Hi Murali,
So, the solution to your problem will be to explicitly convert your
matrix to a numeric matrix. Maybe matrix (?matrix) will do, or you'll
also have to use as.numeric (?as.numeric).
The strings on the left seem to me to be the row labels, right..?, not
elements in the matrix/table.
As
Hi all. I got a question about eigenvector. I've tried input a symmetric
matrix to both R (using eigen function) and minitab, but the result is
really different. Can anyone tell me what's wrong with that?
Thanks.
[[alternative HTML version deleted]]
Hi,
Â
My question is how I load the package garchOxFit. I load the fGarch function
that works quite well, but I can't use the garchOxFit function. I have tried
looking at Help(garchOxFit), I as far as I can understand I am supposed to
download the OxConsole Software together with the OxGarch
Hi everybody!
I'm sure that I overlook something and feel quite stupid to ask, but I
have not found an easy solution to the following problem: Take e.g. the
Orthodont data from the nlme package:
head(Orthodont)
Grouped Data: distance ~ age | Subject
distance age Subject Sex
1 26.0 8
Simple. Minitab must be broken. Have you reported it to them?
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of SH.Chou
Sent: Friday, 18 July 2008 5:24 PM
To: r-help@r-project.org
Subject: [R] function eigen AND Minitab
Hi all. I got a question about
try this:
data(Orthodont, package = nlme)
metaFields - c(Subject, Sex)
Orthodont$ID - do.call(paste, c(Orthodont[metaFields], sep = /))
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address:
do.call('paste', c(data.frame(letters, LETTERS),
list(sep='/')))
Patrick Burns
[EMAIL PROTECTED]
+44 (0)20 8525 0696
http://www.burns-stat.com
(home of S Poetry and A Guide for the Unwilling S User)
Sebastian Weber wrote:
Hi everybody!
I'm sure that I overlook something and feel quite
Or perhaps it is the idea of different that is broken.
If you are doing the same problem, then the eigenvalues
should be equal in the two systems -- up to numerical
error.
If that is true, then the eigenvectors for each distinct
eigenvalue need to span the same space. Thus the
eigenvectors can
Hi the list,
Back on an old problem. I thaught that was ok, but it is still not
working on my computer.
I write a toy package called packClassic. R CMD build packClassic works
fine.
When I run R CMD CHECK packClassic, I get
--- 8 ---
* checking for unstated dependencies in R code
Hello,
Would anyone be able to help me find an algebraic equation sequencer (like
Knuth's topological processor) that will order a system of equations for
nonlinear optimization similar to GAMS/AMPL? eg A[t]=A[t-1]+B[t] with
perhaps sum(A) to be optimised by changing B[t] and other
CG == Christophe Genolini [EMAIL PROTECTED]
on Fri, 18 Jul 2008 11:14:25 +0200 writes:
CG Hi the list,
CG Back on an old problem. I thaught that was ok, but it is still not
CG working on my computer.
CG I write a toy package called packClassic. R CMD build packClassic works
Once you get your matrices in order you do not want to use t(X) %*% X. Instead,
use crossprod(X). They do the same thing, but the former is the matrix
operations based on the algebraic representation whereas numerical analysts
will prefer the methods used in crossprod (hence the reason it
Dear list,
i try to do my first statistics with R.
Given a dataframe of three columns, where col1 is of type factor, col 2 and
col3 are numeric and pairs of observations i would like to perform a paired
t-test for each level of col1.
I would like to avoid specifying the levels of col1 manually
Hi All,
Random Technologies LLCs commercially supported Rstat, based on R
2.7.2, is available today. For product information, visit http://www.random
-technologies-llc.
-Greg
Gregory R. Warnes, Ph.D.
Chief Scientist
Random Technologies LLC
email: [EMAIL PROTECTED]
tel:(585)
Hi Henning,
Henning Wildhagen wrote:
Given a dataframe of three columns, where col1 is of type factor, col 2 and
col3 are numeric and pairs of observations i would like to perform a paired
t-test for each level of col1.
I would like to avoid specifying the levels of col1 manually because it
I have a data frame that is 122 columns and 7ish rows it is a zoo
object, but could be easily converted or read in as something else. It is
multiparameter multistation water quality data - there are a lot of NA s. I
would like to find chuncks of data that are free of NA s to do some
Random Technologies LLC is pleased to announce immediate availability
of RStat version 2.7.2.
This version of RStat provides the features of the latest version of R
from the R-project with with enterprise-level validation,
documentation, software support, and consulting services from
I think the approach is ok. I'm having difficulties though...!
I've managed to get 'merge' working (using the 'all' function as suggested),
but for some strange reason, the output file produces 12 extra rows! So now the
shorter file isn't the same length as the 'master' file, it's now longer!
Hi Simon,
i tried your code, but it results in an error:
error in var(x) : `x` is empty
Do you have an idea what the reason might be?
Thanks a lot,
Henning
Original-Nachricht
Datum: Fri, 18 Jul 2008 11:37:24 +0100
Von: Simon Anders [EMAIL PROTECTED]
An:
Gregory R. Warnes wrote:
Hi All,
Random Technologies LLC’s commercially supported Rstat, based on R
2.7.2, is available today. For product information, visit http://www.random
-technologies-llc.
Hi Greg,
two short questions on your very interesting product:
1. How can it be based on
Hi there,
I have a very simple question. If I execute the following code:
test - function(x) {
name - paste(x,info_within_function)
c(1,2,3,4,5)
}
ret - lapply(1:10, test)
, I end up with a list and each entry is just numbered [[1]], [[2]], ... [[10]]
How can I force the
Hello Everyone,
I mis-typed the version number in the annoucement that just went out. Here
is the corrected message:
On Fri, Jul 18, 2008 at 6:50 AM, Gregory R. Warnes
[EMAIL PROTECTED] wrote:
Random Technologies LLC is pleased to announce immediate availability of
RStat version 2.7.1.
On Fri, 2008-07-18 at 13:45 +0200, Antje wrote:
Hi there,
I have a very simple question. If I execute the following code:
test - function(x) {
name - paste(x,info_within_function)
c(1,2,3,4,5)
}
Here your test is returning c(1,2,3,4,5), and is doing nothing with
name,
na.contiguous.zoo() will return the longest stretch of non-NA data.
Its a zoo method of the na.contiguous generic in the core of R.
rle(!is.na(rowSums(coredata(z will find all stretches.
On Fri, Jul 18, 2008 at 6:47 AM, stephen sefick [EMAIL PROTECTED] wrote:
I have a data frame that is 122
Hi Gavin,
thanks a lot for your answer.
Maybe I did not explain very well what I want to do and probably chose a bad
example. I don't mind spaces or names starting with a number. I could even name it:
Hugo1, Hugo2, ...
My biggest problem is, that not only the values are calculated/estimated
CG --- 8 - 00check.log --
CG * using log directory 'C:/Documents and Settings/Christophe/Mes
CG documents/Docs articles polys résumés/R/tutorial S4/packClassic.Rcheck'
I see many directories with spaces ( ) inside.
This used to cause all kind of problems
Dear all,
I have got a question for generating repeats of a vector's elements.
Please don't hesitate to email me back and say that it is very easy
although I can't find a method to solve it.
If I have a n-vector b, whose elements are b[1], b[2], ..., b[n], how
can I generate such a vector
try this:
b - rnorm(4)
ind - unlist(lapply(seq_along(b), seq_len))
b
b[ind]
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/(0)16/336899
Fax:
#how do I use the below, sorry for being unsavey. I would look for when
value = FALSE meaning the there are no NAs and Then look for the longest
value of continuous measurements (or lengths that I am comfortable with)
correct? How do I subset my original data frame with this information? How
do
Dear List,
Is there a possibility to change the font-face for a part of the title
of a plot?
For example I have the following...
plot(nirs, type=l, xlab=Wellenlänge [nm], col=darkslategray,
main = Spektrum Deschampsia caespitosa)
...and I would like to change the part of the
It would be appreciated if you cut down your data to
a minimal size before posting. At any rate, the ends
are the cumsums of the lengths and
the starts are lengths-1 before that, e.g.
# data
library(zoo)
z - zoo(c(1, 2, NA, 3, 4, 5, NA, 6))
z - cbind(z, z)
z.rle -
On Fri, 2008-07-18 at 14:19 +0200, Antje wrote:
Hi Gavin,
thanks a lot for your answer.
Maybe I did not explain very well what I want to do and probably chose a bad
example. I don't mind spaces or names starting with a number. I could even
name it:
Hugo1, Hugo2, ...
My biggest
Does anyone know how to read SPSS .por (ie Portable) files? The foreign package
only deals with SPSS .sav files and not with those with a por extension.
Thanks,
José
Mr José Luis Iparraguirre D'Elia
Senior Research Economist
Economic Research Institute of Northern Ireland
Floral
I would do it like this but I'm curious to see whether it can be easier solved
:-)
b - c(1:10)
vector_list - lapply(1:length(b), FUN = function(x) { b[1:x] }))
(for everything in a large vector just apply unlist to the vector_list)
Antje
Chaofeng Kou schrieb:
Dear all,
I have got a
Hello,
I am a biologist and I am dealing with files composed of columns with T or A
or C or G (example below)
Sometimes a column is composed of only T
and in that case, the columns becomes a logical column TRUE (example below)
I know that the argument as.is controls the turns off turning a
Thanks a lot for your help!
I know that I cannot directly access the list created, I just was not sure if
there is any format of the return value which could provide additionally a
name for the returned list.
I tried to return the values as list with the appropriate name but then I end
up
minimal, minimal, minimal, I will have to remind myself.
contiguous.zoo - function(x)
{
z.rle - rle(!is.na(rowSums(coredata(x
# row indexes
ends - cumsum(z.rle$lengths)
starts - ends - z.rle$lengths + 1
indexes - with(z.rle, data.frame(starts, ends, lengths, values))
indexes.sort -
Dear R users,
I have had a problem using the step function for the selection of the
variables from a gamma model with log link function.
CODE:
step.glm.gam1.infroma - step(glm.gam1.infroma, direction = backward, k=2)
ERROR MESSAGE:
Error in glm.fit(x[, jj, drop = FALSE], y, wt, offset =
na.contiguous
function (object, ...)
UseMethod(na.contiguous)
environment: namespace:stats
this is what I get when I look for the source code for some functions- Is
there a way to look at the source code?
--
Let's not spend our time and resources thinking about things that are so
little or so
On Fri, 18 Jul 2008, Jose Iparraguirre D'Elia wrote:
Does anyone know how to read SPSS .por (ie Portable) files? The foreign
package only deals with SPSS .sav files and not with those with a por
extension.
Not so. ?read.spss says
'read.spss' reads a file stored by the SPSS 'save' or
This is a S3 method, then:
methods(na.contiguous)
getS3method(na.contiguous, data.frame)
getS3method(na.contiguous, zoo)
On Fri, Jul 18, 2008 at 10:37 AM, stephen sefick [EMAIL PROTECTED] wrote:
na.contiguous
function (object, ...)
UseMethod(na.contiguous)
environment: namespace:stats
Dear R Users,
How can I create names for lists within a function where the name itself
is a function of several variables ?
a-1
b-2
paste(a,b)
[1] 1 2
foo-list(paste(a,b)=3) = DOES NOT WORK
Error: unexpected '=' in foo-list(paste(a,b)=
eval(paste(a,b))
[1] 1 2
Try:
foo - list(3)
names(foo) - paste(a, b)
On Fri, Jul 18, 2008 at 11:03 AM, [EMAIL PROTECTED] wrote:
Dear R Users,
How can I create names for lists within a function where the name itself
is a function of several variables ?
a-1
b-2
paste(a,b)
[1] 1 2
foo-list(paste(a,b)=3) =
Oh true, this would solve the problem too :-)
Thanks a lot for the suggestions!
Antje
Martin Morgan schrieb:
Antje [EMAIL PROTECTED] writes:
Thanks a lot for your help!
I know that I cannot directly access the list created, I just was not
sure if there is any format of the return value
Hi R,
Here's a question/problem on the 'neuralnet' package for neural
networks. I have more than 50 factors in each of my independent
variables. When I apply the command 'neuralnet', I get the below warning
message,
net.sum - neuralnet( Sum~Var1+Var2+Var3, b,
hidden=0,linear.output=TRUE)
Hi Davide,
did you check the R Installation and Administration Manual?
In Section A.2.1 you will find some more information.
Make sure that you have the 'dev' packages installed of tcl8.x and tk8.x.
If you don't know where 'tclConfig.sh' and 'tkConfig.sh' are located,
just find them:
locate
Spencer Graves wrote:
I found the first chapter of Paul Dierckx (1993) Curve and Surface
Fitting with Splines (Oxford U. Pr.). Beyond that, I've learned a lot
from the 'fda' package and the two companion volumes by Ramsay and
Silverman (2006) Functional Data Analysis, 2nd ed. and (2002)
On Fri, 18 Jul 2008, Jose Iparraguirre D'Elia wrote:
Thanks Brian,
The error message reads as follows:
Error in read.spss(G:/Jose/Life and Times Survey/LT 2007/nilt07w1.por) :
error reading portable-file dictionary
So it looks like it is not a portable file, or at least one that read.spss
Many thanks, much appreciated.
Henrique Dallazuanna [EMAIL PROTECTED]
18/07/2008 15:11
To
[EMAIL PROTECTED]
cc
r-help@r-project.org
Subject
Re: [R] creating names for lists
Try:
foo - list(3)
names(foo) - paste(a, b)
On Fri, Jul 18, 2008 at 11:03 AM, [EMAIL PROTECTED] wrote:
Dear R
Dear R Users,
I would like to get the pdf() command to create graphics in landscape
mode, as I am plotting 8 graphs in 2 rows and 4 columns. This is being
generated for an a4 printer (so I also use the paper=a4 command). Is
there a way I can ask pdf() to generate the document in landscape mode
Building upon Jim's answer below (Thanks Jim, that helped a lot), I need
to pickup where this thread left off. I'm using Vegan to calculate the
Jaccard's Index and the Row.Names and column names are represented in my
matrix as seen here.
[,3] [,5] [,6] [,9] [,11]
[3,]06 11
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html and provide commented,
minimal, self-contained, reproducible code.
I do NOT know how to do what you want, but with a self-contained
example, I suspect many people on this list -- probably including me --
On Fri, 18 Jul 2008, Jose Iparraguirre D'Elia wrote:
However, it can be read in SPSS. The file is available on the web, as it
corresponds to the raw database of the Northern Ireland Life and Times Survey
2007 (http://www.ark.ac.uk/nilt/datasets/). It is a file that SPSS recognises;
albeit
Hi, Greg:
Have you answered Uwe's question? I visited your website, and your idea
sounds interesting. I'm an engineer, not a lawyer, but it seems to me that
what you have IS in accord with the GPL - provided that that you make the R
source available as Uwe asks.
So: what's the answer to Uwe's
Is this what you want:
x
[,3] [,5] [,6] [,9] [,11]
[,3] 16 11 1621
[,5] 27 12 1722
[,6] 38 13 1823
[,9] 49 14 1924
[,11]5 10 15 2025
library(reshape)
melt(x)
X1X2 value
1 [,3] [,3] 1
2 [,5]
hi there,
I need to change a column name in a dataframe.how do i do that
eg
abc- dataframe
abc
x y z
i wanna change the colum z to w.
Ramya
--
View this message in context:
http://www.nabble.com/cbind-help-tp18532609p18532609.html
Sent from the R help mailing list archive at Nabble.com.
Dear R users,
I want to read a file like following :
if it is a table then z - read.table(pathname, dec=., header=TRUE)
else if it's not a table (image,doc,...) then send an error or something
like that
acually I have a read.table in the beginnig of my R code, and if my data is
not a table I
Try:
names(abc)[3] - w
On Fri, Jul 18, 2008 at 1:08 PM, Rajasekaramya [EMAIL PROTECTED] wrote:
hi there,
I need to change a column name in a dataframe.how do i do that
eg
abc- dataframe
abc
x y z
i wanna change the colum z to w.
Ramya
--
View this message in context:
However, it can be read in SPSS. The file is available on the web, as it
corresponds to the raw database of the Northern Ireland Life and Times Survey
2007 (http://www.ark.ac.uk/nilt/datasets/). It is a file that SPSS recognises;
albeit the foreign package doesn't -hence my initial query.
José
Maybe something like this:
stopifnot(tail(unlist(strsplit(slides.pdf, \\.)), 1) == txt)
On Fri, Jul 18, 2008 at 12:51 PM, mysimbaa [EMAIL PROTECTED] wrote:
Dear R users,
I want to read a file like following :
if it is a table then z - read.table(pathname, dec=., header=TRUE)
else if it's
To Whom It May Concern:
Are there more examples / information regarding the use of
'dataedit'? If so, where might I find these?
Regards,
Steve Kennedy
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do
pdf(file=..., width=10, height=8)
On Fri, Jul 18, 2008 at 11:04 AM, [EMAIL PROTECTED] wrote:
Dear R Users,
I would like to get the pdf() command to create graphics in landscape
mode, as I am plotting 8 graphs in 2 rows and 4 columns. This is being
generated for an a4 printer (so I also use
[EMAIL PROTECTED] [EMAIL PROTECTED] [Fri, Jul 18, 2008 at 05:04:15PM CEST]:
[...]
Generally, this communication is for informational purposes only
and it is not intended as an offer or solicitation for the purchase
or sale of any financial instrument or as an official confirmation
of any
Hi Charles,
The souce code for RStat is included on the distribution DVD, which meets the
GPL 2 distribution requirement.
We do provide evaluation copies of RStat that are funtionally complete and
include the complete source code. Email [EMAIL PROTECTED] if you would like an
evaluation copy.
I'm trying to find an R package that will smooth a line with the polynomial
approximation with exponential kernel or PAEK algorithm that is used in
ESRI's ArcGIS software. I have a copy of the original paper that provides
the algorithm, but I'm not confident in how to code it. The algorithm will
Hello,
I was messing around with graphics, and noted an odd behavior of par(din). If
the x11 device is empty, par(din) does not return the correct size
if the device
has been resized manually. dev.size() works correctly.
R version 2.7.1; Fedora 8
# case 1 - empty device
x11()
dev.size()
[1]
Doesn't it now? PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html and provide commented,
minimal, self-contained, reproducible code.
On Thu, Jul 17, 2008 at 8:26 AM, Xin [EMAIL PROTECTED] wrote:
Dear All:
I am trying to plot a series of data using histogram plot.
Hello,
assume I have an unstructured text line from a connection. Unfortunately,
it is in string format:
R x
[1] \talpha0\t-0.638\t0.4043\t0.4043\t-2.215\t-0.5765\t-0.137\t501\t2000
How can I extract the data included in this string object x in order to
get the elements for the parameter
Try this:
na.omit(as.numeric(unlist(strsplit(\talpha0\t-0.638\t0.4043\t0.4043\t-2.215\t-0.5765\t-0.137\t501\t2000,
\t
On Fri, Jul 18, 2008 at 1:44 PM, Christine A.
[EMAIL PROTECTED] wrote:
Hello,
assume I have an unstructured text line from a connection. Unfortunately,
it is in string
Jose Iparraguirre D'Elia wrote:
[snip]
Thanks Brian,
The error message reads as follows:
Error in read.spss(G:/Jose/Life and Times Survey/LT 2007/nilt07w1.por) :
error reading portable-file dictionary
So it looks like it is not a portable file, or at least one that read.spss
knows
Ah... obvious isn't it ? As always.
Many thanks,
Tolga
jim holtman [EMAIL PROTECTED]
18/07/2008 17:30
To
[EMAIL PROTECTED]
cc
r-help@r-project.org
Subject
Re: [R] Landscape mode for pdf
pdf(file=..., width=10, height=8)
On Fri, Jul 18, 2008 at 11:04 AM, [EMAIL PROTECTED] wrote:
Dear
I have a binary matrix that represents a map of invasive species risk (1 =
infested; 0 = uninfested). It started as a matrix of probabilities
(developed in ArcMap) that I converted to binary with this R code:
Dear Christine,
Try
x=\talpha0\t-0.638\t0.4043\t0.4043\t-2.215\t-0.5765\t-0.137\t501\t2000
res=unlist(strsplit(x,[\t]))
as.numeric(res[-c(1,2,length(res)-1,length(res))])
HTH,
Jorge
On Fri, Jul 18, 2008 at 12:44 PM, Christine A.
[EMAIL PROTECTED] wrote:
Hello,
assume I have an
Hello, I am trying to identify values that fall within a certain range. I
thought that I might be able to use the which function to do this but I have
been unable to figure out a way to do it. Perhaps a little code will
illustrate what i am trying to do.
a - rnorm(1000, 100, 50)
which( 100 a =
strapply in gsubfn finds matches of the indicated regexp,
in this case a \t followed by one or more minus, dot or digit,
and with backref of -1 it passes the backreference, i.e. portion
of the match within (..), to the function in the third arg. See
http://gsubfn.googlecode.com
library(gsubfn)
Try :
which(a 100 a= 120)
On Fri, Jul 18, 2008 at 3:42 PM, sj [EMAIL PROTECTED] wrote:
Hello, I am trying to identify values that fall within a certain range. I
thought that I might be able to use the which function to do this but I have
been unable to figure out a way to do it. Perhaps a
On Fri, 18 Jul 2008 11:42:09 -0700,
sj [EMAIL PROTECTED] wrote:
[...]
a - rnorm(1000, 100, 50) which( 100 a = 200)
of course this doesn't work but illustrates what I ma trying to do, If
anyone has suggestions I would greatly appreciate it
Have a look at ?
--
Seb
Hello,
I make frequent use of the *step()* and, for plotting, *all.effects()
*functions for *lm()* objects. I am now doing more with *lme()* random
effects models, and haven't been able to find functions similar to
*step()* or *all.effects()* which will accept *lme()* objects. Do
similar
Have a look at the buffer function in the adehabitat package.
HTH,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature
and Forest
Cel biometrie, methodologie en
Hello,
I am calculating 'Betweenness' of a large network using R. Currently, I have
the node-node information (City1-City2) in an excel file, present in two
columns where column A has City1 and column B has City2 that city1 is connected
to. These are the steps that I go through to calculate
Do simply
which(a100 a=200)
Julian
sj wrote:
Hello, I am trying to identify values that fall within a certain range. I
thought that I might be able to use the which function to do this but I have
been unable to figure out a way to do it. Perhaps a little code will
illustrate what i am
This is for ACroske but I can't find his email so I'll just send it to
the list. Hi ACroske: The code below takes a zeros and ones matrix and
puts ones
in the places you wanted. It can be made shorter ( maybe ?. i haven't
thought about that ) but first let me know if that's what you wanted ?
In the following code, I'd like to be able to create a new variable
containing the value of the names of the list.
a - data.frame(var.1 = 1:5)
b - data.frame(var.1 = 11:15)
test.list - list(a=a, b=b)
# in this case, names(test.list) is a and b
# and I'd like to use lapply() so that
# I get
Dear Andrew,
It's not the best solution but it does what you need:
a - data.frame(var.1 = 1:5)
b - data.frame(var.1 = 11:15)
test.list - list(a=a, b=b)
res=do.call(rbind,test.list)
res$var.2=substr(rownames(res),1,1)
rownames(res)=NULL
res
HTH,
Jorge
On Fri, Jul 18, 2008 at 6:21 PM, Andrew
Is this what you wanted; you would use the 'names' to get the names in
the lapply:
lapply(names(test.list), function(x){
+ cbind(test.list[[x]], var.2=x)
+ })
[[1]]
var.1 var.2
1 1 a
2 2 a
3 3 a
4 4 a
5 5 a
[[2]]
var.1 var.2
111 b
212
forgot one step:
z - lapply(names(test.list), function(x){
+ cbind(test.list[[x]], var.2=x)
+ })
names(z) - names(test.list)
z
$a
var.1 var.2
1 1 a
2 2 a
3 3 a
4 4 a
5 5 a
$b
var.1 var.2
111 b
212 b
313 b
414 b
5
Hello,
I am sorry if this is an answered question, but I did my homework for a long
while and couldn't figure out a way to retrieve data entry from a model dialog.
In one of the examples compiled by James Wettenhall:
odalDialog - function(title, question, entryInit, entryWidth = 20,
Hey,
I was wondering if there existed a R function similar to 'fsolve' or
'fzero' Matlab functions?
Thanks!
Francois Aucoin
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How do I use the buffer function since I have more than the two columns it
calls for? (I have 46!)
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Hi all,
I'm currently implementing quasi random generation (torus) on R
(package randtoolbox available on CRAN). Even if it is not a great
idea, I decided to use the machine time to initiate the seed. So when
the seed is not specified by the user, the pkg uses the time machine
time.
Hi there,
I'm trying to get some text in the outer margins of my plots and am
having trouble - the margin text is overlapping my plots, even though
the outer margin I'm trying to put it in is very big.
I've simplified my problem down to this:
-
try using the 'line' parameter:
par(mfrow=c(6,1),oma=c(20,0,20,0), mar=c(0,3.1,1,2.1))
for (i in 1:6) {
plot(cars[,speed],cars[,dist])
}
mtext(Position (Mb), outer=TRUE, side=1, line=3)
mtext(Position (Mb), outer=TRUE, side=3, line=3)
On Fri, Jul 18, 2008 at 7:00 PM, Janet Young [EMAIL
Francois
You might try the BB package, which has quite a nice example.
Stuart
On Sat, 19 Jul 2008 10:20:34 +1000, François Aucoin
[EMAIL PROTECTED] wrote:
Hey,
I was wondering if there existed a R function similar to 'fsolve' or
'fzero' Matlab functions?
Thanks!
Francois Aucoin
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