008 at 10:20 AM, Alberto Monteiro
[EMAIL PROTECTED] wrote:
Gabor Grothendieck wrote:
By write, do you mean print?
No, I mean save to a file.
I solved the problem with this:
library(XML)
x - xmlTreeParse(Irpf2008/aplicacao/dados/12345678901/12345678901.xml)
If you are using the latest version (4.5-25), you will see in rfNews() that
that's the problem I need to fix. The package was able to handle ordered
factors, but some more stringent checks for factor levels consistency
introduced in 4.5-23 broke the support for ordered factors in prediction.
On 29/04/2008 9:53 AM, Julien Roux wrote:
Hi list,
I created a function to plot my data:
plot_function(vector)
I want to write the name of the argument vector in the legend/title of
the plot.
For example if I call:
plot_function(my_vector)
I want my_vector to be written in the legend or
merge can only merge two objects at a time- I would like to merge more than
two objects at a time.
s.d - structure(list(RiverMile = c(202L, 198L, 190L, 185L, 179L, 148L,
119L, 61L)), .Names = RiverMile, row.names = c(NA, -8L), class =
data.frame)
#s.d is all of the river miles that can occur in
Hello Andy,
thanks for your answer and sorry that I did not check the rfNews.
You are right, presently I am only looking at variable importance and
therefore I am very happy to hear that I won`t have problems using
ordered factors.
Since I just started to fiddle around with randomForest it
On Tue, Apr 29, 2008 at 03:53:02PM +0200, Julien Roux wrote:
Hi list,
I created a function to plot my data:
plot_function(vector)
I want to write the name of the argument vector in the legend/title of
the plot.
For example if I call:
plot_function(my_vector)
I want my_vector to be
It appears that these are time series (i.e. there is only one value of
River Mile in any one data frame) so if that's right you would be better
off representing them as time series. Using zoo:
library(zoo)
feb06.z - zoo(feb06[,2], feb06[,1])
may06.z - zoo(may06[,2], may06[,1])
jun06.z -
How can I automatically exclude one variable from being saved in the
workspace when I quit an R session? The problem is I don't know how to
erase a variable once it has been created.
Background: I open a connection called con to a database server in my
~/.Rprofile. Obviously, the connection
Hi All,
I want to hide all the system(R) generated warning messages and want only
the messages from my script should be shown when i run myscript.R
Can you please suggest how can I hide the warnings
Thank you
Vidhu
[[alternative HTML version deleted]]
?rm
Richard
Ralf Goertz wrote:
How can I automatically exclude one variable from being saved in the
workspace when I quit an R session? The problem is I don't know how to
erase a variable once it has been created.
Background: I open a connection called con to a database server in my
Readers,
I am having difficulty understanding how to enter commands into r.
I have data arranged as:
100, 200, 300
5.6, 6.7, 7.8
8.9, 9.0, 0.1
1.2, 2.3, 3.4
The data is saved in csv format and I use the command 'read.table' to
import into r.
The values 5.6...3.4 are a function of values
Suppose X is a long vector of integers (typically about 3 elements). Is
there an efficient way to detect whether there are at least N consecutive
zeros in X, and if yes, where does this occur?
for example, suppose X is:
1 2 3 4 5 0 0 0 0 0 0 0 0 0 0 0 0 0 0 3 4 2 0 1 2 0 0 0 2 2 2 2 2 ...
On 29/04/2008 11:39 AM, Kenn Konstabel wrote:
Suppose X is a long vector of integers (typically about 3 elements). Is
there an efficient way to detect whether there are at least N consecutive
zeros in X, and if yes, where does this occur?
for example, suppose X is:
...
and N is 10. I
Two things:
1. the + Sex term is superfluous
2. the variable Subject needs to be a Factor, not a vector (as I
suspect it currently is). That is, add:
mydata.tab$Subject=as.factor(mydata.tab$Subject)
in the preamble before the aov call, and all should be fine.
On 29-Apr-08, at 4:00 AM,
I am outputting some graphs from SpatStat using a for loop. I want the png
files to include the i and j from the nested loops in their names. For
example, I want the file names to look like i-j_plot.png. The code is
below:
ma - levels(marks(X))
n - length(ma)
for(i in 1:n)
for(j in 1:n)
Richard Pearson wrote:
?rm
Richard
Ralf Goertz wrote:
How can I automatically exclude one variable from being saved in the
workspace when I quit an R session? The problem is I don't know how to
erase a variable once it has been created.
[...]
Ralf
More on the use of rm. If you want
This will work:
my.list - c(2, 28, 31, 4, 27)
sort(my.list)
diff(sort(my.list))
any(diff(sort(my.list)) == 1)
the middle two lines are only to illustrate what's going on.
Best wishes!
Charles Annis, P.E.
[EMAIL PROTECTED]
phone: 561-352-9699
eFax: 614-455-3265
29/04/2008 17:04 trhermes a écrit
I am outputting some graphs from SpatStat using a for loop. I want the png
files to include the i and j from the nested loops in their names. For
example, I want the file names to look like i-j_plot.png. The code is
below:
ma - levels(marks(X))
n -
See help(warnings) and from there you'll also find help(warning). It
is described there.
/Henrik
On Tue, Apr 29, 2008 at 5:14 PM, Vidhu Choudhary
[EMAIL PROTECTED] wrote:
Hi All,
I want to hide all the system(R) generated warning messages and want only
the messages from my script should be
Hey Anthony,
There must be many ways to do this. This is one of them:
#First, define a function to calculate the proportion of consecutive
numbers in a vector.
prop.diff=function(x){
d=diff(sort(x))
prop=(sum(d==1)+1)/length(x)
return(prop)}
#Note that I am counting both numbers in a
Dear All,
I've read the manual on Writing R Extensions and in particular the
part on calling R from C. (Most of the manual is about calling C
from R, not the other way around.)
The good news is that I can now call _some_ R from C, specifically
the R functions which have C header
Hi Richard,
Thanks a lot! What I actually want to have
A1
4
A2
2
. and so on! Is this possible?
Thank you again :)!
- Original Message
From: [EMAIL PROTECTED] [EMAIL PROTECTED]
To: Diego Culattoni [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Monday, April
Sorry I forgot these informations. I'm using R 2.70, under Linux (Debian
Etch). The png driver uses cairo, and the version of libcairo installed
is 1.2.4 (which is not the latest, but more recent versions are not
available is the debian stable repositories)
I tried bitmap(), and it does not
On Tue, 29 Apr 2008, Anthony28 wrote:
I need to use R to model a large number of experiments (say, 1000). Each
experiment involves the random selection of 5 numbers (without replacement)
from a pool of numbers ranging between 1 and 30.
What I need to know is what *proportion* of those
Hey Anthony,
My previous function may not work in all cases. Say one of the
experiments yields these numbers:
1,2,3,6,7
Would you say that the proportion of consecutive numbers is 100%? If
so, this will work:
prop.diff=function(x){
d=diff(sort(x))
prop=sum((c(0,d==1)+c(d==1,0))0)
On Tue, Apr 29, 2008 at 6:20 AM, tom soyer [EMAIL PROTECTED] wrote:
Hi,
I would like to use a weighted lm model to reduce heteroscendasticity. I am
wondering if the only way to generate the weights in R is through the
laborious process of trial and error by hand. Does anyone know if R has
Why will this simple statement not work? I think I am following the
documentation for if(cond) statements, and I have tried wrapping the
cons.expr and alt.expr in {}, I get the same error. There is no example
in the help file, and this is not covered in the Introduction to R,
SimpleR or other
Hi,
Any one has the code that I can borrow? Or any suggestions?
Highly appreciate.
Hongyan Du
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PLEASE do read the
I am try to create a plot using xyplot(). I created a function panel.fun() wich
generate segment, but I need use two columns from dataset2.
library(lattice)
panel.fun - function(x, y, minx, maxx, miny, maxy)
{
panel.xyplot(x,y)
# since I don't know how to call dataset2 inside
On 29/04/2008 12:19 PM, Maximillian Murphy wrote:
Dear All,
I've read the manual on Writing R Extensions and in particular the
part on calling R from C. (Most of the manual is about calling C
from R, not the other way around.)
The good news is that I can now call _some_ R from C,
FYI
This is a nice package that is not on CRAN for some reason. You can get it
at
http://www.csm.ornl.gov/esh/statoed/
Tom
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View this message in context:
On 4/29/2008 1:21 PM, Beck, Kenneth (STP) wrote:
Why will this simple statement not work? I think I am following the
documentation for if(cond) statements, and I have tried wrapping the
cons.expr and alt.expr in {}, I get the same error. There is no example
in the help file, and this is not
Kenneth -
See ?if in the Details section. Specifically this part (at least in R
2.7),
In particular, you should not have a newline between '}' and
'else' to avoid a syntax error in entering a 'if ... else'
construct at the keyboard or via 'source'.
The R interpreter can't 'see ahead'
Hi, I have a question about how to extract paramters from a fitted model. I
can extract coefficients and std, but from some other statistics, I dont
know how to extract. Can anyone help?
Here it is an example:
coxout-coxph(Surv(t,t.censor)~x)
coxout
Call:
coxph(formula = Surv(t, t.censor)
See the source code of function:
getS3method(print, coxph)
is this block:
tmp - cbind(coef, exp(coef), se, coef/se, signif(1 -
pchisq((coef/se)^2, 1), digits - 1))
On 4/29/08, Lisa [EMAIL PROTECTED] wrote:
Hi, I have a question about how to extract paramters from a fitted model.
I
can
Hi Diego,
Try this:
z-As[A1]+As[A2]; names(z)-z
z
4
HTH,
Jorge
On Tue, Apr 29, 2008 at 2:57 PM, Diego Culattoni [EMAIL PROTECTED]
wrote:
Thank you Jorge, what I want to have is
z - A1+A2
z
4
The problem is that A1, A2,... still unknown, so that I have the following
error
A1
On an x86 machine operating under Gentoo Linux, I'm having trouble with
tcltk in R-2.6.1 (the latest version available through Gentoo's
emerge/portage system). The problem first came to my attention when
install.packages(Rmetrics) produced the following error message:
Loading required package:
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